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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • V Offline
      Vanilla Cake
      last edited by

      abc_parent:
      Q12) Tank P was filled with water as shown in the diagram (pls help with this if you have the diagram). Water was then poured from Tank P to Tank Q until the height of the water level in Tank P became twice that of the water level in Tank Q. Find the volume of water in Tank Q. Given your answers in litres.

      http://www.orlesson.org/orp/09Ma/2009-P6-Math-SA2-HenryPark.pdf
      Suggested solution
      Original volume of water in tank P = 55cmx40cmx30cm = 66000 cm³
      Assume the height of water in Tank Q be h,
      New volume of water in tank P = 2h cmx40cmx30cm=2400h cm³
      New volume of water in tank Q = h cmx100cmx20cm = 2000h cm³
      2400h + 2000h = 66000
      4400h = 66000
      h = 15

      New volume of water in Tank Q = 15cmx100cmx20cm = 30000 cm³ = 30 litres.
      Volume of water in Tank Q = 30 litres.

      PS: If there is given answer, pls state it together with the question. Does not matter if it's 100% or not, the given answer is for reference purpose.

      1 Reply Last reply Reply Quote 0
      • D Offline
        Dharma
        last edited by

        Vanilla Cake:
        Hi Uncle Tianzhu / Uncle Dharma,


        Could you pls spare time to look into part (b) of http://psle2010a.blogspot.com/2010/09/volume-p6-2010-maha-bodhi-p2-q13.html and express your comments.The answer given for (b) is 56.25
        Thanks.
        Hi VC,

        Definately there is lack of info from what I read from the qn in Observer's blog. I don't have the actual papers to check the actual wordings on the qn.

        1 Reply Last reply Reply Quote 0
        • T Offline
          tianzhu
          last edited by

          Vanilla Cake:
          Hi Uncle Tianzhu / Uncle Dharma,

          Could you pls spare time to look into part (b) of http://psle2010a.blogspot.com/2010/09/volume-p6-2010-maha-bodhi-p2-q13.html and express your comments.The answer given for (b) is 56.25
          Thanks.
          Hi VC

          There may be some missing information.

          Best wishes

          1 Reply Last reply Reply Quote 0
          • T Offline
            tianzhu
            last edited by

            Maha Bodhi P6 Prelim 2010: Paper 2: Q16. Tom and Jerry shared a box of marbles. If Tom was given 10 fewer marbles, Jerry would have five times as many marbles as Tom. If Tom was given 10 more marbles, he would have ½ as many marbles as Jerry. What percentage of the marbles did Tom receive? [5 marks][Answer given: 25%]


            Hi VC

            Have you tried this question?
            Could you get the same answer as given in the WS?

            You may use MD.

            Before
            Tom -------1u+10
            Jerry -------5 units

            After
            Tom ------- 1u+10+10
            Jerry ------- 2units+40

            3 units ------40
            1unit ------40/3

            Tom ------- 40/3+10 ----- 70/3
            Jerry -------200/3

            Total number of marbles ------- 200/3+70/3 --------90

            Tom/Total ---------70/3/90*100 ------- 25 25/27% (25 and 25/27%)

            Best wishes

            1 Reply Last reply Reply Quote 0
            • V Offline
              Vanilla Cake
              last edited by

              tianzhu:
              Maha Bodhi P6 Prelim 2010: Paper 2: Q16. Tom and Jerry shared a box of marbles. If Tom was given 10 fewer marbles, Jerry would have five times as many marbles as Tom. If Tom was given 10 more marbles, he would have ½ as many marbles as Jerry. What percentage of the marbles did Tom receive? [5 marks][Answer given: 25%]


              Hi VC

              Have you tried this question?
              Could you get the same answer as given in the WS?

              You may use MD.

              Before
              Tom -------1u+10
              Jerry -------5 units

              After
              Tom ------- 1u+10+10
              Jerry ------- 2units+40

              3 units ------40
              1unit ------40/3

              Tom ------- 40/3+10 ----- 70/3
              Jerry -------200/3

              Total number of marbles ------- 200/3+70/3 --------90

              Tom/Total ---------70/3/90*100 ------- 25 25/27% (25 and 25/27%)

              Best wishes
              Dear Uncle Tianzhu,

              Sorry for the late reply as I had accompanied my mum to the wet market, this morning.Thanks for highlighting and after reading your post, I went to look at my calculations again and also went to http://psle2010a.blogspot.com/2010/09/maha-bodhi-p6-prelim-2010-paper-2-q16.html.
              Both of you got 25 and 25/27%. It's the way of interpretation of the question that matters. My one is different from both of you and pls don't laugh at me (just joking) if I am wrong. Using unit and part method that Uncle Dharma usually uses, pls correct me along the way:

              Case 1
              T = u+10
              J = 5u-10

              Case 2
              T = p-10
              J = 2p+10

              2p+10=5u-10
              2p =5u-20
              p = 2.5u-10

              u+10=p-10
              u+10=2.5u-20
              30=1.5u
              u=20
              p=40

              T = u+10 = 20+10 = 30 or p-10 = 40-10=30
              J = 5u-10 = 5(20)-10 =90 or 2p+10 = 2(40)+10 = 90
              Total of T + J = 30+90=120

              Percentage of the marbles received by Tom =30/120x100% = 25%

              1 Reply Last reply Reply Quote 0
              • T Offline
                trytry
                last edited by

                Vanilla Cake:
                tianzhu:

                Maha Bodhi P6 Prelim 2010: Paper 2: Q16. Tom and Jerry shared a box of marbles. If Tom was given 10 fewer marbles, Jerry would have five times as many marbles as Tom. If Tom was given 10 more marbles, he would have ½ as many marbles as Jerry. What percentage of the marbles did Tom receive? [5 marks][Answer given: 25%]


                Hi VC

                Have you tried this question?
                Could you get the same answer as given in the WS?

                You may use MD.

                Before
                Tom -------1u+10
                Jerry -------5 units

                After
                Tom ------- 1u+10+10
                Jerry ------- 2units+40

                3 units ------40
                1unit ------40/3

                Tom ------- 40/3+10 ----- 70/3
                Jerry -------200/3

                Total number of marbles ------- 200/3+70/3 --------90

                Tom/Total ---------70/3/90*100 ------- 25 25/27% (25 and 25/27%)

                Best wishes

                Dear Uncle Tianzhu,

                Sorry for the late reply as I had accompanied my mum to the wet market, this morning.Thanks for highlighting and after reading your post, I went to look at my calculations again and also went to http://psle2010a.blogspot.com/2010/09/maha-bodhi-p6-prelim-2010-paper-2-q16.html.
                Both of you got 25 and 25/27%. It's the way of interpretation of the question that matters. My one is different from both of you and pls don't laugh at me (just joking) if I am wrong. Using unit and part method that Uncle Dharma usually uses, pls correct me along the way:

                Case 1
                T = u+10
                J = 5u-10

                Case 2
                T = p-10
                J = 2p+10

                2p+10=5u-10
                2p =5u-20
                p = 2.5u-10

                u+10=p-10
                u+10=2.5u-20
                30=1.5u
                u=20
                p=40

                T = u+10 = 20+10 = 30 or p-10 = 40-10=30
                J = 5u-10 = 5(20)-10 =90 or 2p+10 = 2(40)+10 = 90
                Total of T + J = 30+90=120

                Percentage of the marbles received by Tom =30/120x100% = 25%


                Can also using units(u) only

                After 1st condition

                Tom:1u
                Jerry:5u

                Reinstate to original position
                Tom:1u+10
                Jerry:5u-10

                2nd condition using original position data

                ..........................................ratio
                Tom:1u+10+10=1u+20--------1
                Jerry:5u-10-10=5u-20----------2

                ===>2u+40=5u-20
                .........3u=60
                .........1u=20

                Tom has 1x20+10=30
                Jerry has 5x20-10=90
                Total=30+90=120

                Percentage=30/120x100=25%

                1 Reply Last reply Reply Quote 0
                • G Offline
                  Guthix
                  last edited by

                  tianzhu:
                  Maha Bodhi P6 Prelim 2010: Paper 2: Q16. Tom and Jerry shared a box of marbles. If Tom was given 10 fewer marbles, Jerry would have five times as many marbles as Tom. If Tom was given 10 more marbles, he would have ½ as many marbles as Jerry. What percentage of the marbles did Tom receive? [5 marks][Answer given: 25%]


                  Hi VC

                  Have you tried this question?
                  Could you get the same answer as given in the WS?

                  You may use MD.

                  Before
                  Tom -------1u+10
                  Jerry -------5 units

                  After
                  Tom ------- 1u+10+10
                  Jerry ------- 2units+40

                  3 units ------40
                  1unit ------40/3

                  Tom ------- 40/3+10 ----- 70/3
                  Jerry -------200/3

                  Total number of marbles ------- 200/3+70/3 --------90

                  Tom/Total ---------70/3/90*100 ------- 25 25/27% (25 and 25/27%)

                  Best wishes
                  Alternatively, you can use algebra.
                  ---------------------------------------------------------------------------------

                  Let t and j represent the number of marbles Tom and Jerry received respectively.

                  j+10=5*(t-10)
                  =5t-50
                  -----------------------
                  Therefore, we have statement 1:
                  j=5t-60
                  -----------------------
                  t+10=(j-10) * 1/2
                  t+10=j/2 - 10/2
                  t+10=j/2 - 5
                  ----------------------
                  Statement 2:
                  t=j/2-15
                  ----------------------
                  Since we know what 't' is in terms of j,
                  Therefore we can replace the 't' in statement 1
                  in terms of 'j'.
                  We have:

                  j=5(j/2-15)-60
                  j= 5j/2 - 75-60
                  j=5j/2 - 135
                  ---------------------
                  We bring all numbers to one side of the equation:
                  5j/2 - j = 135

                  Get rid of the '/2' by multiplying BOTH sides of the equation by 2:

                  5j-2j=270
                  3j=270
                  j=90

                  If Tom was given 10 fewer marbles, Jerry would have five times as many marbles as Tom.

                  j+10=5(t-10)
                  100=5(t-10)
                  t=30
                  30/(90+30)=30/120=25%

                  Note: the PSLE teachers are known to be stingy and MAY penalize you for this: 30/120=25%
                  The safest way is: (30*100%)/(120*100%)=25%

                  1 Reply Last reply Reply Quote 0
                  • T Offline
                    tianzhu
                    last edited by

                    Vanilla Cake:

                    Sorry for the late reply as I had accompanied my mum to the wet market, this morning.Thanks for highlighting and after reading your post, I went to look at my calculations again and also went to http://psle2010a.blogspot.com/2010/09/maha-bodhi-p6-prelim-2010-paper-2-q16.html.
                    Both of you got 25 and 25/27%. It's the way of interpretation of the question that matters. My one is different from both of you and pls don't laugh at me (just joking) if I am wrong.
                    Hi VC

                    I think your mother is training you to be a good wife in the future.

                    There is always more than one ways of looking at a question. How one interprets the question can sometimes lead to different answers.

                    One of the challenges faced by students is guessing correctly what the question setter wanted them to do.

                    Yes, how you interpret the question is logical.The key word here is shared.

                    I am sorry for making the mistake.

                    Best wishes

                    1 Reply Last reply Reply Quote 0
                    • B Offline
                      BryBenMum
                      last edited by

                      Hi,

                      Please help with this question,
                      Ailing, Bala, Chris and Dawn shared the cost of a gift for their friend. Ailing paid 1/5 of the amt paid by Bala, Chris and Dawn. Chris paid 40% of the amt paid by Ailing and Bala. The total amt paid by Ailing and Bala is equal to that paid by Chris and Dawn. Given that Dawn paid $32 more than Ailing for the gift, what was the cost of the gift?
                      Thank you![/list]

                      1 Reply Last reply Reply Quote 0
                      • B Offline
                        BryBenMum
                        last edited by

                        Hi,

                        Please help with this question,
                        Ailing, Bala, Chris and Dawn shared the cost of a gift for their friend. Ailing paid 1/5 of the amt paid by Bala, Chris and Dawn. Chris paid 40% of the amt paid by Ailing and Bala. The total amt paid by Ailing and Bala is equal to that paid by Chris and Dawn. Given that Dawn paid $32 more than Ailing for the gift, what was the cost of the gift?
                        Thank you![/list]

                        1 Reply Last reply Reply Quote 0

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