Hi can we use the caregiver’s address for one phase and use our own address (in nric and currently staying) for another phase?
S
Latest posts made by studybuddy
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RE: 2024 P1 Registration Exercise for 2025 In-take
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RE: CMA Math - Discussion
Hi anyone with review or promo referral code for farrer park or toa payoh pls?
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RE: O-Level Additional Math
hi i suppose the question is to differentiate this wrt x:
y = 10 / (1 + x^2)
y = 10* (1 + x^2)^-1
dy/dx = 10 * (2x) * (1 + x^2) ^ -2
= 20x / (1 + x^2) ^2
the main function is (1 + x^2)^-1
differentiate the function (1+ x^2) --> 2x
and reduce the whole function’s power by 1, i.e. the power becomes -1 -1 = -2
general rule:
differentiate constants --> 0
differentiate x --> 1
differentiate x^n --> n* x^(n-1) -
RE: O-Level Additional Math
reddiechan:
for part b, again notice the similarity with part a, so just sub x = x-7 into part a answer:
(a) 6x2 + 12 x - 90virgo:
Need help on these 2 questions.... many thanks !!!
http://i44.tinypic.com/2ntcz6q.gif\">
= 6 (x2+2x-15)
= 6(x-3)(x+5)
(b) 6(x-7)^2 + 12(x-7) - 90
= 6(x2-14x+49) + 12x - 84 - 90
= 6x2 - 6(14x-49) + 12x - 84 - 90
= (6x2 + 12x - 90) - 6(14x-49)
= 6(x-3)(x+5) - 6(14x-49)
= 6[(x-3)(x+5) - 7(2x-7)]
6(x-7)^2 + 12(x-7) - 90
= 6 ((x-7) - 3) ((x-7) +5)
= 6 (x - 10) (x -2) -
RE: O-Level Additional Math
M-Help:
oh yes, careless! thanks for pointing outDear studybuddy
There seems to be a careless error in your final answer to part (ii). Pls check and confirm. -
RE: O-Level Additional Math
virgo:
a.Need help on these two questions... many thanks !!
http://i43.tinypic.com/35b89wy.gif\">
first term is 3x^2 so it has to be the form of (3x +...y) *(x + ...y )
the coefficient of y will have to give a multiple of 54
one of --> 1, 54 or 2, 27 or 3, 18 or 6, 9
coeff of xy = 9, so the answer has to be
(3x - 9y)*(x + 6y)
b.
consider the similarity to part a.
use substitution of x= (3x - 8y), you will get:
(3 (3x - 8y) - 9y) * ((3x - 8y) + 6y)
= (9x -24y - 9y) *(3x - 8y + 6y)
= (3x - 33y)* (3x - 2y)
do ask if u need more clarifications! :imcool: -
RE: O-Level Additional Math
aceurmaths:
Q12 part a.
You still need any help ?clblinym:
Need help with a question... many thanks. Amy
http://i44.tinypic.com/2lc8snl.jpg\">
height of water = 3/8 * 48cm = 18cm
surface area = base area + rectangular area + 2 trapezium areas + slant area
= 90 *56 + 56 *18 + 2* (.5*(90+75)*18) + 56* 23.4
= 10330 = 10300 sqcm (to 3sf)
the slant height is 23.4cm using pythagoras theorem for bottom right triangle with other lengths 18cm and (90-75) = 15cm.
part b.
volume of water in part a = 75 * 56 * 18 + 0.5 *15*56*18
= 83160 cm3
25% increase = vol of 9 cylinders = 83160*0.25 = 20790 cm3
vol of 1 cylinder = 2310 cm3
= pi*r^2 * h
r^2 = 2310 / (3.142 * 16) = 45.950
r = 6.7786
diameter = 2r = 13.557 = 13.6cm (to 3 sf)