Tutor MathsGuru: Ask me for your burning Maths questions!
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After spending 2/5 of his money on markers, he left with 3/5 of his money left. He then spend 1/3 of the remainder on a highlighter.
So..
1/3 * 3/5= 1/5
so he actually spend 1/5 of his money on the highlighter.
Since we know he spend $0.90 on highlighter, we know the amount he spend on markers is $0.90 x 2=$1.80
Does this clear the question?

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Guan Hui:
Yes, it is very clear. Thanks so much.After spending 2/5 of his money on markers, he left with 3/5 of his money left. He then spend 1/3 of the remainder on a highlighter.
So..
1/3 * 3/5= 1/5
so he actually spend 1/5 of his money on the highlighter.
Since we know he spend $0.90 on highlighter, we know the amount he spend on markers is $0.90 x 2=$1.80
Does this clear the question?

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Hi,
I am not able to open the solutions provided by mathsguru and the other parents. Is it something wrong with my pc ? Please help me.
Thank you. -
Hi again,
I desperately needed those model solutions provided by all the helpful parents. I am having a really hard time helping my girl with her maths paper. Please help me !!
When I click on the picture, it shows a cross. If I save it as "save picture as" I am not able to see it clearly at all. I only encounter this problem today.
Would appreciate your help. Thank you. -
starlight1968sg:
This is Q17 [5 marks] from http://www.orlesson.org/orp/09Ma/2009-Math-SA1-MahaBodhi.pdf set on 5 May 2009.1) Andy, Betty, Candy and Danny each have some money. The amount of money Andy has is 1/3 of the total amount of money Betty, Candy and Danny have. The amount of money Betty has is 1/4 of the total amount of money Andy, Candy and Danny have. The amount of money Candy has is 1/5 of the total amount of money Andy, Betty and Danny have. If Danny has $1725, how much do they have altogether?
starlight1968sg:
This is Q16 [5 marks] from http://www.orlesson.org/orp/09Ma/2009-Math-SA1-MahaBodhi.pdf set on 5 May 2009.2) Tom and Jerry each has some money. If Tom spends $90 per day and Jerry spends $45 per day, Tom will have $1100 left when Jerry has spent all his money. If Tom spends $45 each day and Jerry spends $90 each day, Tom will have $1700 left when Jerry has spent all his money. How much did Jerry have?
This is similar to a 4-mark question from http://www.wendykoh.com/08/primary6-acssa2-maths.pdf set on 20 Aug 2008. -
Hi all,
My problem is somehow solved after I rebooted my pc. thank you. -
sachiko:
1 - 2/5 = 3/52. A highlighter costs 3 times as much as a marker. Bert spent 2/5 of his money on markers and 1/3 of the remainder on a pen. The highlighter cost $0.90. How many markers did he buy?
Thank you.
1/3 x 3/5 = 1/5
3/5 - 1/5 = 2/5
2 u --> $0.90
1 highlighter --> $0.90
1 marker --> 1/3 x 0.90 = $0.30
0.90/0.30 = 3 markers
He bought 3 markers. -
Dear mathsguru
Good morning.
Please help me on the following maths:
1) A man travels from Town X to Town Y at 4 Km/h and from Town Y to Town X at 6 Km/h via the same route. The whole journey takes 45 minutes. Find the distance from Town X to Town Y.
Given answer 1.8 Km, however my answer is 1.875 km.
2) A pen costs 40 cents more than a ruler. John paid $x for a pen and a ruler. Find the cost of a ruler in cents.
Given answer is (50-20)cents
3) A Spaceship lego set cost $80 more than a Tommy train set at a toyshop. During its anniversar, a storewide 20% discount was given to all customers. In addition, members of the toyshop enjoy an addtional 10% discount. Mr. Tan, a member of the toyshop, paid a total of $345.60 for the Spaceship lego set and the Tommy train set. Calculate the original price of the Spaceship set.
Given answer is $28
4) Mr. Tan took 6 hours to drive from Town A to Town B.
Mr. Lim, who started at the same time as Mr. Tan, took 4 hours to drive from Town B to Town A. When they meet each other, they were 48 km from the midpoint of Town A and Town B.
(a) Calculate the distance between Town A and Town B.
(b) Calculate the speed of Mr. Tan.
5) 20% of John’s saving is $120 more than 30% of Brian’s savings. After John spent 5/6 of his savings and Brian spent 1/2 of his savings, John has $20 more than Brian. Find the saving of John at first.
Many thanks
firebird -
Hi firebird,
All your 5 questions are taken from Catholic High School 2009 Primary 6 Preliminary Examination 3 Maths set on 26 August 2009.firebird:
This is a 2-mark question from Q30 - paper 1.1) A man travels from Town X to Town Y at 4 Km/h and from Town Y to Town X at 6 Km/h via the same route. The whole journey takes 45 minutes. Find the distance from Town X to Town Y.
Concept - For constant/fixed/same distance, speed is inversely proportional to time.
Ratio of speed
4 : 6
Ratio of time
6 : 4
Total time = 45 min = 0.75 h
(6+4)units = 10 units
10 units = 0.75 h
1 unit = 0.075 h
Time taken for the man to travel from Town X to Town Y at 4 km/h = 6 units x 0.075 h = 0.45 h
Distance from Town X to Town Y = 0.45 h x 4 km/h = 1.8 km
firebird:
This is a 2-mark question from Q1 - paper 2.2) A pen costs 40 cents more than a ruler. John paid $x for a pen and a ruler. Find the cost of a ruler in cents.
$x = 100x cents
Ruler -> u
Pen -> u + 40 cents
Total cost of a pen and a ruler = 100x cents
Cost of a ruler = (100x-40)cents÷2 = (50x-20) centsfirebird:
This is a 5-mark question from Q16 - paper 2.3) A Spaceship lego set cost $80 more than a Tommy train set at a toyshop. During its anniversar, a storewide 20% discount was given to all customers. In addition, members of the toyshop enjoy an addtional 10% discount. Mr. Tan, a member of the toyshop, paid a total of $345.60 for the Spaceship lego set and the Tommy train set. Calculate the original price of the Spaceship set.
Spaceship Lego Set -> SL
Tommy train -> TT
SL = 100%+$80
TT = 100%
For members only:
SL = [80/100x(100%+80)]x90/100
= (80%+64)x90/100
= 72% + $57.60
TT = (80/100x100%)x90/100
= 72%
72%+72%+$57.60 = $345.60
144% = $288
1% = $2
100% = $200
$(200+80) = $280
Original price of the Spaceship Lego set was $280 -
firebird:
This is a 5-mark question from Q17 - paper 2 from Catholic High School 2009 P6 Prelim Exam 3 set on 26 August 2009.4) Mr. Tan took 6 hours to drive from Town A to Town B.
Mr. Lim, who started at the same time as Mr. Tan, took 4 hours to drive from Town B to Town A. When they meet each other, they were 48 km from the midpoint of Town A and Town B.
(a) Calculate the distance between Town A and Town B.
(b) Calculate the speed of Mr. Tan.
Ratio of time
Mr Tan : Mr Lim
6 : 4
Ratio of distance
Mr Tan : Mr Lim
4 : 6
Distance from Town A to midpoint for Mr Tan -> 4 units + 48 km
which was the same as distance from midpoint to Town B for him.
At the point where both met @ 48 km away from midpoint, Mr Lim had travelled 6 units.
6 units = 48km + 48km + 4 units
2 units = 96 km
1 unit = 48 km
Total distance = (4+6) units = 10 units
10 units = 48x10 = 480 km
(a) Distance between Town A and Town B was 480 km
(b) Speed of Mr Tan = 480 km÷6 hours = 80 km/h
Pls refer to this http://prischoolmaths.blogspot.com/2009/06/maths-speed_4616.html for clear understanding which has the same concept. This is ACS(J)/ACS(P)2008 P6 Prelim Q43.
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