Q&A - P5 Math

[2Transformer]

Pls help to solve this question.



In a stadium, the number of girls is equal to the number of men. There are 252 females altogether. 7/9 of the children and 2/3 of the adults are females.

(a) Find the number of girls.
(b) Find the difference in the number of children and adults.
[Please use model approach]

TIA

[MathIzzzFun]

2Transformer:

Pls help to solve this question.



In a stadium, the number of girls is equal to the number of men. There are 252 females altogether. 7/9 of the children and 2/3 of the adults are females.

(a) Find the number of girls.
(b) Find the difference in the number of children and adults.
[Please use model approach]

TIA

(you can translate the solution to model easily)

using equal fraction method:

7/9 children (girls) = 1/3 adults (men)
7/9 children = 7/21 adults

children --> 9 units, ----- girls : boys --> 7 units : 2 units
adults --> 21 units, ----- women : men --> 14 units : 7 units
Total number of females --> 21 units
21 units --> 252
1 unit --> 12

number of girls --> 7 x 12 = 84
Difference in number of adults and children --> (14 - 2) x 12 = 144

there are 144 more adults than children.

cheers.

[2Transformer]

MathIzzzFun:

2Transformer:

Pls help to solve this question.



In a stadium, the number of girls is equal to the number of men. There are 252 females altogether. 7/9 of the children and 2/3 of the adults are females.

(a) Find the number of girls.
(b) Find the difference in the number of children and adults.
[Please use model approach]

TIA

(you can translate the solution to model easily)

using equal fraction method:

7/9 children (girls) = 1/3 adults (men)
7/9 children = 7/21 adults

children --> 9 units, ----- girls : boys --> 7 units : 2 units
adults --> 21 units, ----- women : men --> 14 units : 7 units
Total number of females --> 21 units
21 units --> 252
1 unit --> 12

number of girls --> 7 x 12 = 84
Difference in number of adults and children --> (14 - 2) x 12 = 144

there are 144 more adults than children.

cheers.

:thankyou: MathIzzzFun !

[sembgal]

jieheng:

sembgal:

Mrs Tan bought 42 apples. Each apple costs $0.70 less than a pear. She spent the same amount of money on 12 pears. How much did Mrs Tan spend on buying the apples?


Please help to solve. Thanks.

1A + 0.7 = 1P
12A + 12*0.7 = 12P
12A + 8.4 = 12P
12A + 8.4 = 42A (the cost of 42 apples = the cost of 12 pears)
30A = 8.4
1A = 0.28
42A = 0.28*42 = 11.76

the amount of money she spent on buying the apples is $11.76

Thanks.

[sembgal]

MathIzzzFun:

sembgal:

Mrs Tan bought 42 apples. Each apple costs $0.70 less than a pear. She spent the same amount of money on 12 pears. How much did Mrs Tan spend on buying the apples?


Please help to solve. Thanks.

cost of 12 pears = cost of 42 apples
cost of 1 pear = 7/2 x cost of 1 apple

cost of 1 pear --> 7 units
cost of 1 apple --> 2 units

5 units --> $0.70
1 unit --> $0.14

cost of 1 apple --> $0.28

Amount paid for the apples = 42 x $0.28 = $11.76

cheers.

Thanks

[iCreative Math]

Alternative Method - (some students may find it easier to understand with a simple "box" model):


You can draw a box picture (which I can’t here) to show as follows:-

Cost of 1 Apple = 1 unit
Cost of 1 Pear = 1 unit + $ 0.70

Cost of 42 Apples = 42 units
Cost of 12 Pears = 12 units + 12 x $ 0.70 = 12 units + $ 8.40

put the two box models, one on top of the other, and the student will see clearly

30 units = $ 8.40
1 unit = $ 0.28
42 units = $ 11.76

Mrs Tan spent $ 11.76 on the apples.

Best Regards,
iCreative Math

[sembgal]

Is iCreative Math related to iCreative Learners?

[iCreative Math]

No. Not Related.

[iCreative Math]

Man_at_work:

Man_at_work:

Can anyone help me with this problem? Many thanks!


4 children Amos, Bala, Chris and Darren, each have some marbles. The number of marbles that Amos has is 1/2 of the total number of marbles that Bala, Chris and Darren have. The number of marbles that Chris has is 1/4 of the total Amos,Bala and Darren have. The number of marbles that Bala has is 2/3 of the total number of marbles that Amos, Chris and Darren have.

Please, anybody can help? Thanks in advance

Your question is incomplete. It is missing one statement that usually says in total they have how many marbles or Bala has 10 more marbles than Amos, etc.

The problem-solving approach will then be as follows:

The ratios between them are 1:2, 1:4, and 2:3, i.e. total of 3 units, 5 units and 5 units respectively.

The lowest common multiple, LCM (which P5 should have learnt) for 3, 5 and 5 is 15.

We therefore start with a total of 15 units for A, B, C & D.

Amos' share compared to the rest is 1:2, hence Amos has 5 units (1/3 x 15).

Chris' share compared to the rest is 1:4,hence Chris has 3 units (1/5 x 15)

Bala's share compared to the rest is 2:3, hence Bala has 6 units (2/5 X 15)

Hence, Darren has 1 unit (15 - 5 - 3 - 6)

In practice, P5 students are not expected to be able to write these statements. These are not necessary. I have included them here to explain the steps. In practice, students need to simply draw a table and complete the table with the number of units A, B, C and D with simple calculation e.g. 1/3 X 15, 2/5 X 15, etc to show how they arrive at the number of units for each person.

Hope this this helpful.

Regards,

iCreative Math

[sembgal]

iCreative Math:

Alternative Method - (some students may find it easier to understand with a simple \"box\" model):


You can draw a box picture (which I can't here) to show as follows:-

Cost of 1 Apple = 1 unit
Cost of 1 Pear = 1 unit + $ 0.70

Cost of 42 Apples = 42 units
Cost of 12 Pears = 12 units + 12 x $ 0.70 = 12 units + $ 8.40

put the two box models, one on top of the other, and the student will see clearly

30 units = $ 8.40
1 unit = $ 0.28
42 units = $ 11.76

Mrs Tan spent $ 11.76 on the apples.

Best Regards,
iCreative Math

This method is easy to understand. Are you a tutor from iCreative Math?