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    1. Home
    2. Trevortan
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    Recent Best Controversial
    • RE: Lower Secondary Mathematics

      1. Participants from China, Japan and Korea will be attending a conference. 96 of them are from China, 72 are from Japan and 48 are from Korea. The organiser wishes to group them into discussion groups such that the participants are distributed equally among the groups. The number of discussion topics that the organiser needs to prepare depends on the number of discussion groups formed.

      (i) What is the greatest number of discussion topics that the organiser has to prepare for the conference?
      (ii) How many China participants are in each discussion group?

      2. Huixian wishes to cut some squares from a rectangular sheet of A4 paper with a length of 84cm and a breadth of 126cm. She wants to cut the A4 paper evenly into small squares and does not want any leftover paper.
      (i) What is the length of each square?
      (ii) How many squares can she cut altogether?

      posted in Secondary Schools - Academic Support
      T
      Trevortan
    • RE: Lower Secondary Mathematics

      Pls help. TIA


      Michael is an art elective programme student who is working on an assignment. He designs a rectangular pattern measuring 45mm by 42mm. He is required to use identical rectangular patterns to form a square. The maximum area of the square allowed is 1.6 square meters.
      (i) How many patterns does he need to form the smallest square?
      (ii) What are the dimensions of the largest square that he can form?

      posted in Secondary Schools - Academic Support
      T
      Trevortan
    • RE: Lower Secondary Mathematics

      Plz help out. Thanks


      The numbers 176 and 342, written as the products of their prime factors, are 176 = 2 to the power of 4 x 11 and 342 = 2 x 3 to the power of 2 x 19. Hence, find the smallest whole number that is divisible by both 176 and 342.

      I am confused with the term 'divisible by'.
      Does 'divisible by' mean LCM: Lowest Common Multiple?

      posted in Secondary Schools - Academic Support
      T
      Trevortan
    • RE: Q&A - PSLE Science

      Can anybody help with this question?


      A group of pupils wanted to find out the temperature changes in a pond and a leaf litter habitat. They took turns to use a data logger to measure the temperature in both habitats at 6 a.m., noon, 6 p.m. and midnight. What should the temperatures of the pond and leaf litter habitats be at the timings?

      posted in Primary 6 & PSLE
      T
      Trevortan
    • RE: Q&A - PSLE Science

      Sysy:
      http://i57.tinypic.com/16le73d.jpg\">


      What is the ans. please explain.

      Thanks.
      Answer is (1).
      The turbine possesses kinetic energy to power the generator which generates electricity, not kinetic energy. The power lines that are connected to the generator are transporting electrical energy from the generator.

      posted in Primary 6 & PSLE
      T
      Trevortan
    • RE: 2014 PSLE Discussions and Strategy

      Same

      1. 火冒三丈
      2. 接触

      posted in Primary 6 & PSLE
      T
      Trevortan
    • RE: 2014 PSLE Discussions and Strategy

      Kangkangteo:

      This is from the earliest post.
      1) 15 (2) 14. (3) 5. (4) 4

      60 x 1 75 x 1
      30 x 2. 25 x 3
      20 x 3. 15 x 5
      15 x 4
      12 x 5
      10 x 6

      5 bags (12 apples and 15 pears)
      15 bags (4 apples and 5 pears) --- maximum number of bags

      So answer is 4 apples. --- option (4)
      Yes answer is 4 as 75 cannot be divided by 12 (option 3)

      posted in Primary 6 & PSLE
      T
      Trevortan
    • RE: 2014 PSLE Discussions and Strategy

      bleeze:

      Question is roughly : There are 60 apples and 75 pears. She wants to group them together with no remainder. There are same no. of total fruitsin each group. How many apples are there in each group?
      1) 5
      2) 4
      3) 12
      4) 15

      60/12 = 5 groups
      75/15 = 5 groups

      12+15 = 27 total fruits (12 apples + 15 pears in a group). So total there are 5 groups.
      My DS's tuition teacher said the ans is 3.
      So there are 60 apples, in your words, 60/5 = 12 in each group. There should be 12 pears as well. 75/12 = X Answer is not 3.
      Let's take 4 groups. 60/4 = 15
      75/15 = 5 No remainder. Correct! Answer is 4.

      posted in Primary 6 & PSLE
      T
      Trevortan
    • RE: Q&A - PSLE Science

      Jamesbond:
      Trevortan, I get it now...Thx.

      No prob

      posted in Primary 6 & PSLE
      T
      Trevortan
    • RE: Q&A - PSLE Science

      Jamesbond:
      http://i62.tinypic.com/28w045j.jpg\">

      Hi Trevortan,
      So, In A, power is got from two batteries and in B, power is got from one battery...Am I right?
      Hi Jamesbond,
      In A, the bulb won't light up as there are two with two negative terminals pointing to left and two with positive terminal towards to right. In B, the power is from 2 batteries.

      posted in Primary 6 & PSLE
      T
      Trevortan
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