Tutor MathsGuru: Ask me for your burning Maths questions!
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liketoeat:
There is answer given for this question. Your question is from http://www.orlesson.org/orp/09Ma/2009-P6-Math-CA1-Rulang.pdf.Hi, I need help with this question. No answer given.
A group of people went hunting. On average, 6 people hunted 5 rabbits, 15 people hunted 2 deer and 10 people hunted 1 buffalo. The total number of animals hunted was 6 more than the total number of people who went hunting. How many people went hunting?
Thank you.
Answer is 90 people and Tianzhu and Dharma had solved and posted the solution for this question before in KSP forum.
Tianzhu/Dharma - Pls repost the solution or direct the link for your solution.
Thks
VC's mum
Suggested solution from DD2 (P5)
\"->\" means hunted
6p-> 5r
30p-> 25r
15p-> 2d
30p-> 4d
10p-> 1b
30p-> 3b
Total: 30p, 32 animals
Difference=2
6÷2=3
3x30=90
Answer : 90 people -
Vanilla Cake:
6 people => 5 rabbits
There is answer given for this question. Your question is from http://www.orlesson.org/orp/09Ma/2009-P6-Math-CA1-Rulang.pdf.liketoeat:
Hi, I need help with this question. No answer given.
A group of people went hunting. On average, 6 people hunted 5 rabbits, 15 people hunted 2 deer and 10 people hunted 1 buffalo. The total number of animals hunted was 6 more than the total number of people who went hunting. How many people went hunting?
Thank you.
Answer is 90 people and Tianzhu and Dharma had solved and posted the solution for this question before in KSP forum.
Tianzhu/Dharma - Pls repost the solution or direct the link for your solution.
Thks
Suggested solution from DD2 (P5)
\"->\" means hunted
6p-> 5r
30p-> 25r
15p-> 2d
30p-> 4d
10p-> 1b
30p-> 3b
Total: 30p, 32 animals
Difference=2
6÷2=3
3x30=90
Answer : 90 people
VC's mum
30 people => 25 rabbits
15 people => 2 deers
30 people => 4 deers
10 people => 1 buffalo
30 people => 3 buffaloes
A group of 30 people can hunt (25 + 4 + 3) = 32 animals
Difference between the no. of animals and people = 32 – 30 = 2
If the difference between the no. of animals and people = 6
No. of people who went hunting = 30 x 3 = 90 -
Vanilla Cake:
Hi
There is answer given for this question. Your question is from http://www.orlesson.org/orp/09Ma/2009-P6-Math-CA1-Rulang.pdf.liketoeat:
Hi, I need help with this question. No answer given.
A group of people went hunting. On average, 6 people hunted 5 rabbits, 15 people hunted 2 deer and 10 people hunted 1 buffalo. The total number of animals hunted was 6 more than the total number of people who went hunting. How many people went hunting?
Thank you.
Answer is 90 people and Tianzhu and Dharma had solved and posted the solution for this question before in KSP forum.
Tianzhu/Dharma - Pls repost the solution or direct the link for your solution.Thks
Please refer to pg 38 of this thread.
http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=6373&postdays=0&postorder=asc&start=370
Best wishes -
Thank you very much to VC’s mum, DD2, Dharma and Tianzhu for your very quick response. Thank you again.
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Vanilla Cake:
Hi Vanilla Cake and Ler
Quick one as I need to go to school,my mum will continue for the rest of your problem sums.Ler:
Maha Bohi SA2 math 2010, Paper 2
Many thanks for working out most of the solutions. I hv problem understanding but still trying to work out.Ler:
Pls post the diagram otherwise how can others be expected to solve without reading the diagram? I notice that you have changed your question as the original question stated \"AB is 10m\" and the diagram showed length of AB labeled as 10m. The original question also stated 133 m² and this is where the confusion comes.So, I change all metres and metres square to cm and cm² to make life simple.Question 7 - In the diagram show above, O is the centre of the circle and OAB is a right angle triange. Given that AB is 10cm and the shaded parts of the circle add up to 133 m square. Find the area of the circle.
Square of length of AO+Square of length of OB=10cmx10cm (http://en.wikipedia.org/wiki/Pythagorean_theorem)
but length of AO=length of OB (radii of circle)
Assume length of AO be n, so
n²+n²=100
2n²=100
n²=50
Area of triangle AOB = 1/2xABxOB=1/2xn²=1/2x50=25 cm²
Since area of the shaded part of the circle was given as 133 cm², area of the circle = (25+133) cm² = 158 cm².
Need to go now and mum will continue the rest.
This Maha Bodhi prelim 2010 paper is very challenging and have a few very interesting questions. Vanilla Cake I don't think Q7 should be solved this way. Pythagoras' Theorem is not taught in P6 yet.
Area of the triangle = 1/2 x base x height
if the radius is given you can use that to work out the answer. But not given in this case. So look at the triangle in another way. You will note that it is 1/4 of the square inscribe in the circle.
base = 10m height = 10m/2 = 5 m
area of the circle = 133m3 + (1/2 x 10x5) =158m3
I always tell my ds, don't think too complicated when doing the questions. They will not give you anything out of the syllabus. Make use of the basic concept taught. -
kancheongmum:
Hi Vanilla Cake and Ler
Quick one as I need to go to school,my mum will continue for the rest of your problem sums.Vanilla Cake:
[quote=\"Ler\"]Maha Bohi SA2 math 2010, Paper 2
Many thanks for working out most of the solutions. I hv problem understanding but still trying to work out.Ler:
Pls post the diagram otherwise how can others be expected to solve without reading the diagram? I notice that you have changed your question as the original question stated \"AB is 10m\" and the diagram showed length of AB labeled as 10m. The original question also stated 133 m² and this is where the confusion comes.So, I change all metres and metres square to cm and cm² to make life simple.Question 7 - In the diagram show above, O is the centre of the circle and OAB is a right angle triange. Given that AB is 10cm and the shaded parts of the circle add up to 133 m square. Find the area of the circle.
Square of length of AO+Square of length of OB=10cmx10cm (http://en.wikipedia.org/wiki/Pythagorean_theorem)
but length of AO=length of OB (radii of circle)
Assume length of AO be n, so
n²+n²=100
2n²=100
n²=50
Area of triangle AOB = 1/2xABxOB=1/2xn²=1/2x50=25 cm²
Since area of the shaded part of the circle was given as 133 cm², area of the circle = (25+133) cm² = 158 cm².
Need to go now and mum will continue the rest.
This Maha Bodhi prelim 2010 paper is very challenging and have a few very interesting questions. Vanilla Cake I don't think Q7 should be solved this way. Pythagoras' Theorem is not taught in P6 yet.
Area of the triangle = 1/2 x base x height
if the radius is given you can use that to work out the answer. But not given in this case. So look at the triangle in another way. You will note that it is 1/4 of the square inscribe in the circle.
base = 10m height = 10m/2 = 5 m
area of the circle = 133m3 + (1/2 x 10x5) =158m3
I always tell my ds, don't think too complicated when doing the questions. They will not give you anything out of the syllabus. Make use of the basic concept taught.[/quote]kancheong mum is correct. Nothing wrong to use Pythagoras but it is not necessary to use it.
Always try to keep things simple and that will make life easy for us. -
kancheongmum:
Hi kancheongmum,Hi Vanilla Cake and Ler
This Maha Bodhi prelim 2010 paper is very challenging and have a few very interesting questions. Vanilla Cake I don't think Q7 should be solved this way. Pythagoras' Theorem is not taught in P6 yet.
Area of the triangle = 1/2 x base x height
if the radius is given you can use that to work out the answer. But not given in this case. So look at the triangle in another way. You will note that it is 1/4 of the square inscribe in the circle.
base = 10m height = 10m/2 = 5 m
area of the circle = 133m3 + (1/2 x 10x5) =158m3
Thks for your highlight. I think that Vanilla Cake (Sec 2) must have forgotten what are taught at P6 level and apply the right method to solve this question - Maha Bodhi School P6 Prelim Paper P2 Q7. :oops:
This type of question is common and has appeared quite a number of times in past years' school exams.If necessary, extend the triangle AOB to form a square within the circle for better visualisation.
AB is 10 m which is the side of the square ie the base of the triangle AOB.To find the height which is 1/2 of the side of the square, just divide 10 by 2 = 5 m
Area of triangle = 1/2x10x5=25 m²
BTW, I think that there is a typo error in this question. All units should be all in cm instead of m.
Hi Dharma,
Thks for your understanding and will let Vanilla Cake knows about this.
VC's mum -
Vanilla Cake:
Thks for your highlight. I think that Vanilla Cake (Sec 2) must have forgotten what are taught at P6 level and apply the right method to solve this question - Maha Bodhi School P6 Prelim Paper P2 Q7. :oops:kancheongmum:
Hi Vanilla Cake and Ler
This Maha Bodhi prelim 2010 paper is very challenging and have a few very interesting questions. Vanilla Cake I don't think Q7 should be solved this way. Pythagoras' Theorem is not taught in P6 yet.
Area of the triangle = 1/2 x base x height
if the radius is given you can use that to work out the answer. But not given in this case. So look at the triangle in another way. You will note that it is 1/4 of the square inscribe in the circle.
base = 10m height = 10m/2 = 5 m
area of the circle = 133m3 + (1/2 x 10x5) =158m3
This type of question is common and has appeared quite a number of times in past years' school exams.If necessary, extend the triangle AOB to form a square within the circle for better visualisation.
AB is 10 m which is the side of the square ie the base of the triangle AOB.To find the height which is 1/2 of the side of the square, just divide 10 by 2 = 5 m
Area of triangle = 1/2x10x5=25 m²
BTW, I think that there is a typo error in this question. All units should be all in cm instead of m.
Hi Dharma,
Thks for your understanding and will let Vanilla Cake knows about this.
VC's mum
Hi VC, VC mum, Kancheongmum, and Dharma
My kid is taking PSLE this year. She is so weak in math, so am I. When I have given her to do the paper, she almost done every sum wrong. Very sad , cant help her. I personally feel that Mohd Bohi sat the paper very challenging, i cant do at all. Very worried that she will fail the math paper. I happen came across this website yesterday, i was so happy. Sincerely, I like to thank you all for helping me to solve these questions. I am still studying how to explain to her. I might have more questions to ask for help. ....Thanks. (Very sorry , a lot of typing error, next time, i will type out the questions.).
Ler -
Hi Ler
No problem there are many people here to help. I have been blessed by this forum, so I will try to contribute if I can. My advice to you now is don’t give your daughter the very challenging questions now. She will get panic if she has weak foundation. Concentrate on the basic concepts and try and to score perfect for the easy questions. For the difficult questions, she may not get the right answers but don’t leave it blank. Read the questions sentence by sentence and try to answer. Remember marks will be awarded for workings. My son is sitting for PSLE too. I always tell him every numbers, fraction has a meaning and story to tell. When he has problem with the question I will ask him to do that. Hope this will encourage you. -
Hi Ler,
Think from now on, try to get her to go thru all the school worksheets and all the exams papers given by the school; especially the questions she had gotten wrong previously. Try to understand where sge went wrong and re-do those questions so that she understands the workings well.
Concentrate on the simple and straight forward questions and make sure she doesn’t make careless mistakes. Next are questions that are of medium level of difficulty. If she’s able handle them, don’t worry too much about the very dfficult ones. Don’t even bother to practice them because if her foundation is not strong then it may make things worse. Focus on Paper 1 and first half of Paper 2.
For problems, most of the questions willbe on ratios, fraction, percentage, whole numbers & mensuration.
If you have problems with any of the questions, pls post them on either one of the 2 Maths threads and there will be people to help u out.
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