Tutor MathsGuru: Ask me for your burning Maths questions!

[clblinym]

Dear parents,


My son has two questions to ask. We tried to solve them, but failed.
Hope parents here can help us get solutions. Thanks in advance.

http://www.postimage.org/image.php?v=gxBAuPA

http://www.postimage.org/image.php?v=PqN6UjA

Amy

[Dharma]

clblinym:

Dear parents,


My son has two questions to ask. We tried to solve them, but failed.
Hope parents here can help us get solutions. Thanks in advance.

http://www.postimage.org/image.php?v=gxBAuPA

http://www.postimage.org/image.php?v=PqN6UjA

Amy

Hi Amy,

Q1

Area of quadrlateral ABCD
= Area of triangle ABC + Area of triangle ADC
= (1/2 x 3cm x 4cm) + (1/2 x 2cm x 2cm)
= 6cm2 + 2cm2
= 8cm2


Q2

Shaded area
= (Area of triangle GBE + Area of triangle HBD) - Area of quad. ABCD
= (1/2 x 10cm x 10cm) - 7cm2
= 50cm2 - 7cm2
= 43cm2

[mathsguru]

super star:

pls help me in solving this problem

Mr.Ong had 5kg rice.after he sold 5/12 of it ,he repacked the remaining rice into smaller packets of 2/3 kg each.how much rice had he left?

Hi Super Star,

Here's my solution for your reference!


MathsGuru

http://www.postimage.org/image.php?v=gxB_e8r

[mathsguru]

clblinym:

Dear parents,


My son has two questions to ask. We tried to solve them, but failed.
Hope parents here can help us get solutions. Thanks in advance.

http://www.postimage.org/image.php?v=gxBAuPA

http://www.postimage.org/image.php?v=PqN6UjA

Amy

Hi Amy,

Here are my solutions.


MathsGuru


http://www.postimage.org/image.php?v=PqNlX9S

http://www.postimage.org/image.php?v=PqNlZF0

[tianzhu]

Hi moderator


Please delete post.

Thanks

[clblinym]

Dear Dharma & Mathsguru,


Thank you so much for the clear explanation.
It’s great to have people like u guys to help selflessly.

Regards,
Amy

[clblinym]

Please help me solve the following Question.


There is no answer because it was one of the 30 questions in NUSHS mathematical Olympiad this year. I guess it is $37, but no confident at all.

Thanks in advance.




Amy
http://www.postimage.org/image.php?v=PqNDwEi

[Dharma]

clblinym:

Please help me solve the following Question.


There is no answer because it was one of the 30 questions in NUSHS mathematical Olympiad this year. I guess it is $37, but no confident at all.

Thanks in advance.




Amy
http://www.postimage.org/image.php?v=PqNDwEi

$37 is the lowest amount of money Mr Tan
will needs to spend.

By spending
1) 1 set of (11 chocs + 9 candies) => $15
2) 2 sets of (7 chocs + 9 candies) => $11x 2 = $22

Total chocs = 11 + 14 = 25
Total candies = 9 + 18 = 27
Each student will get 1 piece of chocolate and 1 piece of candy.( 2 pieces of candy left for Mr Tan to enjoy)

Minimum Amt spent = $15 + $22 = $37

[hapie_always]

Hi Mathsguru,


I have a math problem. Hope you can help me with it.

3 boys shared a box of oranges. Ted took 1/3 and 6 of the oranges. Bob took 1/2 of the remainder and 9 of the oranges. Ken took the last remaining 5 oranges. How many oranges were in the box at first?

Thanks in advance!

[Dharma]

hapie_always:

Hi Mathsguru,


I have a math problem. Hope you can help me with it.

3 boys shared a box of oranges. Ted took 1/3 and 6 of the oranges. Bob took 1/2 of the remainder and 9 of the oranges. Ken took the last remaining 5 oranges. How many oranges were in the box at first?

Thanks in advance!

http://www.postimage.org/image.php?v=TshCZXA