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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • Y Offline
      Yu Xuan
      last edited by

      CJM:
      Some trees are planted along a 400 metres road with a tree on each end of the road. The distance between every 2 nearest trees are 4 metres. If the distance between every 2 nearest trees is to be changed to 5 metres, how many trees will not be removed?

      Multiple of 4 that has a '0' in the ones place are...

      20, 40, 60, 80, 100, 120, ... (20 in total)

      20+1 = 21

      Is that the answer? πŸ™

      1 Reply Last reply Reply Quote 0
      • C Offline
        CJM
        last edited by

        Yu Xuan:
        CJM:

        Some trees are planted along a 400 metres road with a tree on each end of the road. The distance between every 2 nearest trees are 4 metres. If the distance between every 2 nearest trees is to be changed to 5 metres, how many trees will not be removed?


        400 / 4 = 100
        100 + 1 = 101

        400 / 5 = 80
        80 + 1 = 81

        101 - 81 = 20

        Is that the answer? πŸ™


        the teacher has not posted the answer yet : )
        thanks for ur help !

        1 Reply Last reply Reply Quote 0
        • M Offline
          maths6a
          last edited by

          i also calculated 20. all the trees that were planted on mulitples of 5 and 10, in this case are the ones on 20m, 40m,… and 20 tress need not be removed.

          1 Reply Last reply Reply Quote 0
          • C Offline
            CJM
            last edited by

            maths6a:
            i also calculated 20. all the trees that were planted on mulitples of 5 and 10, in this case are the ones on 20m, 40m,... and 20 tress did not be removed.


            thank u : )

            1 Reply Last reply Reply Quote 0
            • Y Offline
              Yu Xuan
              last edited by

              I think I cause some confusion, my first working is wrong... I realised it after reading it again. I have edited my answer and hence my answer is 21 instead after adding the first tree.


              Sori abt that :lol:

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              • T Offline
                Tang
                last edited by

                Yu Xuan:
                CJM:

                Some trees are planted along a 400 metres road with a tree on each end of the road. The distance between every 2 nearest trees are 4 metres. If the distance between every 2 nearest trees is to be changed to 5 metres, how many trees will not be removed?


                Multiple of 4 that has a '0' in the ones place are... It is multiple of both 4 and 5, ie 20.

                20, 40, 60, 80, 100, 120, ... (20 in total)

                20+1 = 21

                Is that the answer? πŸ™


                Hi,

                4 x 5 = 20

                400 / 20 = 20

                20 + 1 = 21 trees will not be removed.

                1 Reply Last reply Reply Quote 0
                • T Offline
                  Tang
                  last edited by

                  CJM:
                  maths6a:

                  i also calculated 20. all the trees that were planted on mulitples of 5 and 10, in this case are the ones on 20m, 40m,... and 20 tress did not be removed.



                  thank u : )


                  Hi,

                  Don't forget to add the one at '0'.

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                  • C Offline
                    Cheerfuldad
                    last edited by

                    Hi all,


                    Please help!

                    Q. Beth had 40% more beads than Diana. After Beth gave 10% of her beads to Diana, She had 48 more beads than Diana.

                    a) How many beads did the two girls have altogether?

                    b) How many beads must Beth give to Diana so that both girls would have the same number of beads?

                    TIA.

                    1 Reply Last reply Reply Quote 0
                    • D Offline
                      Daddy
                      last edited by

                      Thanks Tianzhu & Dharma.


                      Tianzhu Question:
                      "Mr Ong had 5kg of rice. After he sold 5/12 of it, he repacked the remaining rice into smaller packets of 2/3kg each. How much rice had he left? "

                      Above question is difficult than I had asked. I tried.

                      Left => 1- 5/12 = 7/12

                      5 Kg x 7/12 = 35/12kg left

                      Is it the answer?

                      1 Reply Last reply Reply Quote 0
                      • M Offline
                        maths6a
                        last edited by

                        you are right. so plus first tree so it should also be 21. pai say!

                        1 Reply Last reply Reply Quote 0

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