Tutor MathsGuru: Ask me for your burning Maths questions!
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abc_parent:
Hi,
Please help:
Russel delivered 7348 cartons of eggs to several supermarkets. For every carton of eggs safely delivered, he would have paid 80 cents. However, for every damaged carton, he would have to pay $1.40. Russel was paid a total of $5396.60
(a) How many cartons of eggs were damaged?
(b) How many cartons of eggs were delivered safely?
Ans: 219
Ans: 7129
Can you please explain step by step?
Hi abc_parent,
Hopes my method will not confusing you.
Lets : \t
Numer of safely delivered carton = G
Number of damaged carton = D\t\t\t\t
\t\t\t\t\t
\tG + D = 7348 ------------------> (1)\t\t\t\t
\t\t\t\t\t
\t\t\t\t\t
\t0.8G - 1.4D = 5396.6 --------> x 5\t\t\t\t
\t4G - 7D = 26983 --------------> (2)\t\t\t\t
\t\t\t\t\t
a)\tBy eliminating G to get D\t\t\t\t
\t\t\t\t\t
\t4 (7348 - D) - 7D = 26983\t\t\t\t
\t29392 - 4D - 7D = 26983\t\t\t\t
\t11D = 29392 - 26983\t\t\t\t
\t11D = 2409\t\t\t\t
\tD = 219\t\t\t\t
\t\t\t\t\t
\t219 cartons of eggs were damaged. \t\t\t\t
\t\t\t\t\t
b)\t7348 - 219 = 7129\t\t\t\t
\t\t\t\t\t
\t7129 cartons of eggs were delivered safely.
. -
abc_parent:
Assume every carton of eggs is safely deliveredHi,
Please help:
Russel delivered 7348 cartons of eggs to several supermarkets. For every carton of eggs safely delivered, he would have paid 80 cents. However, for every damaged carton, he would have to pay $1.40. Russel was paid a total of $5396.60
(a) How many cartons of eggs were damaged?
(b) How many cartons of eggs were delivered safely?
Ans: 219
Ans: 7129
Can you please explain step by step?
Russel earned = 7348 x $0.80 = $5,878.40
No. of cartons of eggs damaged = ($5,878.40 - $5,396.60)/ ($0.80 + $1.40) = 219
No. of cartons delivered safely = 7348 β 219 = 7129 -
Hi, thanks to Dharma and small.
Can you see this question too?
Mr F drove from home to work at 60km/h . After work, he needed to rush home for dinner and increased his speed on his way home by 30 km/h. As a result, he tool 5 minutes less than what he had taken on his way to work. What was the distance between his house and office?
Ans given: 15km
I think should be 90km. -
abc_parent:
Distance between his house and office is fixed, Speed is inversely proportional to the time taken.Hi, thanks to Dharma and small.
Can you see this question too?
Mr F drove from home to work at 60km/h . After work, he needed to rush home for dinner and increased his speed on his way home by 30 km/h. As a result, he tool 5 minutes less than what he had taken on his way to work. What was the distance between his house and office?
Ans given: 15km
I think should be 90km.
Speed ratio = 2 : 3
Time ratio = 3 : 2
3u β 2u = 1u = 5/60 = 1/12 hrs (Difference in time taken)
Distance = 60km/h x 3 x 1/12hrs = 15km -
Lily, Mina and Oscar each donated some money to charity. The donation made by Lily was 2/3 as much as the total amount donate by Mina and Oscar. Mina donated 1/5 as much as the total donated by Lily and Oscar. If Oscar donated $360 more than Mina, how much did Lily donate?
Ans: $540
Ali, Bala and Charles shared a tin of cookies. Ali took 5/6 of the tin of cookies and 1/3 of a cookie. Bala took 5/6 of the remaining tin of cookies and 1/3 of a cookie. Charles received only 2 cookies. How many more cookies did Ali have than Bala?
Ans: 60
Please help me by explaining step by step. Thanks in advance !
Thanks to Dharma for helping me with my last question!!! -
Hi,
Can anyone help me to solve this problem?
What is the maximum number of right angled triangles, of base 5 cm and height 6 cm, that can be cut from a rectanglular sheet of paper, 49cm long and 34 cm wide?
Ans : 48 -
Almighty:
49/5 = 9 r 4. 49/6 = 8 r 1Hi,
Can anyone help me to solve this problem?
What is the maximum number of right angled triangles, of base 5 cm and height 6 cm, that can be cut from a rectanglular sheet of paper, 49cm long and 34 cm wide?
Ans : 48
34/5 = 6 r 4. 34/6 = 5 r 4
intuitively you want to minimise wastage so you should choose to cut the triangles with theheight 6 cm along the 49 cm long side, ie 8 times 6 = 48 -
abc_parent:
Ali, Bala and Charles shared a tin of cookies. Ali took 5/6 of the tin of cookies and 1/3 of a cookie. Bala took 5/6 of the remaining tin of cookies and 1/3 of a cookie. Charles received only 2 cookies. How many more cookies did Ali have than Bala?
This question was first posted by OK Lor on 12 Apr 2010 08:43 and solved by http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=6373&postdays=0&postorder=asc&start=790 on 12 Apr 2010 09:02 and http://www.postimage.org/image.php?v=gxxlNRS on 12 Apr 2010 13:12 -
abc_parent:
Lily, Mina and Oscar each donated some money to charity. The donation made by Lily was 2/3 as much as the total amount donate by Mina and Oscar. Mina donated 1/5 as much as the total donated by Lily and Oscar. If Oscar donated $360 more than Mina, how much did Lily donate?
Donation made by Lily = 2/5 of the total donation
Donation made by Mina = 1/6 of the total donation
Donation made by Oscar = 1-2/5-1/6 = 13/30 of the total donation
13/30-1/6 = 8/30
8/30 -> $360
Lily : 2/5 = 12/30
12/30 -> 360/8x12 = 540
Amount of donation made by Lily = $540
OR
L : M+O
2 : 3
12 : 18
M : L+O
1 : 5
5 : 25
Lily = 12 units
Mina = 5 units
Oscar = 13 units
(13-5) units = 8 units
8 units = 360
12 units = 540
Amount of donation made by Lily = $540 -
Almighty:
Is the answer 48?Hi,
Can anyone help me to solve this problem?
What is the maximum number of right angled triangles, of base 5 cm and height 6 cm, that can be cut from a rectanglular sheet of paper, 49cm long and 34 cm wide?
Ans : 48
Firstly it should be 48x2 since it is right angled triangles not rectangles.
But even with rectangles, it will be 52
Explanation:
The rectangle 34 x 49 = (24+10) x (30+19)
= 24x30 + 10x49 + 24x19
This can be visualised as take out a 24x30 rectangle from the given 30x49 rectangle.
That leaves u with an L shaped piece which can be represented by 2 rectangles 10x49 and 24x19
So 24x30 will have (24/6) x (30/5) = 4x6=24 rectangles
and 10x49 will have (10/5) x (49/6) = 2x8=16 rectangles
(reminder of 1x10 wasted)
and 24 x 19 will have (24/6) x (19/5) = 4x3=12 rectangles
(reminder of 4x24 wasted)
Hence total rectangles = 24+16+12 = 52
So total triangles = 52 x 2 = 104
Hope that is not confusing.
Dunno how to upload the diagram, that would have been clearer.
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