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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • V Offline
      Vanilla Cake
      last edited by

      Hi Mathsguru,

      Pls help my P5 younger sister to solve this 4-mark question from http://www.orlesson.org/orp/09Ma/2009-Math-SA1-ACS.pdf using models. Thank you.

      The volume of water in bottle P was 3/5 of that in bottle Q. After 60 ml of water was added to bottle P and 20 ml was poured away from bottle Q, the amount of water in bottle P was 3/4 that in bottle Q. What was the amount in each bottle at first?

      Other than models, what are your recommended method/s to tackle such problem sum?

      1 Reply Last reply Reply Quote 0
      • L Offline
        lemofish
        last edited by

        Got it! Thank you!

        1 Reply Last reply Reply Quote 0
        • G Offline
          Guan Hui
          last edited by

          Hi vanilla cake! 😄 ,

          other ways.. for me the most convenient is of course algebra.

          Algebra
          P amount = x
          Q amount = y
          5x=3y-----1
          4(x+60)=3(y-20)
          4x+240=3y-60
          4x+300=3y------2
          5x=4x+300
          x=300ml
          y=500ml

          Ratio(sort of)
          P :Q
          3units :5units
          +60 -20
          3 units +60= 3nUnits(nunits= new units)
          1 nunit= 1unit+20
          3 :4 (ratio is in nunit)
          3u +60:4u+80

          5 u-20=4u+80
          1u=100
          initially P have 3 u.. so 300ml.
          Q have 5 u... so 500ml.


          Hope you understand 1 of them=/

          1 Reply Last reply Reply Quote 0
          • S Offline
            speedmaths.012624com
            last edited by

            Vanilla Cake:
            Hi Mathsguru,

            Pls help my P5 younger sister to solve this 4-mark question from http://www.orlesson.org/orp/09Ma/2009-Math-SA1-ACS.pdf using models. Thank you.

            The volume of water in bottle P was 3/5 of that in bottle Q. After 60 ml of water was added to bottle P and 20 ml was poured away from bottle Q, the amount of water in bottle P was 3/4 that in bottle Q. What was the amount in each bottle at first?

            Other than models, what are your recommended method/s to tackle such problem sum?
            Hi Vanilla Cake,

            The volume of water in bottle P was 3/5 of that in bottle Q.
            After 60 ml of water was added to bottle P and 20 ml was poured away from bottle Q, the amount of water in bottle P was 3/4 that in bottle Q.
            What was the amount in each bottle at first?

            Let’s CHANGE the question (but still using the SAME numbers) to:

            In a shop, the ratio of the number of apples to the number of oranges was 3:5, at first.
            The shopkeeper bought 60 more apples, and sold 20 oranges.
            As a result, the ratio of the number of apples to the number of oranges became 3:4.
            How many apples and how many oranges, were there in the shop at first?

            This is a typical Double-Ratio Question, quite common in the PSLE.

            Using the Bags and Boxes Method (which can solve ALL such Double-Ratio Questions):
            (Once you are familiar with the method, you can cut down some of the steps below)


            At first, the apples / oranges were kept in Bags.
            Each Bag contains the same number of apples / oranges.
            There were 3 Bags of apples, and 5 Bags of oranges, at first.

            After 60 apples were added, and 20 oranges were removed,
            the apples / oranges were then kept in Boxes.
            Each Box contains the same number of apples / oranges.
            There were 3 Boxes of apples, and 4 Boxes of oranges.

            Apples:
            3 bags + 60 apples = 3 Boxes
            (x 4)
            12 bags + 240 apples = 12 Boxes

            Oranges:
            5 bags – 20 oranges = 4 Boxes
            (x 3)
            15 bags – 60 oranges = 12 Boxes

            12 Boxes = 12 bags + 240 apples = 15 bags – 60 oranges
            12 bags + 240 apples = 15 bags – 60 oranges
            0 bags + 240 apples = 3 bags – 60 oranges
            240 apples = 3 bags – 60 oranges
            300 apples / oranges = 3 bags
            1 Bag = 100 apples / oranges
            There were 3 Bags of apples, and 5 Bags of oranges, at first.

            There were 300 apples, and 500 oranges, at first. (ANSWER)

            1 Reply Last reply Reply Quote 0
            • D Offline
              Dharma
              last edited by

              Vanilla Cake:
              Hi Mathsguru,

              Pls help my P5 younger sister to solve this 4-mark question from http://www.orlesson.org/orp/09Ma/2009-Math-SA1-ACS.pdf using models. Thank you.

              The volume of water in bottle P was 3/5 of that in bottle Q. After 60 ml of water was added to bottle P and 20 ml was poured away from bottle Q, the amount of water in bottle P was 3/4 that in bottle Q. What was the amount in each bottle at first?

              Other than models, what are your recommended method/s to tackle such problem sum?
              Hi Vanilla Cake,

              Your sister may wish to look at this while waiting for Mathsguru’s solution.


              http://www.postimage.org/image.php?v=gxEDrbJ

              1 Reply Last reply Reply Quote 0
              • O Offline
                OK Lor
                last edited by

                Hi Mathsguru,


                The product of two numbers, A and B, is 108. The difference betweeen A and B is a common factor of A and B. Find the values of A and B.

                Thanks.

                1 Reply Last reply Reply Quote 0
                • D Offline
                  Dharma
                  last edited by

                  OK Lor:
                  Hi Mathsguru,


                  The product of two numbers, A and B, is 108. The difference betweeen A and B is a common factor of A and B. Find the values of A and B.

                  Thanks.
                  108 = 2 X 2 X 3 X 3 X 3 = 12 X 9
                  A = 12, B = 9 (A – B = 12- 9 = 3)
                  3 is a common factor of both 12 and 9.

                  1 Reply Last reply Reply Quote 0
                  • H Offline
                    Herbie
                    last edited by

                    Hi, Maths Guru and all


                    Can help to solve the qn below?

                    Amy and Tommy each have some money. If Amy spends $50 per day and Tommy spends $60 per day, Amy would still have $500 left when Tommy has spent all his money.
                    If Amy spends $60 per day and Tommy spends $50 per day, Amy would still have $280 left when Tommy spent al his money. How much money does Tommy have?

                    Tx

                    1 Reply Last reply Reply Quote 0
                    • C Offline
                      ck123
                      last edited by

                      Hi all


                      I need help with the model for this question.

                      The number of marbles in Box A, Box B and Box C was 195.
                      John added 60 marbles to those in Box A, doubled the number of marbles in Box B and halved the number of marbles in Box C.
                      The ratio of the number of marbles becomes 4:1:2.
                      What is the total number of marbles in the three boxes now?

                      Thanks

                      1 Reply Last reply Reply Quote 0
                      • V Offline
                        Vanilla Cake
                        last edited by

                        Herbie:
                        Amy and Tommy each have some money. If Amy spends $50 per day and Tommy spends $60 per day, Amy would still have $500 left when Tommy has spent all his money.

                        If Amy spends $60 per day and Tommy spends $50 per day, Amy would still have $280 left when Tommy spent al his money. How much money does Tommy have?
                        Hi Herbie,
                        Your question is similar to this http://www.postimage.org/image.php?v=gxtwwpi which Mathsguru had provided clear explanations.

                        1st case
                        Amy : Tommy
                        5 : 6
                        25 : 30

                        2nd case
                        Amy : Tommy
                        6 : 5
                        36 : 30

                        Draw models for better visualisation,
                        1st case
                        Amy: 25 units + a long block to indicate $500 left
                        Tommy : 30 units

                        2nd case
                        Amy: 36 units + a long block to indicate $280 left
                        Tommy: 30 units

                        Make sure that total length of both blocks for Amy in 1st/2nd case must be the same.

                        25 units+$500=36 units+$280
                        11 units = $220
                        1 unit = $20

                        Tommy has 30 units = $600

                        Check
                        1st case - 10 days
                        Amy -> $1000-(10x$50) = $500
                        Tommy=> $600-(10x60) = 0

                        2nd case - 12 days
                        Amy -> $1000-(12x60) = $280
                        Tommy -> $600-(12x50) = 0

                        1 Reply Last reply Reply Quote 0

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