O-Level Additional Math

[Guan Hui]

here you go I hope you can see this


http://www.postimage.org/image.php?v=aVdEdpi

http://www.postimage.org/image.php?v=PqtXhEA

http://www.postimage.org/image.php?v=gx1SzoJ

[OK Lor]

Hi Sir,


Thanks a lot, but for Q3 need some time to digest.

[Guan Hui]

q3 workings always start with 1x1x because i already dictate where the 1st and 2nd letter has gone to.

I am sure there is a better solution then mine=/

[OK Lor]

Hi Sir,


Thanks.

Please help to resolve the fraction (1-11x-4x^2+3x^3-2x^4)/(6-4x+3x^2-2x^3) into partial fraction.

Thanks.

[CoffeeCat]

OK Lor:

Hi Sir,


Thanks.

Please help to resolve the fraction (1-11x-4x^2+3x^3-2x^4)/(6-4x+3x^2-2x^3) into partial fraction.

Thanks.

Hey, to resolve to partial fraction, one will need to factorise the bottom denominator part.

6 - 4x + 3x^2 - 2x^3

This is not easy to factorise at first sight, this belongs to the case where grouping the 1st and 3rd term together, and the 2nd and 4th term together will show sth.
6 + 3x^2 = 3( x^2 + 2)
-4x - 2x^3 = -2x (x^2 + 2)

Together 6 - 4x + 3x^2 - 2x^3 = (3 -2x ) (x^2 + 2)

I will let tutor guanhui continue from here.

[OK Lor]

Hi Coffeecat,


Thanks, got it. Cheers. 卧虎藏龙 here

[Guan Hui]

haha i got it to this step yest too but still thinking on what to do to the numeratorXD

[CoffeeCat]

Ok lor I find Your questions interesting and challenging ( definitely not ok lor) so I am curious are you in some math enrichment program in sch or sth?

[OK Lor]

Hi CoffeCat,


Ya, currently in school Math Talent Program training. Find a wealth of resources here. 请多多指教. Thanks.

[Guan Hui]

Wa=D but i am not a talent but I am glad I am of help sometimes… still working on it=p