Tutor MathsGuru: Ask me for your burning Maths questions!

[Dharma]

Almighty:

Dharma:

[quote=\"Almighty\"]
Hi Dharma,
Can you please explain how did u do the thing marked in red?? :stupid:

Hi Almighty,

When Kumar met Clara for the 1st time at P, he had jogged 80m from M. When they met at P, in total they both would covered a total distance of half the circumference of the track (M to N).

Now when Kumar and Clara met for the 2nd time at Q, in total they would have covered the circumference of the track ( P to Q).

M to P => 80m (Kumar) when Kumar & Clara covered ½ the circumference
P to Q => 80m x 2 = 160m (Kumar) when Kumar & Clara covered the whole circumference.

Thankyou very much Dharma..I'm able to understand now ...Looks simple now..i dont know how come it dint strike me yesterday..MAy be i was a bit tensed in my preparation for my Prelim Oral...[/quote]No worries, Almighty.

[Almighty]

Dharma:

Almighty:

[quote=\"Dharma\"]
Hi Almighty,

When Kumar met Clara for the 1st time at P, he had jogged 80m from M. When they met at P, in total they both would covered a total distance of half the circumference of the track (M to N).

Now when Kumar and Clara met for the 2nd time at Q, in total they would have covered the circumference of the track ( P to Q).

M to P => 80m (Kumar) when Kumar & Clara covered ½ the circumference
P to Q => 80m x 2 = 160m (Kumar) when Kumar & Clara covered the whole circumference.

Thankyou very much Dharma..I'm able to understand now ...Looks simple now..i dont know how come it dint strike me yesterday..MAy be i was a bit tensed in my preparation for my Prelim Oral...

No worries, Almighty.[/quote]Sorry Dharma,
Still confused...in problem it is not stated that Point P is the mid point of the circle. Then how can we assume?Still tht 80 X 2 is confusing me....Please explain

[Dharma]

Almighty:

Dharma:

[quote=\"Almighty\"]
Thankyou very much Dharma..I'm able to understand now ...Looks simple now..i dont know how come it dint strike me yesterday..MAy be i was a bit tensed in my preparation for my Prelim Oral...

No worries, Almighty.

Sorry Dharma,
Still confused...in problem it is not stated that Point P is the mid point of the circle. Then how can we assume?Still tht 80 X 2 is confusing me....Please explain[/quote]See if can understand this ... if Kumar jogged 80m when he & Clara jogged 1/2 the circumference of track; then he must have jogged 160m when he and Clara jogged the whole circumference of the track.
Underlying assumption is the speed of Kumar and Clara do not change.
http://www.postimage.org/image.php?v=PqPN0f9

[clblinym]

Dharma:

clblinym:

Please help me solve the following Question.


There is no answer because it was one of the 30 questions in NUSHS mathematical Olympiad this year. I guess it is $37, but no confident at all.

Thanks in advance.




Amy
http://www.postimage.org/image.php?v=PqNDwEi

$37 is the lowest amount of money Mr Tan
will needs to spend.

By spending
1) 1 set of (11 chocs + 9 candies) => $15
2) 2 sets of (7 chocs + 9 candies) => $11x 2 = $22

Total chocs = 11 + 14 = 25
Total candies = 9 + 18 = 27
Each student will get 1 piece of chocolate and 1 piece of candy.( 2 pieces of candy left for Mr Tan to enjoy)

Minimum Amt spent = $15 + $22 = $37

~~~~~~~~~~~~~~~~~~
Dear Dharma

Thank you so much for your great help. I really appreciate it.

[Dharma]

clblinym:

Dharma:

[quote=\"clblinym\"]Please help me solve the following Question.


There is no answer because it was one of the 30 questions in NUSHS mathematical Olympiad this year. I guess it is $37, but no confident at all.

Thanks in advance.




Amy
http://www.postimage.org/image.php?v=PqNDwEi

$37 is the lowest amount of money Mr Tan
will needs to spend.

By spending
1) 1 set of (11 chocs + 9 candies) => $15
2) 2 sets of (7 chocs + 9 candies) => $11x 2 = $22

Total chocs = 11 + 14 = 25
Total candies = 9 + 18 = 27
Each student will get 1 piece of chocolate and 1 piece of candy.( 2 pieces of candy left for Mr Tan to enjoy)

Minimum Amt spent = $15 + $22 = $37

~~~~~~~~~~~~~~~~~~
Dear Dharma

Thank you so much for your great help. I really appreciate it.[/quote]No worries.

[Almighty]

Dharma:

Sorry Dharma,
Still confused...in problem it is not stated that Point P is the mid point of the circle. Then how can we assume?Still tht 80 X 2 is confusing me....Please explain

See if can understand this ... if Kumar jogged 80m when he & Clara jogged 1/2 the circumference of track; then he must have jogged 160m when he and Clara jogged the whole circumference of the track.
Underlying assumption is the speed of Kumar and Clara do not change.
http://www.postimage.org/image.php?v=PqPN0f9[/quote]

Ok ok.I got it..Its based on the Principle[excuse me for the typo error]
\"When K covers 80m =1/2 of the circumference is covered
so, ? = full circumference
ie.,(80 X 2) = 160m from the point of K's journey...
Thankyou Dharma, Onceagain for a very very patient reply...I drew the same diagram and tried to understand intially..but failed to get it..My apologies for bothering you toooooo much....

[Ngserene617]

Hi can someone help me to solve this question:

- Find the value of 60 divide 80 divide 5 x 4
thanks !

Almighty:

[quote=\"Dharma

Sorry Dharma,
Still confused...in problem it is not stated that Point P is the mid point of the circle. Then how can we assume?Still tht 80 X 2 is confusing me....Please explain

See if can understand this ... if Kumar jogged 80m when he & Clara jogged 1/2 the circumference of track; then he must have jogged 160m when he and Clara jogged the whole circumference of the track.
Underlying assumption is the speed of Kumar and Clara do not change.
http://www.postimage.org/image.php?v=PqPN0f9[/quote]

Ok ok.I got it..Its based on the Principal
\"When K covers 80m =1/2 of the circumference is covered
so, ? = full circumference
ie.,(80 X 2) = 160m from the point of K's journey...
Thankyou Dharma, Onceagain for a very very patient reply...I drew the same diagram and tried to understand intially..but failed to get it..My apologies for bothering you toooooo much....[/quote]

[Ngserene617]

1. Jane paid $580 for an oven after 20% discount in a sale. What was the original price of the oven?

[singmathstutor]

Ngserene617:

1. Jane paid $580 for an oven after 20% discount in a sale. What was the original price of the oven?

80% --> $580
100% --> 100x580/80
= $725

[Muffins]

yes, you are right Ngserene617, it is based on the principal of the school, not the principle!!! :lol: :rotflmao: