O-Level Additional Math

[tweet]

Hi Guan Hui


Thanks for your help.Will show the worked solution to my son.

Rgds

[emerald]

Hi, need your help to solve the following using Commutative Laws, Associative Laws &/or Distributive Laws (Easy method):


(54.2 x 1.8 + 0.2 x 25.86)


TIA.

[Guan Hui]

54.2x1.8+0.2x25.86

= 54.2x9x0.2+25.86x0.2
=0.2(54.2 x 9+25.86)
=0.2(50x9+4.2x9+25.86)
=0.2(450+37.8+25.86)
=0.2(513.66)
=102.732

I do not know if this is the answer you want emerald.
For me I will jus take 54.2 x 1.8 and 0.2 x 25.86 it will be much easier.

For multiplication of decimals just need to remember these 2 examples:
54.2 x 1.8(take not 54.2 have 1 decimal place and 1.8 have 1 decimal place also)
Total decimal place =1+1= 2
ignore the dots....
542 x 18= 9756
bring in the dot... 2 decimal place
ans=97.56

another example:
0.1 x 0.01 (total decimal 3)
remove dots... 1x1 =1
put in dot 3 decimal place..
ans: 0.001

hope it helps

[emerald]

Thanks a lot, Guan Hui.

[OK Lor]

Hi Guan Hui,


Please help to solve:

x²-286x+c=0 has roots a²b and ab². x²+px+q=0 has roots a and b. Find p and q, given that a, b and c are integer positive.

Thanks.

[Guan Hui]

if x²-286x+c=0 have root a²b and ab²

means
(x-a²b)(x-ab²)=0
expand it
x²-ab²x-a²bx+a^3b^3=0
x²-(ab²+a²b)x+a^3b^3=0
so…
ab²+a²b=286------1
a^3 b^3=c---------2

x²+px+q=0
(x-a)(x-b)=0
x²+x(-a-b)+ab=0
-a-b=p--------------3
ab=q----------------4



ab²+a²b=286
ab(a+b)=286
since a b and c are integer positive
ab and (a+b) are integer positive
factors of 286
1x286
2x143
11x26
13x22

13=(11+2) while 22 =(11x2)
a=11 or 2 and b=2 or 11
c= a^3b^3=11^3 2^3
c=10648

p=-a-b
p=-13
q=11x2
=22

sorry for late answer just saw it this morning.

[OK Lor]

Hi Guan Hui,


Thanks a lot, cheers.

[Muffins]

Hey Guan Hui, Secondary version of Mathsguru!

[Guan Hui]

Muffins:

Hey Guan Hui, Secondary version of Mathsguru!

I am so flattered haha=) Just glad i can do something for this awesome community.

[Muffins]

Hey, don't ever forget, you are part of this awesome community!