Tutor MathsGuru: Ask me for your burning Maths questions!
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Carrot:
ME MY FRIENDHi Maths Guru please help :?: DS cannot solve and I also cant do
My friend and I went to a bookstore to buy books. We bought a total of 18 books over the last 3 days. The number of books I bought on the third day is equal to the sum of the total number of books my friend bought on the 2nd day and third days. The number of books my friend bought on the first day is 2 more than the sum of what I bought on the first and second days. How many books did each one of us buy?
Day DAY
1:2:3 1:2:3
(1u-1):1 (1u+1):1
Meaning
Me bought 1u-1+1u= 2u-1
He bought 1u+1+1u=2u+1
9-1=8
9+1=10
Me - 8
He - 10 -
Carrot:
Hi Thanks for your quick responseTang:
[quote=\"Carrot\"]Hi Maths Guru please help :?: DS cannot solve and I also cant do
My friend and I went to a bookstore to buy books. We bought a total of 18 books over the last 3 days. The number of books I bought on the third day is equal to the sum of the total number of books my friend bought on the 2nd day and third days. The number of books my friend bought on the first day is 2 more than the sum of what I bought on the first and second days. How many books did each one of us buy?
Hello,
I bought 2 books less than my friend. We bought a total of 18 books.
So I - Small unit; My friend - Big unit.
hum...can you explain a bit on your working ? :? solution ? where to find the hint from question... is it my DS langunage level weak or question tricky ...he said he dono how to solve ... need to knw which area weak :idea:[/quote]
Hello,
We bought a total of 18 books over the last 3 days.
The number of books I bought on the third day is equal to the sum of the total number of books my friend bought on the 2nd day and third days.
The number of books my friend bought on the first day is 2 more than the sum of what I bought on the first and second days.
18 - 2 = 16
16 / 2 = 8 books --- I
18 - 8 = 10 books --- My friend -
Dear Maths guru
Good morning.
Please help me on the Pei Hwa SA2 2009 Q17 paper 2:
Michael asked his classmate what time it was. Jackson the Math whiz replied with a cheeky grin, "Itβs 2000 hours, 1990 minutes and 1980 seconds before midnight." Can you help Michael find out what time it is?
Thank you
Firebird -
firebird:
Let me try....Dear Maths guru
Good morning.
Please help me on the Pei Hwa SA2 2009 Q17 paper 2:
Michael asked his classmate what time it was. Jackson the Math whiz replied with a cheeky grin, \"It's 2000 hours, 1990 minutes and 1980 seconds before midnight.\" Can you help Michael find out what time it is?
Thank you
Firebird
2000hrs = 83 1/3 day
leave out 83 days because we are interested only in hrs and min
1/3 day = 8 hrs
1990min = 33 1/6 hr = 1 day + 9 1/6 hr
9 1/6 hr = 9 hrs 10 min
1980 s = 33 min
Total time before midnight = 8 hrs + 9 hrs 10 min + 33 min
= 17 hrs 43 min
Use timeline
17 hrs 43 min before 12 midnight is 6.17 am -
Dear Singmathstutor
You are correct.
Many thanks for the answer sir/madam.
With best regards
firebird -
firebird:
Always a pleasure, firebird... :dancing:Dear Singmathstutor
You are correct.
Many thanks for the answer sir/madam.
With best regards
firebird -
Tang:
Hi Thanks for your quick responseCarrot:
[quote=\"Tang\"]
Hello,
I bought 2 books less than my friend. We bought a total of 18 books.
So I - Small unit; My friend - Big unit.
hum...can you explain a bit on your working ? :? solution ? where to find the hint from question... is it my DS langunage level weak or question tricky ...he said he dono how to solve ... need to knw which area weak :idea:
Hello,
We bought a total of 18 books over the last 3 days.
The number of books I bought on the third day is equal to the sum of the total number of books my friend bought on the 2nd day and third days.
The number of books my friend bought on the first day is 2 more than the sum of what I bought on the first and second days.
18 - 2 = 16
16 / 2 = 8 books --- I
18 - 8 = 10 books --- My friend[/quote] :thankyou: very much!;) -
Hello, How do you do this question?
Denise,Ginny and Florence each made some bookmarks for sale. At first, Denise had 1365 bookmarks more than Ginny. Then Denise sold 420 bookmarks and made another 175 bookmarks. Florence sold 140 bookmarks and made another 350 bookmarks. Ginny made some more bookmarks and her number of bookmarks doubled. In the end, all three girls had the same number of bookmarks. Find the total number of bookmarks the three girls had at first. -
Hi Maths Guru
Can you look at this Clock Question, please?
Please help on the answer to the question below.
John and Tom race around a circular track, divided like the face of a clock, into 12 sections. If John gives Tom four sections start and runs half as fast again as Tom, at what point on the track will he overtake Tom? (Assume on the clock face that John and Tom start at 12 and 4, respectively).
The answer is 12, however, if John gives Tom four sections starts and is half as fast, surely does not half as fast mean that John is running at half the speed of Tom. And if he is 4 sections behind, surely Tom will win. Unless half as fast means that John runs at 1.5 times of Tom. Tearing my hair out here. Please help!!! -
Skydust:
Please correct me if I'm wrong Dharma and/or Tianzhu, or anyone who basically spots a mistake in this working.Hello, How do you do this question?
Denise, Ginny and Florence each made some bookmarks for sale. At first, Denise had 1365 bookmarks more than Ginny. Then Denise sold 420 bookmarks and made another 175 bookmarks. Florence sold 140 bookmarks and made another 350 bookmarks. Ginny made some more bookmarks and her number of bookmarks doubled. In the end, all three girls had the same number of bookmarks. Find the total number of bookmarks the three girls had at first.
1365 - 420 + 175 = 1120 => Number of bookmarks extra Denise has in regard to Ginny
If D had 1390 more bookmarks than G and G's doubled unit equals it, then it is safe to assume that 1 unit is 1120.
So for D, she had 2 units + 245, so 1120 X 2 + 245 = 2485
G - 1120 (1 unit)
F - 1120 X 2 = 2240
2240 - 210 = 2030
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