Tutor MathsGuru: Ask me for your burning Maths questions!

[firebird]

Dear ruyu


The question posted by me was given from my child’s class.

Kindly help

Thank you.
Firebird

[Almighty]

Hi Dharma / MAthguru,


http://www.postimage.org/image.php?v=gxiHqdA

1) Is my answer for Qt:12 right? I need a clarification on one thing in this problem.
The shaded length of the first square is 6 cm, how can the whole length of the second square also be 6 cm? (Marked in pencil)
2)Circle question.Unable to get a hint 2 do this.Any help?

[Almighty]

firebird:

Dear Maths guru


Good morning.

Please help me on the following question:

Keane bought some marbles and gave half of them to Leon. Leon bought some stamps and gave half of them to Keane.

Keane used 5 stamps and Leon gave away 11 marbles. The ratio of the number of stamps to the number of marbles Keane had left then became 1:7 and ratio of the number of stamps to the number of marbles Leon had left became 1:5.

How many stamps did Leon buy?

Thank you.
Firebird

Hi Fire Bird,

Let m represent number of marbles
Let S represent number of Stamps

Kate : Leon
At First:
Marble - 1m : Marble : 0m
Stamps – 0 S : Stamps: 1s

After giving:
Kate : Leon
M --- ½ m : ½ m - 11
S - -- 1/2 s – 5 : ½ S
The ratio of the number of stamps to the number of marbles Keane had left then became 1:7.So,

S / m = 1: 7
1/2s -5 = 1
½ m 7
7/2 S – 35 = ½ m ------------- (1)

ratio of the number of stamps to the number of marbles Leon had left became 1:5

So, s/m = 1 : 5

½ S = 1
½ m – 11 5

5/2 S = 1/2m -11 ------------- (2)
Substituting ½ m from equation (1)

5/2 S = 7/2S-35 – 11
S = 46
Stamps bought by Leon is 46.

[Dharma]

Almighty:

Hi Dharma / MAthguru,


http://www.postimage.org/image.php?v=gxiHqdA

1) Is my answer for Qt:12 right? I need a clarification on one thing in this problem.
The shaded length of the first square is 6 cm, how can the whole length of the second square also be 6 cm? (Marked in pencil)
2)Circle question.Unable to get a hint 2 do this.Any help?

Hi Almighty,

I'm not able to read the attachment . Can u enlarge and repost? Thanks

[Almighty]

Dharma:

Almighty:

Hi Dharma / MAthguru,


http://www.postimage.org/image.php?v=gxiHqdA

1) Is my answer for Qt:12 right? I need a clarification on one thing in this problem.
The shaded length of the first square is 6 cm, how can the whole length of the second square also be 6 cm? (Marked in pencil)
2)Circle question.Unable to get a hint 2 do this.Any help?

Hi Almighty,

I'm not able to read the attachment . Can u enlarge and repost? Thanks

Sorry 2 hv wasted yr time dharma..I'm not still good in these attachments...let me try 2 get it in bigger font..

[Almighty]

Dharma:

Almighty:

Hi Dharma / MAthguru,


http://www.postimage.org/image.php?v=gxiHqdA

1) Is my answer for Qt:12 right? I need a clarification on one thing in this problem.
The shaded length of the first square is 6 cm, how can the whole length of the second square also be 6 cm? (Marked in pencil)
2)Circle question.Unable to get a hint 2 do this.Any help?

http://www.postimage.org/image.php?v=aVl3uA0

[Almighty]

Please scroll down to the bottom of the page for the question.

Is my answer for Qt:12 right? I need a clarification on one thing in this problem.
The shaded length of the first square is 6 cm, how can the whole length of the second square also be 6 cm? (Marked in pencil)


http://www.postimage.org/image.php?v=aVl47ui

[Almighty]

Hi Dharma,


Question 11 also please.... AM i right for a)?? HOw 2 do (b) section.Stuck while finding the Diameter...



http://www.postimage.org/image.php?v=aVl5jjA

[Dharma]

Almighty:

Hi Dharma,


Question 11 also please.... AM i right for a)?? HOw 2 do (b) section.Stuck while finding the Diameter...



http://www.postimage.org/image.php?v=aVl5jjA

Part (a) is correct

Part (b)

Circumference of semi circle = 22cm ... Correct
2 sides of the square : 14cm x 2 = 28cm

Lastly, we need to find out the length of sides of the right angle triangle within the square.Let's call the side of the right angle triangle, \"a\"

We have 4 such right angle triangles in the square of sides 14cm. The right angle triangle has 2 sides of length a and the longer length is 14cm.

If we take 2 of the triangles and rearrange them to form a smaller square of side \"a\". Do the same for the other 2 triangles. We have 2 smaller squares of sides \"a\" and the total area of these 2 squares is the same as
the area if the larger square (196cm2)

2 x a x a =198
a x a = 99
a = 9.95cm (calculator)

Perimeter
= 22cm + 28cm + 9.95cm
= 59.95cm

[firebird]

Dear Almighty


Thank you very much for your answer.

With best regards
firebird