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    Q&A - P3 Math

    Scheduled Pinned Locked Moved Primary 3
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    • S Offline
      shurley197323
      last edited by

      Thanks. Ks2me. But still unclear about Q2. If u don’t mind, can explain in other ways?

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      • corneyAmberC Offline
        corneyAmber
        last edited by

        shurley197323:
        Thanks. Ks2me. But still unclear about Q2. If u don't mind, can explain in other ways?

        q1 n 2 are similar in concept. Both testing multiplication table.

        In q1 it is told, the difference is 1 more straight forward to simulate the answer. In q2, I use the equation 7*u packets +5 =9*v packets + 6 = total number of hairpins to find out what is the difference amt like in q1.
        Rearranging the equation, I get 7*u = 9*v +1. So now it becomes same as q1 pattern, can u see that?

        In q2 harder to see directly becos it takes 7*13 to get 91 and usually our mental times table stops at 7*12 but right hand side easy to see 90+1 mentally. Anyway for p3/p4 level for guess n check method usually the multiples won't be too difficult.

        Hope this explains better.
        Basically math is alot about putting it into a pattern easy to see intuitively.

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        • Suz855S Offline
          Suz855
          last edited by

          Need help to validate answer, thanks



          http://www.postimage.org/

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          • S Offline
            small
            last edited by

            Suz855:
            Need help to validate answer, thanks



            http://www.postimage.org/
            Hi Suz855,

            Hope this helps. My method might not so clear as I am still under learning stage. :oops:

            http://s3.postimage.org/rd5ES-fe3f4cfd2c241f4acdbf433ec3730af2.png\">

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            • corneyAmberC Offline
              corneyAmber
              last edited by

              Small, I cannot see your answer image as it is not coming out on the screen.


              Here's my solution:

              1+2005 = 2006
              3 +2003 = 2006
              5 + 2001 = 2006
              :
              :
              1 to 2005 = 2005 numbers
              Number of odd numbers = 1003
              So number of pairs of odd numbers to give total 2006 = 1002/2 = 501
              so there are 501 whole numbers because (1+2005)/2006 = 1 + (3+2003)/2006=1 + ......................+ (1001+1005)/2006=1

              Middle odd number without a pair would be = 1003

              So 501 + 1003/2006 = 501 + 0.5 = 501.5

              Is this P3/P4 question?

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              • S Offline
                small
                last edited by

                Bingo ks2me.


                Your method looks more pro.. :celebrate:

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                • corneyAmberC Offline
                  corneyAmber
                  last edited by

                  small:
                  Bingo ks2me.


                  Your method looks more pro.. :celebrate:
                  Aiyo small, no la, share your image again as it is not visible on screen. No comparison intended, we all just post our learnings here together as parents. Different kids take to different approaches so it is good to share a few methods in order to know what works for the children.

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                  • S Offline
                    small
                    last edited by

                    Hi ks2me.


                    Sure..I have uploaded the picture again, it is similar to your method.

                    I used 'U' shade method to solve the question. :oops:

                    http://www.postimage.org/image.php?v=Pqrd5ES

                    http://www.postimage.org/image.php?v=Pqrd5ES

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                    • corneyAmberC Offline
                      corneyAmber
                      last edited by

                      Small, your approach is good and concise. :celebrate:

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                      • Suz855S Offline
                        Suz855
                        last edited by

                        Thanks KS2me, this qn is taken from an assessment book … as suspect, the answer given was incorrect.


                        Thanks for your solution, appreciate

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