Logo
    • Education
      • Pre-School
      • Primary Schools Directory
      • Primary Schools Articles
      • P1 Registration
      • DSA
      • PSLE
      • Secondary
      • Tertiary
      • Special Needs
    • Lifestyle
      • Well-being
    • Activities
      • Events
    • Enrichment & Services
      • Find A Service Provider
      • Enrichment Articles
      • Enrichment Services
      • Tuition Centre/Private Tutor
      • Infant Care/ Childcare / Student Care Centre
      • Kindergarten/Preschool
      • Private Institutions and International Schools
      • Special Needs
      • Indoor & Outdoor Playgrounds
      • Paediatrics
      • Neonatal Care
    • Forum
    • ASKQ
    • Register
    • Login

    Q&A - PSLE Science

    Scheduled Pinned Locked Moved Primary 6 & PSLE
    2.9k Posts 529 Posters 1.5m Views 1 Watching
    Loading More Posts
    • Oldest to Newest
    • Newest to Oldest
    • Most Votes
    Reply
    • Reply as topic
    Log in to reply
    This topic has been deleted. Only users with topic management privileges can see it.
    • M Offline
      Mathmaniac
      last edited by

      fristrom:

      This is the part I am having trouble with. Assuming the two balls A and B:

      - the balls have the same mass
      - collision is elastic

      Before collision:
      A -> <- B

      After collision:
      <A>

      The balls should just change direction without changing the speed, as speed a scalar quantity... my answer would be (1)
      I don't understand why the speed can remain the same? :?

      1 Reply Last reply Reply Quote 0
      • F Offline
        fristrom
        last edited by

        Mathmaniac:
        The balls should just change direction without changing the speed, as speed a scalar quantity... my answer would be (1)




        I don't understand why the speed can remain the same? :?


        For the two balls A, B:
        KE_before = 0.5 (mass_A) (velocity_A)^2 + 0.5 (mass_B) (velocity_B)^2

        assuming elastic collision,
        KE_before = KE_after = 0.5 (mass_A) (velocity_A)^2 + 0.5 (mass_B) (velocity_B)^2

        since mass of ball would not change due to collision, then, (velocity_A)^2 and (velocity_B)^2 would be the same before and after collision.

        Velocity is a vector. With a change in direction, the sign would be changed before and after collision, but squaring it means the sign is immaterial.

        Speed is scalar. As it has no sign, then, the numerical value should be unchanged.

        It has been a long time since I do physics so my reasoning may not make much sense. I am not even sure at primary level, speed and velocity is the same thing...

        1 Reply Last reply Reply Quote 0
        • M Offline
          meimeitan
          last edited by

          It becomes complicated. Anyone can draw to the conclusion? :?

          1 Reply Last reply Reply Quote 0
          • M Offline
            Muffins
            last edited by

            meimeitan:
            Hi


            never mind lah! U wear glasses so that u can solve more problems for me. Ha ha ha..... See! one more to come......

            Some children are playing a game with two tennis balls. Each child rolls the tennis balls along the floor so that they collide. Which statement(s) is/are the effect of the force on the ball observed from the above activity?

            (a) the ball stops moving.
            (b) the shape of the ball is changed
            (c) the speed of the ball is changed
            (d) the direction of the ball is changed

            (1) d only
            (2) a and c only
            (3) c and d only
            (4) a, c and d only

            Anyone who wears glasses also can pitch in to help. Thanks. :lol:
            Hi from what I've learnt, the answer would be 3.

            1 Reply Last reply Reply Quote 0
            • M Offline
              Muffins
              last edited by

              tianzhu:
              meimeitan:

              Hi! TianZhu and Starlight1968sg


              Thanks for previous explanation. However, i quite confuse about the term of gravitational force. If a man lying on the ground, there should be no gravitational force acting on him. But, how come i cannot lying on the ground when i am on the moon. As i dun hv clear concept, then i dun know how to answer the following question.

              Which of the following object(s) do(es) not have any gravitational force acting on it?

              (a) a bird flying in the sky
              (b) a man lying on the floor
              (c) a balloon rising into the air

              Hi meimeitan

              In PSLE science, students learned that gravity pulls all objects towards the Earth. Gravity is acting on you all the time. Even when you are standing still or lying on the ground, gravity still pulls you downwards. Without gravity, you would be floating in the air.

              Yes, gravity or gravitational forces have effect on the three cases you mentioned.

              Here a video, this may be some help to you.
              http://www.cosmolearning.com/video-lectures/physics-in-primary-schools-forces-gravity-7090/

              Best wishes

              :offtopic: :congrats: on your GMI!!!!!!

              When you upgraded yourself, I upgraded myself :lol: :rotflmao:

              1 Reply Last reply Reply Quote 0
              • T Offline
                tianzhu
                last edited by

                Muffins:


                :offtopic: :congratss: on your GMI!!!!!!

                When you upgraded yourself, I upgraded myself :lol: :rotflmao:
                Hi Muffins

                Thank you.

                Best wishes

                1 Reply Last reply Reply Quote 0
                • M Offline
                  Mathmaniac
                  last edited by

                  fristrom:
                  Mathmaniac:

                  The balls should just change direction without changing the speed, as speed a scalar quantity... my answer would be (1)




                  I don't understand why the speed can remain the same? :?



                  For the two balls A, B:
                  KE_before = 0.5 (mass_A) (velocity_A)^2 + 0.5 (mass_B) (velocity_B)^2

                  assuming elastic collision,
                  KE_before = KE_after = 0.5 (mass_A) (velocity_A)^2 + 0.5 (mass_B) (velocity_B)^2

                  since mass of ball would not change due to collision, then, (velocity_A)^2 and (velocity_B)^2 would be the same before and after collision.

                  Velocity is a vector. With a change in direction, the sign would be changed before and after collision, but squaring it means the sign is immaterial.

                  Speed is scalar. As it has no sign, then, the numerical value should be unchanged.

                  It has been a long time since I do physics so my reasoning may not make much sense. I am not even sure at primary level, speed and velocity is the same thing...

                  While it is true about what you said regarding elastic collision, it is irrelevant here, especially in primary school context.

                  1 Reply Last reply Reply Quote 0
                  • M Offline
                    meimeitan
                    last edited by

                    Hi


                    Actually I always feel warm as some of the families cannot afford to hire any tutors or join those famous or popular tution centres, here is the place where we can get help. Really, thanks a lot.

                    1 Reply Last reply Reply Quote 0
                    • A Offline
                      atutor2001
                      last edited by

                      meimeitan:
                      Hi


                      Actually I always feel warm as some of the families cannot afford to hire any tutors or join those famous or popular tution centres, here is the place where we can get help. Really, thanks a lot.
                      Actually the answers we are getting here are equal if not better than top tuition centres - especially for mathematics.

                      1 Reply Last reply Reply Quote 0
                      • M Offline
                        meimeitan
                        last edited by

                        Hi! Please help,


                        (A) Which of the following are possible reasons why aquatic plants and
                        animals cannot survive in a pond that contains mud particles?

                        a The water carries diseases.
                        b Sunlight cannot reach the aquatic plants
                        c The aquatic animals cannot get enough dissolved oxygen.
                        d There is not enough clean water for the aquatic plants and animals.

                        (1) a and c only
                        (2) b and c only
                        (3) b, c and d only
                        (4) a, b, c and d

                        (B) The population of bullfrogs near a pond. The number of bullfrogs
                        incresed in the first few weeks. However, it stopped increasing the
                        following weeks. Which of the following events are possible causes
                        for the change in the population of bullfrogs from point A to point B?

                        a a great drop in the water level of the pond
                        b A great decrease in the number of fish in the pond
                        c A great decrease in the number of dragonfly nymphs in the pond
                        d A great decrease in the number of diseaseinfecting organisms that
                        kill the prey of the bullfrogs

                        (1) a and c only
                        (2) b and d only
                        (3) a, c and d only
                        (4) b, c and d only

                        Thanks.

                        1 Reply Last reply Reply Quote 0

                        Hello! It looks like you're interested in this conversation, but you don't have an account yet.

                        Getting fed up of having to scroll through the same posts each visit? When you register for an account, you'll always come back to exactly where you were before, and choose to be notified of new replies (either via email, or push notification). You'll also be able to save bookmarks and upvote posts to show your appreciation to other community members.

                        With your input, this post could be even better šŸ’—

                        Register Login
                        • 1
                        • 2
                        • 82
                        • 83
                        • 84
                        • 85
                        • 86
                        • 288
                        • 289
                        • 84 / 289
                        • First post
                          Last post



                        Online Users

                        Statistics

                        4

                        Online

                        210.8k

                        Users

                        34.2k

                        Topics

                        1.8m

                        Posts
                        Popular Topics
                        New to the KiasuParents forum? Tips and Tricks!
                        Choosing and Evaluating Primary Schools
                        DSA 2026
                        PSLE Discussions and Strategies
                        How much do you spend on the kids' tuition/enrichments?
                        SkillsFuture + anything related to upskilling/learning something new!

                          About Us Contact Us forum Terms of Service Privacy Policy