Tutor MathsGuru: Ask me for your burning Maths questions!

[tinasen]

Dear Maths Guru,


I badly need help to solve this homework problem for my son.

A basket with 65 sweets has a mass of 3200g. The same basket with 40 sweets has a mass of 2125g. Each sweet has the same mass. What is the mass of the basket.

Your help is greatly appreciated.
Thanks
Tinasen

[Eddow]

basket + 65 sweets = 3200

basket _ 40 sweets = 2125

So if you take 3200- 2125 = 1075, the result will be for the 25 sweets
then, 1 sweet will be 1075 divide by 25 = 43g

take 43 x 40 sweets =1720g
2125 - 1720 = 405g (mass of basket)

[tinasen]

Eddow:

Hi Eddow,

Just a doubt. Doesn't 1720g include the basket mass as well.

- tinasen

basket + 65 sweets = 3200
basket _ 40 sweets = 2125

So if you take 3200- 2125 = 1075, the result will be for the 25 sweets
then, 1 sweet will be 1075 divide by 25 = 43g

take 43 x 40 sweets =1720g
2125 - 1720 = 405g (mass of basket)

[tinasen]

Sorry… Haven’t used the forum so started this as new topic instead of posting it in this forum. Now have re-posted my question here. Sorry for the inconvenience.


Dear Maths Guru,

I badly need help to solve this homework problem for my son.

A basket with 65 sweets has a mass of 3200g. The same basket with 40 sweets has a mass of 2125g. Each sweet has the same mass. What is the mass of the basket.

Your help is greatly appreciated.
Thanks
Tinasen

[Brenda10]

tinasen:

Sorry.. Haven't used the forum so started this as new topic instead of posting it in this forum. Now have re-posted my question here. Sorry for the inconvenience.


Dear Maths Guru,

I badly need help to solve this homework problem for my son.

A basket with 65 sweets has a mass of 3200g. The same basket with 40 sweets has a mass of 2125g. Each sweet has the same mass. What is the mass of the basket.

Your help is greatly appreciated.
Thanks
Tinasen

Hi, I'm not mathsguru but hope the following working can help:

3200g - 2125g = 1075g (To find out the mass of 25 sweets)
1075g / 25 = 43g (Mass of one sweet)
2125g - (40 x 43g) = 405g

Hence, the mass of the basket is 405g.

[tinasen]

Hi Brenda10, Eddow

Thanks for your help at this hour.
I got it now.
-Tinasen

Brenda10:

tinasen:

Sorry.. Haven't used the forum so started this as new topic instead of posting it in this forum. Now have re-posted my question here. Sorry for the inconvenience.

Dear Maths Guru,

I badly need help to solve this homework problem for my son.

A basket with 65 sweets has a mass of 3200g. The same basket with 40 sweets has a mass of 2125g. Each sweet has the same mass. What is the mass of the basket.

Your help is greatly appreciated.
Thanks
Tinasen

Hi, I'm not mathsguru but hope the following working can help:

3200g - 2125g = 1075g (To find out the mass of 25 sweets)
1075g / 25 = 43g (Mass of one sweet)
2125g - (40 x 43g) = 405g

Hence, the mass of the basket is 405g.

[tinasen]

I got it. Thank you Eddow.

Eddow:

basket + 65 sweets = 3200
basket _ 40 sweets = 2125

So if you take 3200- 2125 = 1075, the result will be for the 25 sweets
then, 1 sweet will be 1075 divide by 25 = 43g

take 43 x 40 sweets =1720g
2125 - 1720 = 405g (mass of basket)

[lin_bb2000.021981yahoo.021981com.021981sg]

Dear Maths Guru-

Have been finding help all over but i cannot solve this. Can you please help?

:? Amelia, Beatrice and Casey had $738 at first. After Amelia gave 3/8 of her money to Beatrice, Beatrice found that she had $18 less than Amelia. If Casey had 7/10 of what Amelia had left, how much did Beatrice have at first?

[iFruit]

LL:

Dear Maths Guru-

Have been finding help all over but i cannot solve this. Can you please help?

:? Amelia, Beatrice and Casey had $738 at first. After Amelia gave 3/8 of her money to Beatrice, Beatrice found that she had $18 less than Amelia. If Casey had 7/10 of what Amelia had left, how much did Beatrice have at first?

Assume at the end, Amelia = 10u.

Then Casey = 7u, Beatrice = 10u -18

10u + 7u + 10u - 18 = 738

27u = 756---> u = 28

So Amelia at the end = 10u = 280

Beatrice at the beginning = 280 - 3/8 x 448 -18 = 280 - 168 - 18 = 94

HTH.

[Yu Xuan]

LL:

Dear Maths Guru-

Have been finding help all over but i cannot solve this. Can you please help?

:? Amelia, Beatrice and Casey had $738 at first. After Amelia gave 3/8 of her money to Beatrice, Beatrice found that she had $18 less than Amelia. If Casey had 7/10 of what Amelia had left, how much did Beatrice have at first?

Not a guru, but this is my solution;

At first
Amelia --> 16 units

After transfering 3/8 to Beatrice
Amelia --> 16u - 6u = 10u
Beatrice --> 10u - 18
Casey --> 7/10 * 10u = 7u

Working backward, Beatrice started off with;
10u - 18 - 6u --> 4u - 18

10u + 10u + 7u --> 738 + 18
1u --> 756 / 27 = 28

Beatrice at first --> 4*28 - 18 = $94

Is that the answer?