Q&A - PSLE Math

[Dharmaratnam]

Hi Small,


Now that you are aware that AB can be found using at least 2 methods … the examiner can go 1 step further to ask for area of FED.

[kiasiparent]

All these questions are maths competition questions from about 10 years ago.

[Dharma]

kiasiparent:

All these questions are maths competition questions from about 10 years ago.

You're right ...they may very well be from previous years' maths competitions ....but I think these sort of questions are more like the ones that appear in school exams nowadays. The level of difficulty of these questions tend to increase as the years pass by.

It will be good if our kids are exposed to some these non-routine kind of questions besides the problem solving qns as they are almost certain to appear in the psle. It will equip them with the necessary skills to approach that requires higher order thinking ...

[small]

Thanks for your time.


P6 question from a school exam paper.

Question:

There were a total of 20800 sacks of rice in Warehouse X and Warehouse Y. After 3/4 of the stock in Warehouse X and 3/5 of the stock in Warehouse Y were sold, there were 1040 more sacks of in rice Warehouse Y than Earehouse X. How many sacks of rice were there in each warehouse at first? :?

[fxchow]

Hi,


Pls help to solve this speed question. TIA

A tiger and a leopard are 60km apart.
The tiger runs at a speed of 55km/h.
At the same time, the leopard runs towards the tiger at a speed of 25km/h.
How much further will the tiger have run than the leopard when the two animals meet?

[small]

fxchow:

Hi,


Pls help to solve this speed question. TIA

A tiger and a leopard are 60km apart.
The tiger runs at a speed of 55km/h.
At the same time, the leopard runs towards the tiger at a speed of 25km/h.
How much further will the tiger have run than the leopard when the two animals meet?

Hope this help.

For every 1 hour, the two animals ran -> 55 + 25 = 80 km

If total distance is 60 km, that will take 60 / 80 = ¾ hour

So the two animals will take ¾ hour ( 45mins) to meet.

(55-25) km/hr X ¾ hr -> 30 x ¾ = 22.5 km

[corneyAmber]

http://i724.photobucket.com/albums/ww246/ks2me/P6MathRiceSacks-1.jpg\">

[Dharmaratnam]

fxchow:

Hi,


Pls help to solve this speed question. TIA

A tiger and a leopard are 60km apart.
The tiger runs at a speed of 55km/h.
At the same time, the leopard runs towards the tiger at a speed of 25km/h.
How much further will the tiger have run than the leopard when the two animals meet?

For fixed time taken, the ratios of speed and distance of tiger to leopard are ..
\tTiger\tLeopard
Speed\t11 :\t5
Distance\t11 :\t5

16units =60km
2units = 7.5km
6units = 22.5km

The tiger would have run 22.5km further than the leopard when they meet.

[fxchow]

Dear Small & Dharmaratnam,


Thanks for your solution. :lol:

[small]

ks2me:

http://i724.photobucket.com/albums/ww246/ks2me/P6MathRiceSacks-1.jpg\">

Thanks again ks2me, you are great...

No wonder I not able to get the answer due to my wrong calculation; 1920 x 5 = 9100.