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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • L Offline
      liketoeat
      last edited by

      tianzhu:
      liketoeat:


      2) Car A left Town X for Town Y at the same time when Car B left Town Y for Town X. The average speed of Car A was 56 km/h and the average speed for Car B was 72 km/h. The two cars passed each other at a point 24 km from the midway of the two towns. What is the distance between Town X and Town Y? (Ans: 384km)

      Hi

      One way to solve this question is to use the concept that distance varies in direct proportion to speed. The faster the speed, the more distance is covered.

      Car A ----- Speed ---- 56(7) ------- Distance -------7u
      Car B ------ Speed ----- 72(9) -------Distance -------9u

      The midpoint is at 8u (16/2)
      1u ------24 km
      16u ------384 km

      Best wishes

      Thank you, Tianzhu.

      1 Reply Last reply Reply Quote 0
      • L Offline
        liketoeat
        last edited by

        Brenda10:
        liketoeat:

        1) Jane has some money. After spending $100 on 3 bags and 7 belts, she is short of $4 if she wants to buy another bag. However, if she buys 1 more belt, she will have $6 left.

        a) How much does one bag cost? (Ans: $13)
        b) How much does Jane have? (Ans: $109)

        Hi, I have come across the similar question. However now I try to solve this question by following the previous sample I couldn’t get the answer same as you provided. I can only get (a) $17, (b) $113

        That’s mean that I kept the wrong sample!! :!: Sorry not able to help and I also need to seek help from the rest.

        I've got this solution but didn't quite understand, could someone please explain to me... thank you.

        $4 + $6 = $10
        $100 + $10 x 7 = $170

        $170 / (3 + 7) = $17 (a)

        $100 + $17 - $4 = $113 (b)

        1 Reply Last reply Reply Quote 0
        • T Offline
          tianzhu
          last edited by

          Cheerfuldad:

          400 people took part in a camp. 73 of them were adults and the rest were children. 2/5 of the boys and 1/4 of the girls were lower primary pupils while the rest of them were upper primary pupils. There were 9 more upper primary girls than upper primary boys.
          a) How many upper primary pupils were there?
          b) What percentage of the people who took part in the camp were girls?
          Hi

          I’ll describe how to do it by MD.

          400 people – 73 adults ----- 327 children

          The units representing boys and girls are different.

          Boys ----- 3parts (UP)----- 2 parts (LP)
          Girls ----- 3 units (UP)----- 1 units (LP)

          3 units is greater than 3 parts by 9
          Therefore 1 unit is greater than 1 part by 3

          5parts+4units ------ 327
          5parts+ (4parts +12) -----327

          9parts ----- 315
          1 part -----35
          Hence, 1 unit ---- 38

          a)Number of upper primary boys ------(35*3) -----105
          Number of upper primary girls -----(105+9) ----- 114
          Number of upper primary pupils -----219

          b)Number of girls ------(38*4) -----152
          Therefore the percentage of girls to number of people ------152/400*100 ----- 38%

          Hope this helps.

          Best wishes

          1 Reply Last reply Reply Quote 0
          • T Offline
            tianzhu
            last edited by

            Dreamybee:

            Tks alot Tianzhu, you have been very kind and helpful....I really appreciate any form of support now...
            Hi

            No worries.
            I am a father too and I wish every child will enjoy going to schools.

            Best wishes

            1 Reply Last reply Reply Quote 0
            • B Offline
              Brenda10
              last edited by

              liketoeat:
              Brenda10:

              [quote=\"liketoeat\"]1) Jane has some money. After spending $100 on 3 bags and 7 belts, she is short of $4 if she wants to buy another bag. However, if she buys 1 more belt, she will have $6 left.

              a) How much does one bag cost? (Ans: $13)
              b) How much does Jane have? (Ans: $109)

              Hi, I have come across the similar question. However now I try to solve this question by following the previous sample I couldn’t get the answer same as you provided. I can only get (a) $17, (b) $113

              That’s mean that I kept the wrong sample!! :!: Sorry not able to help and I also need to seek help from the rest.

              I've got this solution but didn't quite understand, could someone please explain to me... thank you.

              $4 + $6 = $10
              $100 + $10 x 7 = $170

              $170 / (3 + 7) = $17 (a)

              $100 + $17 - $4 = $113 (b)[/quote]Hi Liketoboat

              Paiseh. I am not good in explination :oops: but the following is my working step:

              $4 + $6 = $10

              1 Bag [ ]$10]
              1 Belt [ ]

              7 belts = 7 [ ]
              3 bags = 3 [ ] + $30

              10 [ ] = $100 - $30 = $70
              1 [ ] = $7

              $7 + $10 = $17
              Each bag cost $17

              Original amount : $100 + $7 + $6 = $113

              Sorry unable to draw the model. This [ ] represent a rectangle model box

              1 Reply Last reply Reply Quote 0
              • O Offline
                optimistforum
                last edited by

                Can someone explain the method for calculating the maths question below, please?


                In a new game, played by two teams, there are several ways of scoring points: Points listed in brackets

                Ways of scoring\t
                “Runners”\t (1)
                “Bumps”\t (2)
                “Sprints”\t(4)

                How many different ways can a score of five points be reached?

                1 Reply Last reply Reply Quote 0
                • T Offline
                  Tang
                  last edited by

                  optimistforum:
                  Can someone explain the method for calculating the maths question below, please?


                  In a new game, played by two teams, there are several ways of scoring points: Points listed in brackets

                  Ways of scoring\t
                  “Runners”\t (1)
                  “Bumps”\t (2)
                  “Sprints”\t(4)

                  How many different ways can a score of five points be reached?

                  Hello,

                  Let me try.

                  1 x 1 + 2 x 2
                  1 x 1 + 4
                  1 x 3 + 2
                  1 x 5

                  So there are 4 different ways.

                  1 Reply Last reply Reply Quote 0
                  • T Offline
                    tianzhu
                    last edited by

                    liketoeat:

                    Thank you, Tianzhu.
                    Hi

                    You're welcome.

                    Best wishes

                    1 Reply Last reply Reply Quote 0
                    • M Offline
                      maths6a
                      last edited by

                      Cheerfuldad:
                      Hi all,


                      Please help!

                      Q. 400 people took part in a camp. 73 of them were adults and the rest were children. 2/5 of the boys and 1/4 of the girls were lower primary pupils while the rest of them were upper primary pupils. There were 9 more upper primary girls than upper primary boys.

                      a) How many upper primary pupils were there?

                      b) What percentage of the people who took part in the camp were girls?

                      3units of Boys and 3 units of girls are in upper pr, so
                      each girl unit is 3 more than each boy unit.
                      5 boy units and 4 girl units + 12 = (400 - 73)
                      9 units = 400 - 73 - 12
                      = 315
                      1 unit = 35
                      6 units + 9 = 219 upper pr pupils (a)
                      (4 units + 12)/400 x 100% = 38%

                      Hope I am correct.


                      TIA

                      1 Reply Last reply Reply Quote 0
                      • F Offline
                        firebird
                        last edited by

                        Dear maths guru


                        Please help with the following P6 maths:
                        1) Mrs Chia baked 120 beef pies and chicken pies. After she gave away 1/4 of the beef pies and 2/5 of the chicken pies, she was left with 30 beef pies. How many chicken pies had she left?

                        2) The ratio of the number of yellow marbles to the total number of green and red marbles was 7:13. 40% of the marbles were red marbles. After throwing away 65 red marbles that were chipped, 20% of the remaining marbles were red. How many marbles were there left if another 24 green marbles were found to be chipped and thrown away?

                        3) Alicia gave some beads to Betty such that Betty had 40% of the number of beads that Alica had. After that, Alica gave another 170 beads to Betty. In the end, Betty had 80% of the number of beads that Alica had. How many beads did Betty have in the end?

                        4) There were 4 times as many boys as girls at a party at first. After 20 boys went home and 16 more girls joined in, there were 6 more boys than girls remaining at the party.
                        a) How many boys were there at the party initially?
                        b) How many children attended the party?

                        Thank you
                        Firebird

                        1 Reply Last reply Reply Quote 0

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