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ksi:
Thanks :lol:maggieloh:
From Red Swastika Prelim 2010 MCQ Question worth 2 marks
Answer is (2) 10
Check the working here: http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&start=1730 -
Vanilla Cake:
Sorry have put in missing info but where can Isee Uncle Observer's solution?
There is missing info in your diagram. Pls refer to the http://2.bp.blogspot.com/_EG8oMs7TIYA/TIns3AWWjTI/AAAAAAAAAR0/x-6klcSbE-8/s1600/MathsP610AreaRosythA15.jpg in Uncle Observer's blog.corvette:
Also need with question attached. Rosyth 2010 prelims Qn 15.
Thank you
http://www.postimage.org/image.php?v=aVCGgL0 -
corvette:
Sorry have put in missing info but where can Isee Uncle Observer's solution?[/quote]http://psle2010a.blogspot.com/2010/09/area-p6-2010-sa2-rosyth-p2-q15.html for Rosyth P6 Prelim 2010 Paper 2 Q15. Pls visit his http://psle2010a.blogspot.com/ for solutions for most of the questions from P6 Prelim 2010 - top schools.
There is missing info in your diagram. Pls refer to the http://2.bp.blogspot.com/_EG8oMs7TIYA/TIns3AWWjTI/AAAAAAAAAR0/x-6klcSbE-8/s1600/MathsP610AreaRosythA15.jpg in Uncle Observer's blog.Vanilla Cake:
[quote=\"corvette\"]Also need with question attached. Rosyth 2010 prelims Qn 15.
Thank you
http://www.postimage.org/image.php?v=aVCGgL0 -
This is from Red Swastika Prelim 2010 Q 8:
Raju and Gywneth shared some sweets. If Raju gave 1/2 of his share to Gywneth, Gywneth will have 8 more sweets from Raju. If Raju gave 1/4 of his share to Gywneth, Gywneth would have 2 more sweets than Raju. How many sweets did Raju have at first ?
The given answer was 12. Is this correct ? -
benorito:
Hi this is how my ds solve the problem as he is not good with model:This is from Red Swastika Prelim 2010 Q 8:
Raju and Gywneth shared some sweets. If Raju gave 1/2 of his share to Gywneth, Gywneth will have 8 more sweets from Raju. If Raju gave 1/4 of his share to Gywneth, Gywneth would have 2 more sweets than Raju. How many sweets did Raju have at first ?
The given answer was 12. Is this correct ?
get the common denominator for both fraction 1/2 --- 2/4
Raju has a total of 4u at first
this is internal transfer so total for both cases are equal
1st case --- Raju gave Gywneth 2u --- total --- 2u + 2u +8 = 4u +8
2nd case ---Raju gave Gywneth 1u --- total --- 3u + 3u +2 = 6u +2
4u + 8 = 6u + 2
2u --- 6
1u --- 3
4u --- 3 x 4 = 12 sweets -
benorito:
The answer is correct.This is from Red Swastika Prelim 2010 Q 8:
Raju and Gywneth shared some sweets. If Raju gave 1/2 of his share to Gywneth, Gywneth will have 8 more sweets from Raju. If Raju gave 1/4 of his share to Gywneth, Gywneth would have 2 more sweets than Raju. How many sweets did Raju have at first ?
The given answer was 12. Is this correct ?
Raju [ ][ ][ ][ ] -> 4 parts (before giving away)
After for Raju if he gave 1/2 [ ][ ]
After for Gyw if she recd 1/2 [ ][ ]<8>
After for Raju if he gave 1/4 [ ][ ][ ]
After for Gyw if she recd 1/2 [ ][ ][ ] <2>
So (Raju)2 parts + (Gyw)2 parts + 8 = (Raju)3 parts + (Gyw)3 parts + 2
4 parts + 8 = 6 parts + 2
2 parts = 6
1 part = 3
So Raju has 4 parts initially => (4*3) = 12 sweets -
benorito:
1/2 - (-1/2) = 1 whole => 8This is from Red Swastika Prelim 2010 Q 8:
Raju and Gywneth shared some sweets. If Raju gave 1/2 of his share to Gywneth, Gywneth will have 8 more sweets from Raju. If Raju gave 1/4 of his share to Gywneth, Gywneth would have 2 more sweets than Raju. How many sweets did Raju have at first ?
The given answer was 12. Is this correct ?
1/4 - (-1/4) = 1/2 => 2
Diff = 1/2 => 8 - 2 = 6
1 whole => 12 ( total number of sweets Raju had at first ) -
Hi,
Need help with the below 2 questions :
1) Nanyang 2010 P6 Prelim paper 1 Qn 21
The cost of 3 mangoes is the same as the cost of 5 grapefruits.
The cost of 3 mangoes is also the same as the cost of 10 pears.
Find the ratio of the cost of a mango to the cost of a grapefruit to the cost of a pear.
(ans : 10 : 6 : 3)
2) Nanyang 2010 P6 Prelim paper 1 Qn 30
The figure below is formed by stacking 4 pieces of square paper one on top of another. The papers have different prints and sizes (of sides 3cm, 4cm, 5cm and 6cm).
The 6-cm piece is placed at the bottom of the stack, followed by the 5-cm piece, then the 4-cm piece and the 3-cm piece is placed right on top.
Find the sum of the area A and B.
(ans : 8 cm2)
http://www.postimage.org/image.php?v=aVDISRJ
Thank you very much! -
[Moderator's note: Article edited & selected for http://www.kiasuparents.com/kiasu/content/some-questions-and-answers-primary-6-math]
YLH88:
Nanyang 2010 P6 Prelim paper 1 Qn 21Hi,
Need help with the below 2 questions :
1) Nanyang 2010 P6 Prelim paper 1 Qn 21
The cost of 3 mangoes is the same as the cost of 5 grapefruits.
The cost of 3 mangoes is also the same as the cost of 10 pears.
Find the ratio of the cost of a mango to the cost of a grapefruit to the cost of a pear.
(ans : 10 : 6 : 3)
2) Nanyang 2010 P6 Prelim paper 1 Qn 30
The figure below is formed by stacking 4 pieces of square paper one on top of another. The papers have different prints and sizes (of sides 3cm, 4cm, 5cm and 6cm).
The 6-cm piece is placed at the bottom of the stack, followed by the 5-cm piece, then the 4-cm piece and the 3-cm piece is placed right on top.
Find the sum of the area A and B.
(ans : 8 cm2)
http://www.postimage.org/image.php?v=aVDISRJ
Thank you very much!
3M = 5G
1M = 5/3 G
1M : 1G = 5 : 3 = 10 : 6
3M = 10P
1M = 10/3 P
1M : 1P = 10 : 3
1M : 1G : 1P = 10 : 6 : 3
Nanyang 2010 P6 Prelim paper 1 Qn 30
Area of large square β Area of yellow square = 6^2 β 3^2 = 36 β 9 = 27
Yellow square => 3 x 3
Orange square => 4 x 4
White square => 5 x 5
Blue square => 6 x 6
Length of A = Width of A = 6 - 4 = 2
Area of A = 2 X 2 = 4
Area of A = Area of B [Symmetry]
Area of A + Area of B = 4cm2 x 2 = 8cm2 -
Dear all,
May I know is there any good books to learn and practice Mathematics Solving? I think I really need it in order to understand and prepare myself when I teach my daughter.
TIA.
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