Tutor MathsGuru: Ask me for your burning Maths questions!

[maggieloh]

From Red Swastika Prelim 2010 MCQ Question worth 2 marks


In a group of 36 students, the number of students who like sushi is thrice the number of students who like nuggets. If 2 students like neither sushi nor nuggets and 6 students like both, how many students like nuggets ?
(1) 13
(2) 10
(3) 3
(4) 7

[corvette]

Also need with question attached. Rosyth 2010 prelims Qn 15.

Thank you.
ABCD is a square with side 12 cm. AFC and BFE are straight lines. Given that AE = ED, find the shaded of CDEF.
http://www.postimage.org/image.php?v=aVCGgL0

[corneyAmber]

maggieloh:

From Red Swastika Prelim 2010 MCQ Question worth 2 marks


In a group of 36 students, the number of students who like sushi is thrice the number of students who like nuggets. If 2 students like neither sushi nor nuggets and 6 students like both, how many students like nuggets ?
(1) 13
(2) 10
(3) 3
(4) 7

Answer is (2) 10

Check the working here: http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&start=1730

[Vanilla Cake]

corvette:

Also need with question attached. Rosyth 2010 prelims Qn 15.

Thank you
http://www.postimage.org/image.php?v=aVCGgL0

There is missing info in your diagram. Pls refer to the http://2.bp.blogspot.com/_EG8oMs7TIYA/TIns3AWWjTI/AAAAAAAAAR0/x-6klcSbE-8/s1600/MathsP610AreaRosythA15.jpg in Uncle Observer's blog.

[maggieloh]

ksi:

maggieloh:

From Red Swastika Prelim 2010 MCQ Question worth 2 marks


Answer is (2) 10

Check the working here: http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&start=1730

Thanks :lol:

[corvette]

Vanilla Cake:

corvette:

Also need with question attached. Rosyth 2010 prelims Qn 15.

Thank you
http://www.postimage.org/image.php?v=aVCGgL0

There is missing info in your diagram. Pls refer to the http://2.bp.blogspot.com/_EG8oMs7TIYA/TIns3AWWjTI/AAAAAAAAAR0/x-6klcSbE-8/s1600/MathsP610AreaRosythA15.jpg in Uncle Observer's blog.

Sorry have put in missing info but where can Isee Uncle Observer's solution?

[Vanilla Cake]

corvette:

Vanilla Cake:

[quote=\"corvette\"]Also need with question attached. Rosyth 2010 prelims Qn 15.

Thank you
http://www.postimage.org/image.php?v=aVCGgL0

There is missing info in your diagram. Pls refer to the http://2.bp.blogspot.com/_EG8oMs7TIYA/TIns3AWWjTI/AAAAAAAAAR0/x-6klcSbE-8/s1600/MathsP610AreaRosythA15.jpg in Uncle Observer's blog.

Sorry have put in missing info but where can Isee Uncle Observer's solution?[/quote]http://psle2010a.blogspot.com/2010/09/area-p6-2010-sa2-rosyth-p2-q15.html for Rosyth P6 Prelim 2010 Paper 2 Q15. Pls visit his http://psle2010a.blogspot.com/ for solutions for most of the questions from P6 Prelim 2010 - top schools.

[benorito]

This is from Red Swastika Prelim 2010 Q 8:


Raju and Gywneth shared some sweets. If Raju gave 1/2 of his share to Gywneth, Gywneth will have 8 more sweets from Raju. If Raju gave 1/4 of his share to Gywneth, Gywneth would have 2 more sweets than Raju. How many sweets did Raju have at first ?

The given answer was 12. Is this correct ?

[kancheongmum]

benorito:

This is from Red Swastika Prelim 2010 Q 8:


Raju and Gywneth shared some sweets. If Raju gave 1/2 of his share to Gywneth, Gywneth will have 8 more sweets from Raju. If Raju gave 1/4 of his share to Gywneth, Gywneth would have 2 more sweets than Raju. How many sweets did Raju have at first ?

The given answer was 12. Is this correct ?

Hi this is how my ds solve the problem as he is not good with model:

get the common denominator for both fraction 1/2 --- 2/4
Raju has a total of 4u at first
this is internal transfer so total for both cases are equal

1st case --- Raju gave Gywneth 2u --- total --- 2u + 2u +8 = 4u +8
2nd case ---Raju gave Gywneth 1u --- total --- 3u + 3u +2 = 6u +2

4u + 8 = 6u + 2
2u --- 6
1u --- 3

4u --- 3 x 4 = 12 sweets

[corneyAmber]

benorito:

This is from Red Swastika Prelim 2010 Q 8:


Raju and Gywneth shared some sweets. If Raju gave 1/2 of his share to Gywneth, Gywneth will have 8 more sweets from Raju. If Raju gave 1/4 of his share to Gywneth, Gywneth would have 2 more sweets than Raju. How many sweets did Raju have at first ?

The given answer was 12. Is this correct ?

The answer is correct.

Raju [ ][ ][ ][ ] -> 4 parts (before giving away)
After for Raju if he gave 1/2 [ ][ ]
After for Gyw if she recd 1/2 [ ][ ]<8>

After for Raju if he gave 1/4 [ ][ ][ ]
After for Gyw if she recd 1/2 [ ][ ][ ] <2>

So (Raju)2 parts + (Gyw)2 parts + 8 = (Raju)3 parts + (Gyw)3 parts + 2
4 parts + 8 = 6 parts + 2
2 parts = 6
1 part = 3

So Raju has 4 parts initially => (4*3) = 12 sweets