Tutor MathsGuru: Ask me for your burning Maths questions!
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CoffeeCat:
Thank you Coffeecat!
twice of a number=> 10/5 of the numberCheerfuldad:
Q 1. Twice a number is greater than 3/5 of the number by 21. What is 2/3 of the number?
Q2. Aifangpi ans Sashimi had an equal amount of money. Each day, Aifangpi spent $60 and Sashimi spent $32. When Aifangpi has spent all her money. Sashimi still had $336 left. How much money had Aifangpi at first?
TIA
(10/5 - 3/5)= 7/5 of the number = 21
the number is (21/7) times 5 =15
2/3 of number is 10
since both had same amt of money at first, the $336 is due to the difference of 60 and 32.
Number of days = 336/(60-32)= 12
t
Amt of monev at first = 12 times 60=720
Have a good day! -
free willy:
Box AI don't know how to help my P6 boy with this homework question. He miss the class cause he had to go for tournment.
Box A has 200 red balls and 90 blue balls. Box B has 80 red balls and 100 blue balls. How many red balls and blue balls need to be moved from box A to Box B so that there are 80%of red balls in box A and 50% of blue balls in box B.
Red – 200/280 = 71.43%
Blue – 90/190 = 47.36%
How can you transfer red and blue balls out of Box A and into Box B and end up with higher percentages of balls in Box A… i.e. 80% of red balls and 50% of blue balls in Box A?
Think the question typed out wrongly ….. should from box B to box A , instead. -
free willy:
Hi free willy,Box A has 200 red balls and 90 blue balls. Box B has 80 red balls and 100 blue balls. How many red balls and blue balls need to be moved from box A to Box B so that there are 80%of red balls in box A and 50% of blue balls in box B.
Your question is similar to RGPS P6 SA1 2009 P2 Q18 and the model solution had been provided by http://www.postimage.org/image.php?v=aVNZHuS on 22 Mar 2010.
Tang had also provided his http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&postdays=0&postorder=asc&start=1170 on 19 Mar 2010.
Using simultaneous equation to solve while waiting for Mathsguru's model solution.
Final scenario
Box A
Red balls : Blue balls
4 : 1 (80% : 20%)
Box B
Red balls : Blue balls
1 : 1 (50% : 50%)
4A+B = 200+80 = 280
A+B = 90+100 = 190
3A = 90
A = 30
B = 190-30=160
Final scenario
Box A
Red balls : Blue balls
120 : 30
Box B
Red balls : Blue balls
160 : 160
Before scenario
Box A
Red balls : Blue balls
200 : 90
Box B
Red balls : Blue balls
80 : 100
80 red balls and 60 blue balls to be moved from box A to Box B so that there are 80% of red balls in box A and 50% of blue balls in box B. -
Vanilla Cake:
Hi Vanilla Cake,
Hi free willy,free willy:
Box A has 200 red balls and 90 blue balls. Box B has 80 red balls and 100 blue balls. How many red balls and blue balls need to be moved from box A to Box B so that there are 80%of red balls in box A and 50% of blue balls in box B.
Your question is similar to RGPS P6 SA1 2009 P2 Q18 and the model solution had been provided by http://www.postimage.org/image.php?v=aVNZHuS on 22 Mar 2010.
Tang had also provided his http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&postdays=0&postorder=asc&start=1170 on 19 Mar 2010.
Using simultaneous equation to solve while waiting for Mathsguru's model solution.
Final scenario
Box A
Red balls : Blue balls
4 : 1 (80% : 20%)
Box B
Red balls : Blue balls
1 : 1 (50% : 50%)
4A+B = 200+80 = 280
A+B = 90+100 = 190
3A = 90
A = 30
B = 190-30=160
Final scenario
Box A
Red balls : Blue balls
120 : 30
Box B
Red balls : Blue balls
160 : 160
Before scenario
Box A
Red balls : Blue balls
200 : 90
Box B
Red balls : Blue balls
80 : 100
80 red balls and 60 blue balls to be moved from box A to Box B so that there are 80% of red balls in box A and 50% of blue balls in box B.
Don’t you think the statement, “there are 80% of red balls in box A ….” is different from “80% of balls in Box A are red …..” -
Dharma:
Hi Vanilla Cake,
Hi free willy,Vanilla Cake:
[quote=\"free willy\"]Box A has 200 red balls and 90 blue balls. Box B has 80 red balls and 100 blue balls. How many red balls and blue balls need to be moved from box A to Box B so that there are 80%of red balls in box A and 50% of blue balls in box B.
Your question is similar to RGPS P6 SA1 2009 P2 Q18 and the model solution had been provided by http://www.postimage.org/image.php?v=aVNZHuS on 22 Mar 2010.
Tang had also provided his http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&postdays=0&postorder=asc&start=1170 on 19 Mar 2010.
Using simultaneous equation to solve while waiting for Mathsguru's model solution.
Final scenario
Box A
Red balls : Blue balls
4 : 1 (80% : 20%)
Box B
Red balls : Blue balls
1 : 1 (50% : 50%)
4A+B = 200+80 = 280
A+B = 90+100 = 190
3A = 90
A = 30
B = 190-30=160
Final scenario
Box A
Red balls : Blue balls
120 : 30
Box B
Red balls : Blue balls
160 : 160
Before scenario
Box A
Red balls : Blue balls
200 : 90
Box B
Red balls : Blue balls
80 : 100
80 red balls and 60 blue balls to be moved from box A to Box B so that there are 80% of red balls in box A and 50% of blue balls in box B.
Don’t you think the statement, “there are 80% of red balls in box A ….” is different from “80% of balls in Box A are red …..” [/quote]Hi Dharma,
Thanks for your remainder.
Something is not right in the way this question is phrased.
free willy:
Hi free willy,I don't know how to help my P6 boy with this homework question. He miss the class cause he had to go for tournment.
Pls clarify with your P6 boy about this homework question and let us know.
Thanks. -
free willy:
I think 80% of red balls mean 80 % of total red balls while 50 % of blue balls means 50% of total blue ballsI don't know how to help my P6 boy with this homework question. He miss the class cause he had to go for tournment.
Box A has 200 red balls and 90 blue balls. Box B has 80 red balls and 100 blue balls. How many red balls and blue balls need to be moved from box A to Box B so that there are 80%of red balls in box A and 50% of blue balls in box B.
200+80=280 red balls
80% of 280=224 red balls
90+100=190 blue balls
50% of 190=95 blue balls
For me, from my interpretation 24 red balls and 5 blue balls need to be move from box B to A..
I dunno if I am correct.>.< Just my opinion.
(I know question say how many balls from BOX A to BOX B) -
Hi Maths Guru,
Please help me to solve the below question.
An MRT train was 2/5 full of passengers. At the first station, 1/2 of the passengers alighted and 17 people boarded the train. The train is now 1/4 full. How many passengers were there on the train at first?
Thank you.
Shemum -
shemum:
2/5 minus half = 1/5 = 0.2FullHi Maths Guru,
Please help me to solve the below question.
An MRT train was 2/5 full of passengers. At the first station, 1/2 of the passengers alighted and 17 people boarded the train. The train is now 1/4 full. How many passengers were there on the train at first?
Thank you.
Shemum
0.2Full + 17 = 0.25F
hence 17 = 0.05Full
original number = 0.4Full = 8 x 0.05Full = 8x 17 = 136
should be easy with the model / diagram method too -
shemum:
Let me try:Hi Maths Guru,
An MRT train was 2/5 full of passengers. At the first station, 1/2 of the passengers alighted and 17 people boarded the train. The train is now 1/4 full. How many passengers were there on the train at first?
Say, full train has 20 units.
2/5 full = 8 units.
1/2 alighted ==> 4 units alighted and left with 4 units.
17 people boarded ==> 4 units (left over) + 17
1/4 full = 5 units.
Thus, 1 unit = 17 passengers.
So MRT was originally 8 units = 136 passengers
Correct me if I am wrong. -
shemum:
Let me try:Hi Maths Guru,
An MRT train was 2/5 full of passengers. At the first station, 1/2 of the passengers alighted and 17 people boarded the train. The train is now 1/4 full. How many passengers were there on the train at first?
Say, full train has 20 units.
2/5 full = 8 units.
1/2 alighted ==> 4 units alighted and left with 4 units.
17 people boarded ==> 4 units (left over) + 17
1/4 full = 5 units.
Thus, 1 unit = 17 passengers.
So MRT was originally 8 units = 136 passengers
Correct me if I am wrong.
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