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    O-Level Chemistry

    Scheduled Pinned Locked Moved Secondary Schools - Academic Support
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    • K Offline
      KSP2013777
      last edited by

      Thank you, hmong, for yr answer.

      1 Reply Last reply Reply Quote 0
      • K Offline
        KSP2013777
        last edited by

        Now I little bit worry. How u know answer they want is moles of chlorine molecules or moles of chlorine atoms. This question never say which one… so can give any one answer?

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        • K Offline
          KSP2013777
          last edited by

          How many atoms are there in 2 moles of ammonia gas?


          My friend say 2 X 6 X 10^23 = 12 × 10^23 atoms

          But I think must break up NH3 first

          Hydrogen : 2 × 6 × 10 ^ 23 = 12 × 10 ^ 23 hydrogen atoms
          Nitrogen : 2 × 3 × 6 × 10 ^ 23 = 36 × 10^23 nitrogen atoms
          total atoms = 48 × 10^23 atoms

          We argue long time about this. Who correct? My friend or I?

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          • S Offline
            Skyed
            last edited by

            Split. Your friend is correct if they ask number of molecules, not number of atoms.

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            • D Offline
              Dr.033430Daniel
              last edited by

              KSP2013777:
              How many atoms are there in 2 moles of ammonia gas?


              My friend say 2 X 6 X 10^23 = 12 × 10^23 atoms

              But I think must break up NH3 first

              Hydrogen : 2 × 6 × 10 ^ 23 = 12 × 10 ^ 23 hydrogen atoms
              Nitrogen : 2 × 3 × 6 × 10 ^ 23 = 36 × 10^23 nitrogen atoms
              total atoms = 48 × 10^23 atoms

              We argue long time about this. Who correct? My friend or I?
              You are correct that you have to break up the NH3 into atoms first. In your calculation you multiplied the number of nitrogen atoms by 3, but you need to do that for the hydrogen. I think you meant to say this:

              Nitrogen : 2 × 6 × 10 ^ 23 = 12 × 10 ^ 23 nitrogen atoms
              Hydrogen : 2 × 3 × 6 × 10 ^ 23 = 36 × 10^23 hydrogen atoms
              total atoms = 48 × 10^23 atoms

              The number of ammonia molecules is 2 X 6 X 10^23 = 12 × 10^23 molecules.

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              • K Offline
                KSP2013777
                last edited by

                Thank you Dr Daniel for your explain. Yes, sorry I type too fast, little bit mix up.


                I have new question. How many atoms are there in 64g of sulphur?
                chemical formula for sulphur is S8 or S2?
                If S8, then 64 ÷ (8×32) = 0.25 mol
                0.25 X 6 X 10^23 = 1.5 × 10^23 sulphur atoms

                Is this correct?

                Pls help. Tks

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                • D Offline
                  Dr.033430Daniel
                  last edited by

                  Hi KSP – Sulphur is an element and it is a solid at room temperature, so there is no chemical formula for it. It’s just S1, although a chemist would not write S1, they would just write S. Sulphur is a yellow powder in it’s elemental form.


                  According to the Periodic Table of the elements sulphur has an atomic mass of 32, meaning 32 grams per mole. That means that 32 grams would be one mole and double that or 64 grams, would be 2 moles. That comes out to 12 X10^23.

                  If you have a periodic table just look up Aluminium and you’ll see that it has an atomic mass of 27. If I have 27 grams of Aluminium then I have 1 mole. So 27 grams of Aluminium has the same number of atoms as 32 grams of sulphur.

                  I have several samples of metals that are all one mole. I was showing these to some students just yesterday. It’s neat to see all the metals lined up with the same number of atoms in each sample.

                  There are times when an element has more than one atom and this would be the case for so called “diatomic gasses”. An example is the Oxygen we breathe. It pairs up as a gas into a molecule of O2. Oxygen has an atomic mass of 16, so if a question asked how many oxygen atoms are in 16 grams of oxygen gas, then the answer would be one mole. But if they asked how many oxygen molecules are in 16 grams of oxygen gas, then the answer would be half a mole.

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                  • H Offline
                    HappieNewbie123
                    last edited by

                    Hi I require some help for these 2 redox reaction questions:


                    Q1)
                    Equations given:
                    1) Cl2(g) + H2S(g) –> 2HCl(g) + S(s)
                    2) SO2(g) + 2H2S(g) –> 2H2O(l) + 3S(s)
                    3) Cl2(g) + 2H2O(l) + SO2(g) –> 2HCl(aq) + H2SO4(aq)

                    a) From the equations given, deduce which of the three gases: chlorine, hydrogen sulfide and sulfur dioxide is the strongest
                    i) Oxidation agent
                    ii) Reducing agent

                    b) State how you arrive at your answers.

                    Q2) Disproportionation is a reaction in which the same element is both oxidized and reduced in a reaction.
                    Explain why the following reaction is a disproportionation reaction.
                    Cl2 + 2NaOH –> NaCl + NaOCl + H2O

                    (Oxidation state of NaOCl is not balanced? Na is +1, O is -2 and Cl is -1?? I find this a bit strange…)
                    Thank you!

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                    • D Offline
                      Dr.033430Daniel
                      last edited by

                      HappieNewbie123:
                      Hi I require some help for these 2 redox reaction questions:


                      Q1)
                      Equations given:
                      1) Cl2(g) + H2S(g) --> 2HCl(g) + S(s)
                      2) SO2(g) + 2H2S(g) --> 2H2O(l) + 3S(s)
                      3) Cl2(g) + 2H2O(l) + SO2(g) --> 2HCl(aq) + H2SO4(aq)

                      a) From the equations given, deduce which of the three gases: chlorine, hydrogen sulfide and sulfur dioxide is the strongest
                      i) Oxidation agent
                      ii) Reducing agent

                      b) State how you arrive at your answers.

                      Q2) Disproportionation is a reaction in which the same element is both oxidized and reduced in a reaction.
                      Explain why the following reaction is a disproportionation reaction.
                      Cl2 + 2NaOH --> NaCl + NaOCl + H2O

                      (Oxidation state of NaOCl is not balanced? Na is +1, O is -2 and Cl is -1?? I find this a bit strange...)
                      Thank you!
                      I asked our new Chemistry tutor these questions. Here are the answers:

                      1(a)
                      Strongest Oxidising Agent: Cl2
                      Strongest Reducing Agent: H2S

                      (b) From the first two equations, we can see that S always oxidised from -2 in H2S to 0 in S by both Cl2 and SO2. Granted, its ease of being oxidised makes it the strongest reducing agent. Then we look at the 3rd equation, where Cl is still reduced from 0 in Cl2 to -1 in HCl, while S is oxidised from +4 in SO2 to +6 in H2SO4. This indicates that SO2 is more easily oxidised than Cl2 (and thus a stronger reducing agent). Hence, the strength of oxidising agents is as such: Cl2 > SO2 > H2S

                      2) The reaction is a disproportionation reaction because Cl is 0 in Cl2, and it is concomittantly reduced to -1 in NaCl and oxidised to +1 in NaOCl.

                      *The oxidiation state of Na is always +1, O is generally -2 (except in cases of peroxides and superoxides), and for Cl to fulfill charge neutrality it has to be +1 in NaOCl.

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                      • I Offline
                        iamastudent
                        last edited by

                        Hi,

                        May I know what is the oxidation state of ions? Example like the equation:
                        (S2O3)2- + 4Cl2 + 5H2O –> 2(SO4)2- + 8Cl- + 10H+

                        What is the oxidation state of H in H+? Is it +1 or is it 0?
                        O in (SO4)2-? Is it -2? S in (SO4)2-? Is it +6? Thank you

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