Tutor MathsGuru: Ask me for your burning Maths questions!
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little_twin_stars:
Wanted to avoid decimals when it comes to multiply by 20%, 30% or even the fractions. So, I try to make life easy.Thanks...
but call me dumb, ignorant... but why 30u and 30p?
The simultaneously equation part I understand liao... but
haiz...
help ...
You can use 6u & 6p or any of its multiples…. No problem. -
okay, i understood already...
thanks a lot
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Hi thank you in advance please help me stuck on this question:
Mr Ho used to travel at a speed of 80km/h from town A to town B. He slowed down his speed to 60km/h and reached town B 1 1/2 hours later than usual. Find the distance between town A and Town B.
:?: :?: :?:
Thanks ! -
Carrot:
Speed Ratio:Hi thank you in advance please help me stuck on this question:
Mr Ho used to travel at a speed of 80km/h from town A to town B. He slowed down his speed to 60km/h and reached town B 1 1/2 hours later than usual. Find the distance between town A and Town B.
:?: :?: :?:
Thanks !
Usual : Slower
80 : 60
4 : 3
Time Ratio
Usual : Slower
3 : 4
4u - 3u = 1 1/2h
1 u = 1 1/2h
1 1/2h * 3 = 4 1/2h
4 1 /2h * 80 = 360km
Is 360km that the answer? -
Carrot:
Mr Ho used to travel at a speed of 80km/h from town A to town B. He slowed down his speed to 60km/h and reached town B 1 1/2 hours later than usual. Find the distance between town A and Town B
Constant distance
Ratio of speed
80 : 60
4 : 3
Ratio of time
3 : 4
Difference in time = 1u = 1½ h = 1.5 h
Distance travelled @ 80 km/h -> 3ux80 = 3x1.5x80 = 360 km
or
Distance travelled @ 60 km/h -> 4ux60 = 4x1.5x60 = 360 km
Distance between town A and Town B was 360 km.
OR
Using algebra and let the distance between town A and Town B be D.
Form an equation to solve:
D/80+3/2=D/60
(D+120)/80=D/60
80D = 60D+7200
20D = 7200
D = 360
Distance between town A and Town B was 360 km. -
Hi,
A pet shop owner bought some cans of dog food. He divided the dog food equally among his dogs.
If he bought 7 cans for each dog, he would have bought 4 extra cans.
If he bought 11 cans for each dog, he would need 28 more cans.
(a) How many dogs were there in the pet shop?
(b) How many cans did the owner buy?
I am confused!
Many thanks. -
starlight1968sg:
Hi, the question is familar but can't recall from which paper.Hi,
A pet shop owner bought some cans of dog food. He divided the dog food equally among his dogs.
If he bought 7 cans for each dog, he would have bought 4 extra cans.
If he bought 11 cans for each dog, he would need 28 more cans.
(a) How many dogs were there in the pet shop?
(b) How many cans did the owner buy?
I am confused!
Many thanks.
11 - 7 = 4
4 + 28 = 32
32 /4 = 8 (dogs)
8 x 7 + 4 = 60 (cans the owner buy)
Hope the abvoe useful. :lol: -
starlight1968sg:
By giving each dog 4 more cans, he use up the extra 4 cans and needed another 28 more.Hi,
A pet shop owner bought some cans of dog food. He divided the dog food equally among his dogs.
If he bought 7 cans for each dog, he would have bought 4 extra cans.
If he bought 11 cans for each dog, he would need 28 more cans.
(a) How many dogs were there in the pet shop?
(b) How many cans did the owner buy?
I am confused!
Many thanks.
Hence
28 + 4 = 32
32 / 4 = 8
a) 8 dogs
b) (7 * 8 ) + 4 = 60 -
Brenda10:
Why 11 - 7 ?11 - 7 = 4
4 + 28 = 32
32 /4 = 8 (dogs)
8 x 7 + 4 = 60 (cans the owner buy)
Hope the abvoe useful. :lol:
Then what is \"4 + 28\"?
Can you offer some explanations?
Many thanks. -
Brenda10:
Hi Brenda10,
Hi, the question is familar but can't recall from which paper.starlight1968sg:
Hi,
A pet shop owner bought some cans of dog food. He divided the dog food equally among his dogs.
If he bought 7 cans for each dog, he would have bought 4 extra cans.
If he bought 11 cans for each dog, he would need 28 more cans.
(a) How many dogs were there in the pet shop?
(b) How many cans did the owner buy?
I am confused!
Many thanks.
11 - 7 = 4
4 + 28 = 32
32 /4 = 8 (dogs)
8 x 7 + 4 = 60 (cans the owner buy)
Hope the abvoe useful. :lol:
It's from http://www.orlesson.org/orp/09Ma/2009-Math-SA2-ACS.pdf.
Hi starlight1968sg,
To help potential problem solvers in one way or another, pls kindly provide the source of your question and given answer even though the given answer may or may not 100% correct.
Thanks.
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