Tutor MathsGuru: Ask me for your burning Maths questions!

[mathsguru]

P5G:

Pl help.


Paper 1 Q13.
http://www.orlesson.org/orp/09Ma/2009-Math-SA1-MGS.pdf


Worksheet answer is (4) 135 [not likely].


Please advise how to get (3) 125 as Benny's score?


TIA.

Hi P5G,

Sorry for the late reply. Here's my answer.


MathsGuru

http://www.postimage.org/image.php?v=aVjUVjJ

[KSP]

I need help on the 2 questions below.


1. The figure below is not drawn to scale. Given that the area of WXYZ is 40cm sq, find the area of the shaded part. Ans: 68cm sq

http://www.postimage.org/image.php?v=aVjVKHJ



2. The figure below is made up of two identical right-angled triangles, a small square and a big square. The parimeter of the shaded region is 50cm, and the total area of the two unshaded squares is 254.5cm sq. Find the total area of the two shaded right-angled triangles. Ans: 114.75cm sq

http://www.postimage.org/image.php?v=gxNVMm9

[mathsguru]

mmmouse:

Anyone knows how to solve this Pr. 3 Maths question?


5 erasers + 3 rulers = S$5.05
3 erasers + 6 rulers = S$3.95
2 erasers + 2 rulers = ???

Thanks!

Hi Mmmouse,

Think there's probably a typo error in the question, cos I can't seem to get nice numbers for the answers and I think for P3, they haven't learnt rounding off yet.

In any case, here's my solution. You can follow the steps. It's the same kind of steps to solve such questions.

Cheers,
MathsGuru

http://www.postimage.org/image.php?v=aVjVXar

[Dharma]

KSP:

I need help on the following questions.


1. Container A contains 250 red marbles and 200 blue marbles. Container B contains 600 red marbles and 150 blue marbles. How many red and blue marbles must be moved from Container A to Container B such that 25% of the marbles in Container A are red and 75% of the marbles in Container B are red? Ans: 350


2. In a math competition, participants can obtain 4 possible award: Gold, Silver, Bronze and Participation. 3/7 of the participants obtained Gold awards, 1/4 of the them obtained Silver awards, and 1/6 of them obtained Bronze awards. Given that there were less than 100 participants taking the competition,
a) How many participants obtained the awards for Participation? Ans: 13
b) How many more participants obtained Gold awards then Bronze awards? Ans: 22

Q1
Container A
Red : 250 – 1u [25%]
Blue : 200 – 1p [75%]

(250 – 1u) x 3 = 200 – 1p
3u – 1p = 550 …………..(1)

Container B
Red : 600 + 1u [75%]
Blue : 150 + 1p [25%]

(150 + 1p) x 3 = 600 + 1u
3p – 1u = 150 …………..(2)

8u = (1550 x 3) + 150 = 1800 ….solving (1) and (2)
1u = 225 red marbles
1p = 225 x 3 -550 = 125 blue marbles
No. of red and blue marbles moved = 225 + 125 = 350


Q2
Gold : 36/84
Silver : 21/84
Bronze : 14/84

a)\tNo. participants obtained Participation = 84 – 36 – 21 – 14 = 13
b)\t36 – 14 = 22 participants received gold than bronze.

[KSP]

Dharma:

Q2
Gold : 36/84
Silver : 21/84
Bronze : 14/84

a)\tNo. participants obtained Participation = 84 – 36 – 21 – 14 = 13
b)\t36 – 14 = 22 participants received gold than bronze.

How do you get 84?

[Dharma]

KSP:

I need help on the 2 questions below.


1. The figure below is not drawn to scale. Given that the area of WXYZ is 40cm sq, find the area of the shaded part. Ans: 68cm sq

http://www.postimage.org/image.php?v=aVjVKHJ

The shaded area consist of 2 triangles with height of 18cm and total base length of 12cm but the have an overlapping area of 40cm2 (i.e. Area of WXYZ)
Shaded area = (½ x 18 x 12)cm2 – Area of WXYZ = 108cm2 – 40cm2 = 68cm2

[Dharma]

KSP:

I need help on the 2 questions below.



2. The figure below is made up of two identical right-angled triangles, a small square and a big square. The parimeter of the shaded region is 50cm, and the total area of the two unshaded squares is 254.5cm sq. Find the total area of the two shaded right-angled triangles. Ans: 114.75cm sq

http://www.postimage.org/image.php?v=gxNVMm9

Side of large square = 1u
Side of small square = 1p

1u + 1p = (50 – 6)/ 2 = 22

Slide up the triangle with the larger square up the slope and u get 2 squares and a rectangle.

Shaded area = [(1u + 1p) x (1u + 1p) – 254.5] / 2 = [(22 x22) – 254.5] /2 = 114.75

[Dharma]

KSP:

How do you get 84?

84 is the smallest number that is divisible by 4,6 and 7

[KSP]

Dharma:

84 is the smallest number that is divisible by 4,6 and 7

Thanks for all your help.

[mathsguru]

YLH88:

Hi Mathsguru,


Need your help with the below question :

Dan and Mark received some money from their father.
Mark would have $128 more than Dan if Dan gave 2/5 of his share to Mark.
Mark would have $288 more than Dan if Dan gave 2/3 of his share to Mark.
How much money did Dan receive from his father ?

Thank you so much!

Hi YLH88,

Here's my solution. Apologies for the delayed reply.


MathsGuru

http://www.postimage.org/image.php?v=Pqys7r0