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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • H Offline
      Herbie
      last edited by

      hi Dharma,


      If the qn is silent abt the pi, it is possible for us to key into the calculator 22/7 and it is for calculation?

      i dun know why but 22/7 = 3.142857143 whereas the pi the calculator is 3.141592654.

      My son used 22/7 for his calculation and his school teacher marked his answer 228.38 as incorrect.

      What is yr view on this???

      Many thanks!

      1 Reply Last reply Reply Quote 0
      • D Offline
        Dharma
        last edited by

        Herbie:
        hi Dharma,


        If the qn is silent abt the pi, it is possible for us to key into the calculator 22/7 and it is for calculation?

        i dun know why but 22/7 = 3.142857143 whereas the pi the calculator is 3.141592654.

        My son used 22/7 for his calculation and his school teacher marked his answer 228.38 as incorrect.

        What is yr view on this???

        Many thanks!
        If the qn is silent; then use the pi sign in the calculator.
        You should use 22/7 only when the question says (pi = 22/7) or use 3.142 when qns says (pi = 3.142)

        To be safe, just follow the instructions. The accuracy in the answer to decimal places may be important now with the introduction of calculators for paper 2.

        Anyway, I'm just a parent. You may wish to check with your son's maths teacher on this just to be doubly sure.

        1 Reply Last reply Reply Quote 0
        • M Offline
          Muffins
          last edited by

          Dharma is completely right. For a test, I had put my answer as 60.22, because I had used 22/7, but the answer was 60.21, and I had lost the 4 marks. So, it is better to check the question before... πŸ™‚

          1 Reply Last reply Reply Quote 0
          • T Offline
            Tang
            last edited by

            Dharma:
            Yu Xuan:

            [quote=\"Dharma\"]
            Mass of all 5 boys
            = (105 + 113 + 116 + 117 + 118 + 124 + 125 + 130 + 137 + 139)/4
            = 306

            Sum of the mass of the 2 lightest boys and 2 heaviest boys
            = 105 + 139
            = 244

            The mass of the 3rd heaviest boy = 306 – 244 = 62


            cracking my head on how I should proceed after getting 306.

            I surelyyou.

            Hi Yu Xuan,

            Thanks but I am actually learning from all of you everyday and I hope that our sharing will be truly beneficial to parents and their P6 kids in this coming PSLE Maths exam.[/quote]
            Hi,

            A - largest, E - smallest

            A + B = 139

            A + C = 137

            Based on answer above C = 62, so A = 137 - 62 = 75

            and B = 139 - 75 = 64


            E + D = 105

            E + C = 113

            Similarly, E = 113 - 62 = 51 and D = 105 - 51 = 54

            A, B, C, D, E --> 75, 64, 62, 54, 51

            However the mass of 2 are:

            139, 137, 129, 126, 126, 118, 116, 115, 113 and 105

            These do not tally with those numbers given in the question.

            Any comments?

            1 Reply Last reply Reply Quote 0
            • S Offline
              super star
              last edited by

              hi maths guru

              please help me with this problem.
              Eliot can paint a room in 3 hrs.fred can paint the same room in 5 hrs.how long will they take to paint the room if they do it together?

              1 Reply Last reply Reply Quote 0
              • S Offline
                super star
                last edited by

                pls help me with this problem


                fill in the blank
                0.7:7/8=__ :___

                1 Reply Last reply Reply Quote 0
                • starlight1968sgS Offline
                  starlight1968sg
                  last edited by

                  super star:
                  pls help me with this problem


                  fill in the blank
                  0.7:7/8=__ :___
                  0.7 = 7/10 = 700/1000

                  7/8 = 875/1000

                  So the ratio is 700 : 875 = 28 : 35 = 4 : 5 :roll:

                  1 Reply Last reply Reply Quote 0
                  • starlight1968sgS Offline
                    starlight1968sg
                    last edited by

                    Tang:
                    Hi,


                    A - largest, E - smallest

                    A + B = 139

                    A + C = 137

                    Based on answer above C = 62, so A = 137 - 62 = 75

                    and B = 139 - 75 = 64


                    E + D = 105

                    E + C = 113

                    Similarly, E = 113 - 62 = 51 and D = 105 - 51 = 54

                    A, B, C, D, E --> 75, 64, 62, 54, 51

                    However the mass of 2 are:

                    139, 137, 129, 126, 126, 118, 116, 115, 113 and 105

                    These do not tally with those numbers given in the question.

                    Any comments?
                    I don't understand that given solution too.

                    1 Reply Last reply Reply Quote 0
                    • M Offline
                      maths6a
                      last edited by

                      super star:
                      pls help me with this problem


                      fill in the blank
                      0.7:7/8=__ :___
                      Let me try:=
                      2 : 3 is also equal to 2 divide by 3

                      so 0.7 : 7/8
                      = 7/10 divide by 7/8
                      = 7/10 x 8/7
                      = 4/5
                      = 4 : 5

                      another way is to make to common denomintaors:
                      7/10 : 7/8
                      = 28/40 : 35/40
                      = 28 : 35
                      = 4 : 5

                      AM I correct?
                      THanks

                      1 Reply Last reply Reply Quote 0
                      • A Offline
                        Almighty
                        last edited by

                        super star:
                        hi maths guru

                        please help me with this problem.
                        Eliot can paint a room in 3 hrs.fred can paint the same room in 5 hrs.how long will they take to paint the room if they do it together?
                        Hi Superstar,
                        Let me try:


                        Eliot can paint 1/3 of a room in 1 hr
                        Fred can paint 1/5 th of a room in 1 hr.
                        If they paint together:
                        in 1 hr they can paint 8/15 of a room
                        So,they will take 1 7/8 hrs to paint a room together. πŸ˜„

                        1 Reply Last reply Reply Quote 0

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