Tutor MathsGuru: Ask me for your burning Maths questions!

[Herbie]

How many girls passed the test?

tx

[Dharma]

Herbie:

340 children the test

Hi Herbie,

340 children passed or failed the test.?

[YLH88]

Dharma:

firebird:

Dear maths guru


Please help me on the following maths:

2) At 9am John was cycling from Point A to Point B. At the same time, Mary was cycling from point B to point A using the same route as John. Cycliing at a speed of 4km/h faster than Mary, they would pass each other 300 meter away from the mid point.

a) What time did they pass each other?
b) If John took another 3 minutes to reach Point B, what time would Mary reach Poin A?

Q2)
a) Difference in distance travelled by John and Mary = 4km/h x T
T = 0.3km x 2/(4km/hr) = 3/20 hrs = 9 mins
Time they passed each other => 9.09am

b) For a fixed distance
Time ratio => John : Mary = 3 : 9 = 1 : 3
If John takes 12 mins to travel from A to B; Mary will take 36 mins to travel from B to A.
Mary reaches Pt A at 9.36am

Hi Dharma,

For the speed question stated above, for part (b), how do you get
Time ratio --> John : Mary = 3 : 9 ?

:?

[Dharma]

YLH88:

Dharma:

[quote=\"firebird\"]Dear maths guru


Please help me on the following maths:

2) At 9am John was cycling from Point A to Point B. At the same time, Mary was cycling from point B to point A using the same route as John. Cycliing at a speed of 4km/h faster than Mary, they would pass each other 300 meter away from the mid point.

a) What time did they pass each other?
b) If John took another 3 minutes to reach Point B, what time would Mary reach Poin A?

Q2)
a) Difference in distance travelled by John and Mary = 4km/h x T
T = 0.3km x 2/(4km/hr) = 3/20 hrs = 9 mins
Time they passed each other => 9.09am

b) For a fixed distance
Time ratio => John : Mary = 3 : 9 = 1 : 3
If John takes 12 mins to travel from A to B; Mary will take 36 mins to travel from B to A.
Mary reaches Pt A at 9.36am

Hi Dharma,

For the speed question stated above, for part (b), how do you get
Time ratio --> John : Mary = 3 : 9 ?

:?[/quote]
From the meeting place( place where John and Mary passed each other); John takes another 3 minutes to reach Point B [Given in part (b) of question]

Mary takes 9 minutes to reach the meeting place from Point B [we worked this out in part (a)]

For the same distance (meeting place to Point B or vice versa)
Time ratio of John : Mary = 3 : 9 = 1 : 3

[YLH88]

Dharma:

YLH88:

[quote=\"Dharma\"]
Q2)
a) Difference in distance travelled by John and Mary = 4km/h x T
T = 0.3km x 2/(4km/hr) = 3/20 hrs = 9 mins
Time they passed each other => 9.09am

b) For a fixed distance
Time ratio => John : Mary = 3 : 9 = 1 : 3
If John takes 12 mins to travel from A to B; Mary will take 36 mins to travel from B to A.
Mary reaches Pt A at 9.36am

Hi Dharma,

For the speed question stated above, for part (b), how do you get
Time ratio --> John : Mary = 3 : 9 ?

:?

From the meeting place( place where John and Mary passed each other); John takes another 3 minutes to reach Point B [Given in part (b) of question]

Mary takes 9 minutes to reach the meeting place from Point B [we worked this out in part (a)]

For the same distance (meeting place to Point B or vice versa)
Time ratio of John : Mary = 3 : 9 = 1 : 3[/quote]1:3 is from mtg place to B, so it also means is the same ratio 1:3 from A to B ? so if total time for John is 12 min, this means 1u = 12 min, so for Mary, 3u = 12 x 3 = 36 min ?

[Dharma]

YLH88:

Dharma:

[quote=\"YLH88\"]
Hi Dharma,

For the speed question stated above, for part (b), how do you get
Time ratio --> John : Mary = 3 : 9 ?

:?

From the meeting place( place where John and Mary passed each other); John takes another 3 minutes to reach Point B [Given in part (b) of question]

Mary takes 9 minutes to reach the meeting place from Point B [we worked this out in part (a)]

For the same distance (meeting place to Point B or vice versa)
Time ratio of John : Mary = 3 : 9 = 1 : 3

1:3 is from mtg place to B, so it also means is the same ratio 1:3 from A to B ? so if total time for John is 12 min, this means 1u = 12 min, so for Mary, 3u = 12 x 3 = 36 min ?[/quote]Yes.

[Herbie]

Hi dharma. 340 failed the test

[Vanilla Cake]

Herbie:

Hi! I hv one qn.

4800 children registered to take part in a fitness test. 3/5 of the children were boxs. On the actual day of the fitness test, some boys did not turn up. Hence the % of the boys who actually took the test was 40% of the total no of children present tat day. At the end of the fitness test the no of girls who pasSed was 20% more than the no of boys who passed. 340 children the testHow many boys turned up for test

Herbie:

How many girls passed the test?
tx

Herbie:

Hi dharma. 340 failed the test

Hi Herbie,
While waiting for Dharma's reply,pls refer to DD2's working and pls don't laugh at her if she gets it wrong as she is only P5.


Actual
B: 1280
G: 1920

Passed test
B: 100%
G: 120%

1280+1920-340=2860
220% -> 2860
120% -> 1560

(a)Number of boys who turned up for test=1280
(b)Number of girls who passed the test =1560

VC's mum

PS: Honestly speaking, it took me a while to understand DD2's workings and I have to edit 2 times for this post due to typing errors because of my carelessness in following her workings.
:stupid:

[YLH88]

Hi Dharma,


Thank you!

[Dharma]

Herbie:

Hi dharma. 340 failed the test

Thanks Herbie.

Boys registered = 3/5 x 4800 = 2880 (60%)
Girls registered = 2/5 x 4800 = 1920 (40%)

% girls took test => 60%
60% => 1920
100% => 3200

No. of boys took test = 3200 – 1920 = 1280
No. of children who passed:
Boys : 5u
Girls : 6u

11u => 3200 – 340 = 2860
1u = 260

No. of girls who passed the test = 6u = 6 x 260 = 1560