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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • T Offline
      Tang
      last edited by

      Almighty:
      Thank you Tang.This is a new one i learnt 2day.This concept was not known 2 me until now.Thank you to all.


      Always compare apple to apple.

      1 Reply Last reply Reply Quote 0
      • R Offline
        RedRedWine
        last edited by

        Hi Maths Guru


        I have 2 questions from Catholic High Prelim exan 2. Can you help tp solve?

        1) At a swimmimg pool, the number of boys to the numbers of girls was 4:3. After 3/8 of the boys left and 12 more girls joined the group, there were 2/3 as many boys as girls. How many children were there at the swimming pool first?

        2) Tom had $144 more than Ali at first. After Tom spent 25% of his money and Ali spent 1/3 of his money. Tom had $122 more than Ali. How much did Tom have at first?

        TIA

        1 Reply Last reply Reply Quote 0
        • M Offline
          MOE Hater
          last edited by

          RedRedWine:
          Hi Maths Guru


          I have 2 questions from Catholic High Prelim exan 2. Can you help tp solve?

          1) At a swimmimg pool, the number of boys to the numbers of girls was 4:3. After 3/8 of the boys left and 12 more girls joined the group, there were 2/3 as many boys as girls. How many children were there at the swimming pool first?

          2) Tom had $144 more than Ali at first. After Tom spent 25% of his money and Ali spent 1/3 of his money. Tom had $122 more than Ali. How much did Tom have at first?

          TIA
          1) At First - Boys : Girls = 4 : 3 = 16 : 12
          After Boys Left - Boys : Girls = 5/8 x 16 : 12 = 10 : 12
          After Girls Joined - Boys : Girls = 10 : 3/2 x 10 = 10 : 15
          (15-12)u = 3u = 12
          1u = 12/3 = 4
          (16+12)u = 28u = 4 x 28 = 112

          2) Let x be the money Tom had at first

          (1-25/100)x = (1-1/3)(x-144) + 122
          3/4 x = 2/3 x - 96 + 122
          9/12 x = 8/12 x + 26
          1/12 x = 26
          x = 312

          Hope this is self-explanatory enough. :lol:

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          • A Offline
            abc_parent
            last edited by

            Hi MOE HAter, VanillaCake & Maths Monster

            Thanks for your help.

            Vanilla Cake, I have indicated the exam paper name in my Subject already, thanks for your pointer, though!

            πŸ™‚

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            • V Offline
              Vanilla Cake
              last edited by

              Tang:
              Almighty:

              Thank you Tang.This is a new one i learnt 2day.This concept was not known 2 me until now.Thank you to all.


              Always compare apple to apple.

              Hi Tang,
              Thks for helping to explain to Almighty.
              πŸ˜‰

              1 Reply Last reply Reply Quote 0
              • V Offline
                Vanilla Cake
                last edited by

                abc_parent:
                Hi MOE HAter, VanillaCake & Maths Monster

                Thanks for your help.

                Vanilla Cake, I have indicated the exam paper name in my Subject already, thanks for your pointer, though!

                πŸ™‚
                Hi abc_parent,
                Refer to your http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=6373&postdays=0&postorder=asc&start=1380 dated 03 Jun 2010 14:58, you wrote: Post subject: RGPS SA1 2010.In actual fact, it should be RGPS P6 SA1 2009.

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                • D Offline
                  Dharma
                  last edited by

                  RedRedWine:
                  Hi Maths Guru


                  I have 2 questions from Catholic High Prelim exan 2. Can you help tp solve?

                  1) At a swimmimg pool, the number of boys to the numbers of girls was 4:3. After 3/8 of the boys left and 12 more girls joined the group, there were 2/3 as many boys as girls. How many children were there at the swimming pool first?

                  TIA
                  Boys : Girls = 4 : 3 = 16 : 12
                  Boys : 16u - 6u = 10u
                  Girls : 12u +12

                  12u + 12 = 15u
                  3u = 12
                  1u = 4
                  No.of children at first = 28u = 28 x 4 = 112

                  1 Reply Last reply Reply Quote 0
                  • M Offline
                    Muffins
                    last edited by

                    RedRedWine:
                    Hi Maths Guru


                    I have 2 questions from Catholic High Prelim exan 2. Can you help tp solve?

                    1) At a swimmimg pool, the number of boys to the numbers of girls was 4:3. After 3/8 of the boys left and 12 more girls joined the group, there were 2/3 as many boys as girls. How many children were there at the swimming pool first?

                    2) Tom had $144 more than Ali at first. After Tom spent 25% of his money and Ali spent 1/3 of his money. Tom had $122 more than Ali. How much did Tom have at first?

                    TIA
                    Hi, we can go about the question like this:

                    Firstly, change the ratio of boys to girls to a number that is a multiple of 8, in this case 8 itself. It should look like this:

                    B : G
                    8 : 6

                    When 3/8 of the boys left, 5/8 of them left, so we put it as 5 units (u) in this case. The full ratio should look like this:

                    B : G
                    8 : 6
                    (-3u) (+ 12 girls)
                    5 : 7.5

                    (7.5 units because 5 divided by 2/3 is 7.5)

                    7.5u - 6u = 1.5u

                    1.5 u => 12
                    1u => 8
                    8 X (8+6) = 112

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                    • M Offline
                      MOE Hater
                      last edited by

                      Vanilla Cake:
                      abc_parent:

                      Hi MOE HAter, VanillaCake & Maths Monster

                      Thanks for your help.

                      Vanilla Cake, I have indicated the exam paper name in my Subject already, thanks for your pointer, though!

                      πŸ™‚

                      Hi abc_parent,
                      Refer to your http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=6373&postdays=0&postorder=asc&start=1380 dated 03 Jun 2010 14:58, you wrote: Post subject: RGPS SA1 2010.In actual fact, it should be RGPS P6 SA1 2009.

                      That confused me as well. I study in Henry Park but my teacher got her hands on the RGPS SA1 2010 paper. I completely did not understand when you said questions 13b, 14 and 15 were about circles when none were. As a matter of fact, there was no question 13b πŸ˜„

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                      • V Offline
                        Vanilla Cake
                        last edited by

                        MOE Hater:
                        That confused me as well. I study in Henry Park but my teacher got her hands on the RGPS SA1 2010 paper. I completely did not understand when you said questions 13b, 14 and 15 were about circles when none were. As a matter of fact, there was no question 13b πŸ˜„

                        Hi MOE Hater,
                        What I mean is that the marble question (answer=350) was from RGPS P6 SA1 2009 Paper 2 Q18. Do you have copies of the RGPS SA1 2010 paper? Perhaps you may wish to post Q13b, 14 and 15 on behalf of abc_parent and provide solutions for them since you mentioned that your teacher got her hands on these papers.Hope this will clear the confusion.
                        πŸ˜„

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