Q&A - PSLE Math
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1) There are 85 plates of fried noodle for 80 people. Each adult eats 2 plates of fried noodle and every three children share 1 plate of fried noodle. How many adults and children are there?
2) 20 boys and girls sold tickets for a funfair. Each ticket was sold at $5.Each boy sold 5 tickets and each girl sold 3 tickets. The amount collected by the boys was $20 more than the amount collected by the girls. Find a) how many girls were there in the group b) how many tickets were sold altogether?
3) Daniel has $160 more than Alex. After giving 1/10 of his money to Alex, he now has 3 times as much money than Alex. How much money do they have in the first place? -
More headache for us parents? Heheh. It’s good that we see these questions for ourselves… that way we respect our children even more if they managed to get the questions right.
Quick question: Which Primary level are these questions for? -
ChiefKiasu:
P5/P6More headache for us parents? Heheh. It's good that we see these questions for ourselves... that way we respect our children even more if they managed to get the questions right.
Quick question: Which Primary level are these questions for? -
Yes, these are typical P5/P6 questions. Good thing is, when you get to P6, you can use algebra if you wish to.
Q1 can be solved by algebra, model or guess and check. The last method should be least encouraged at this level.
35 adults, 45 children.
Q2 by ratio should be easy enough
8 boys and 12 girls
Q3 by model
Daniel : $200, Alex : $40
I am not sure, but I would think that Q1 and Q2 are 5 mark each and Q3, 4 marks.
So, there are more than 1 way to solve the problems. The child must be good enough to identify the shortest and most accurate way to solve it due the time constraint and pressure during exam.
:idea: -
1) There were some marbles at a shop. The ratio of the number of red marbles to the number of blue marbles was 2:3. When 50 more red marbles and 30 more blue marbles were added, the ratio of the number of red marbles to the number of blue marbles became 5:6. How many marbles were there at first?
2) Susan went shopping with a sum of money. She spent 0.5 of her money plus $5 on a handbag. She then spent 0.5 of the remaining money plus $3 on a pair of sunglasses. Finally she spent 0.5 of what was left plus $2 on an umbrella. She was then left with $1.50. How much money did she have at first?
3) There are 600 children in Team A and 30% of them are boys.
There are 400 children in Team B and 60% of them are boys.
After some children are transferred from Team B to Team A, 40% of the children in Team A and 60% of the children in Team B are boys.
How many children are transferred from Team B to Team A? -
Answers :
1. Blue marbles = 150, Red marbles = 100
2. $50
3. 300 children -
KKKS:
HiAnswers :
1. Blue marbles = 150, Red marbles = 100
2. $50
3. 300 children
For the benefits of all members, could you provide the detailed solutions? -
lizawa:
HiYes, these are typical P5/P6 questions. Good thing is, when you get to P6, you can use algebra if you wish to.
Q1 can be solved by algebra, model or guess and check. The last method should be least encouraged at this level.
35 adults, 45 children.
Q2 by ratio should be easy enough
8 boys and 12 girls
Q3 by model
Daniel : $200, Alex : $40
I am not sure, but I would think that Q1 and Q2 are 5 mark each and Q3, 4 marks.
So, there are more than 1 way to solve the problems. The child must be good enough to identify the shortest and most accurate way to solve it due the time constraint and pressure during exam.
:idea:
For the benefits of all members, could you provide the detailed solutions? -
Q2 :
# tickets sold by 1 boy : # tickets sold by 1 girl
= 5: 3
ticket sales by 1 boy : ticket sales by 1 girl ( x $5 / ticket)
= 25 : 15
If there are u number of boys,
ticket sales by boys : ticket sales by girls
= 25u : 15 (20 -u)
Difference in ticket sales = 20
25u - 15(20-u) = 20
40u = 320
u = 8
# boys = 8; # girls = 12 -
Q3 :
Not sure how to draw model here. Need to have before and after model.
Before :
Daniel : 10 units + $160
Alex : 10 units
After :
Daniel : 3 parts
Alex : 1 part
Since Daniel gives 1/10 to Alex, he has given (1 unit + $16) to Alex
In the \"After\" model,
1 part (for Alex) = 11 units + $16
3 parts (for Daniel) = 9 units + $144 ; ie. 1 part for Daniel is 3 units + $48
The difference is 2 parts : this is the key
2(11units + 16) = 6 units + $96
22 units + $32 = 6 units + $96
16 units = $64
1 unit = $4
At first,
Alex has 10 units = 10 X $4 = $40
Daniel has 10 units + $160 = $40 + $160 = $200.
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