Tutor MathsGuru: Ask me for your burning Maths questions!
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Thks in advance for your worked solutions.Much appreciated.

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Thks in advance for your worked solutions.Much appreciated.

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Thks in advance for your worked solutions.Much appreciated.

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Thks in advance for your worked solutions.Much appreciated.

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Vanilla Cake:
Q5http://postimage.org/image/2o8g5qe2s/

1/2 x AD x BC = 1/2 x BE x AC
AD = 20 x 18/ 24 = 15
x = 15cm -
Vanilla Cake:
Q7http://postimage.org/image/34icnb0mc/

Name the columns A,B,C and D from left to right and the rows 1,2, 3 and 4 from top to bottom.
Notice the pattern below :
C3 = C4 + D4 + D3
5 = 1 + 3 + 5
B2 = B3 + C3 + C2 = 7 + 5 + 7 = 19
Check
A1 = A2 + B2 + B1 = 35 + 19 + 35 = 89 - OK
x = 19 -
verykiasumummy:
Hihi everyone here...
i was reading this thread and i was totally amazed! really...!!
i always hv challenging maths questions from my boy... he always accumulate it to ask his tutor who only has lessons with him once a week due to limited slots...
it'll be so helpful if i could get solutions here n try to explain to him..
1]. At first, Tom had 2/3 as many stickers as Edward. After Tom bought another 8 stickers and Edward lost 5, Tom had 4/5 as many stickers as Edward. Find the number of stickers Tom had at first.
2]. There are 200 people in a party. What is the minimum number of people whose birthday fall in the same month?
3]. What is the largest 5-digit number which is a multiple of 2, 3 and 5? How many 5-digit numbers are there which are multiples of 2, 3 and 5?
Thanks in advance.
http://postimage.org/image/34ur6epyc/
Q2.
200/12 = 16R8, so at least 16 people had birthday in the same month.
Q3.
LCM of (2,3,5) = 30
Range of 5-digit number : 10000 to 99999
Smallest multiple of 30 = 10020, and largest = 99990
10020/30 = 334, 99990/30 = 3333
Number of multiples of 30 from 10020 to 99990 = 3333-334+1 = 3000
cheers.
cheers. -
Vanilla Cake:
Q8http://postimage.org/image/1yp7bb24k/
Thks in advance for your worked solutions.Much appreciated.

Since n1, n2, n3,β¦., n8 and n9 are consecutive numbers
(n β 4) + (n -3 ) + β¦ + n + (n + 1) + β¦ + (n + 4 ) = 9
9n = 9
n = 1
n5 = n
n4 = n -1 = 1 -1 = 0
n1 x n2 x β¦ x n8 x n9 = 0 -
Vanilla Cake:
http://postimage.org/image/10w36l1gk/
Thks in advance for your worked solutions.Much appreciated.

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Hi Vanilla Cake
http://postimage.org/image/12kl9d3tw/
N = (2x5)^2000x2^9 = 512 x 10^2000 >>> 2003 digits
cheers.
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