Tutor MathsGuru: Ask me for your burning Maths questions!

[Muffins]

yes, you are right Ngserene617, it is based on the principal of the school, not the principle!!! :lol: :rotflmao:

[DragonAxe]

Ngserene617:

1. Jane paid $580 for an oven after 20% discount in a sale. What was the original price of the oven?

5/4x$580 = 145x5 = 1450/2 = 1400/2 + 50/2 = 700+25 = 725

ANSWER : $725.

[Dharma]

Almighty:

[quote=\"Dharma


Sorry Dharma,
Still confused...in problem it is not stated that Point P is the mid point of the circle. Then how can we assume?Still tht 80 X 2 is confusing me....Please explain

See if can understand this ... if Kumar jogged 80m when he & Clara jogged 1/2 the circumference of track; then he must have jogged 160m when he and Clara jogged the whole circumference of the track.
Underlying assumption is the speed of Kumar and Clara do not change.
http://www.postimage.org/image.php?v=PqPN0f9[/quote]

Ok ok.I got it..Its based on the Principal
\"When K covers 80m =1/2 of the circumference is covered
so, ? = full circumference
ie.,(80 X 2) = 160m from the point of K's journey...
Thankyou Dharma, Onceagain for a very very patient reply...I drew the same diagram and tried to understand intially..but failed to get it..My apologies for bothering you toooooo much....[/quote]


For meeting problems; time taken us fixed provided Kumar and Clara leaves at the same time.

You can check as shown below ....

When they meet for the 1st time
Kumar : 80m (from M to P)
Clara : 100m (from N to P)
Total distance => 160m (1/2 of circumference)

When they meet for 2nd time
Kumar : 160m ( from P to Q - clockwise direction)
Clara : 200m (from P to Q - anti clockwise direction)
Total distance => 360m (Circumference)

[Almighty]

Dharma:

Almighty:

[quote=\"Dharma


For meeting problems; time taken us fixed provided Kumar and Clara leaves at the same time.

You can check as shown below ....

When they meet for the 1st time
Kumar : 80m (from M to P)
Clara : 100m (from N to P)
Total distance => 160m (1/2 of circumference)

When they meet for 2nd time
Kumar : 160m ( from P to Q - clockwise direction)
Clara : 200m (from P to Q - anti clockwise direction)
Total distance => 360m (Circumference)

Hi Sir,(Feel like calling you like this..You truly deserve much more respect ...)
Thank you Very much Dharma Sir...

[Almighty]

Muffins:

yes, you are right Ngserene617, it is based on the principal of the school, not the principle!!! :lol: :rotflmao:

Dear Muffins,

It was not Ngserene...But me who made the mistake.. My apologies for doing it..Edited rightly ...thanks for the info

[Herbie]

Hi I have one question


Paul and Ray worked together to paint a house. During the job Paul rested for 4 days and Ray took 2 days off. However, they were not absent on the same days. If they had done the same job alone. Paul would have taken 18 days and Ray 12 days.

How long did the two painters take to complete painting the house?

Kindly assist.

My working.
Work done by Paul in one day = 1/18
Work done by Ray in one day = 1/12

Work done for one house in one day = 1/18 + 1/12 = 5/36

Portion of work left = 1-5/36 = 31/36

Then 31/5 = 6.2 = 6.5 days

No. of days required to complete the work = 6.5 + 2 + 4 = 12.5 days

Is my answer correct???

Tx

[Dharma]

Herbie:

Hi I have one question


Paul and Ray worked together to paint a house. During the job Paul rested for 4 days and Ray took 2 days off. However, they were not absent on the same days. If they had done the same job alone. Paul would have taken 18 days and Ray 12 days.

How long did the two painters take to complete painting the house?

Kindly assist.

My working.
Work done by Paul in one day = 1/18
Work done by Ray in one day = 1/12

Work done for one house in one day = 1/18 + 1/12 = 5/36

Portion of work left = 1-5/36 = 31/36

Then 31/5 = 6.2 = 6.5 days

No. of days required to complete the work = 6.5 + 2 + 4 = 12.5 days

Is my answer correct???

Tx

Paul – 1 day => 1/18 of job
Ray – 1 day => 1/12 of job
Paul & Ray – 1 day => 1/18 + 1/12 = 30/(18x 12) = 5/36 of job

Let say Paul and Ray take N days to complete job

Paul => N days to complete => (N – 4)/18 of job
Ray = > N days to complete => (N – 2)/ 12 of job

N/18 – 4/18 + N/12 – 2/12 = 1
5N/36 – 7/18 = 1
(5N – 14)/36 = 36/36
5N – 14 = 36
5N = 50
N = 10 days

[DragonAxe]

Herbie:

Hi I have one question


Paul and Ray worked together to paint a house. During the job Paul rested for 4 days and Ray took 2 days off. However, they were not absent on the same days. If they had done the same job alone. Paul would have taken 18 days and Ray 12 days.

How long did the two painters take to complete painting the house?

Paul - 1/18 / day
Ray - 1/12 / day


During Paul's off day :
Ray did 4/12 of the job


During Ray's off day :
2/18

1/18+1/12 = 2/36 + 3/36 = 5/36

1 - 4/12 - 2/18
= 8/12 - 2/18
= 24/36 - 4/36
= 20/36

20/36 divide by 5/36 = 4

4 days + 4 days + 2 days = 10 days.

[DragonAxe]

hapie_always:

Hi Mathsguru,


I have a math problem. Hope you can help me with it.

3 boys shared a box of oranges. Ted took 1/3 and 6 of the oranges. Bob took 1/2 of the remainder and 9 of the oranges. Ken took the last remaining 5 oranges. How many oranges were in the box at first?

Thanks in advance!

5+9=14
14*2=28
28+6=34
3/2 * 34 = 51

CHECK
Ted - 17+6= 23 | 28 left
Bob - 14+9= 23 | 5 left
Ken - 5 oranges.

[Ngserene617]

mathsguru:

Original Title: Let MathsGuru Answer Your Burning Maths Questions!


:welcome:

Dear Parents,

Are you frustrated/stuck when helping your child solve his/her Maths questions? Are you inclined to use Algebra most of the time? Do you have difficulty trying to use diagrams or other heuristic methods (that Primary School students learn) to solve?

:idea: Post your questions here and see how MathsGuru solve them to the best of her ability. Detailed solutions will be posted back in this thread.


Hi can someone help me to solve this question:
- Find the value of 60 divide 80 divide 5 x 4
thanks !


So start asking and watch this space!!

Cheers :celebrate: ,
MathsGuru

P/S (Disclaimer, in case you're wondering...):
Although MathsGuru is a full-time Maths tutor, this thread is meant to be an absolutely free resource for parents (or even children) with no strings attached. Just someone who's passionate about Maths and wanna spread the fun in learning Maths with others.