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[MathIzzzFun]

tinasen:

I think the confusion I had earlier was about how to compare 5/7 and less by 45.

Thank you very much! Now I understand.
Your clear illustration is worth a million words.

MathIzzzFun:

[quote=\"tinasen\"]Any help to solve this homework problem through model method is much appreciated!

Mrs Tay baked some cookies. She gave 5/7 of them to her mother and 45 fewer cookies to her neighbour than what her mother received. If she had 15 cookies left, how many cookies she give to her neighbour?

- Many Thanks
Tina

Hi


http://postimage.org/image/yas6c5dw/

cheers.

[/quote]Hi tinasen

glad to be of help :lol:

cheers.

[imacsg]

Sandra had twice as many apples as oranges at first. She removed 4 apples and 3 oranges each time. In the end, there were 18 apples and 1 orange left. How many fruits did Sandra have at first?


[3][3]…[3][1][1+2][1+2]…[1+2][1] apples
[3][3]…[3][1] oranges
<1u>

number of groups –> (18 - 2)/2 = 8

1u –> 8 x 3 + 1 = 25
Sandra had 3 x 25 = 75 fruits at first.

Thanks for your prompt reply. But I do not understand. Can you help to explain or any one can help to explain. Thanks.

[MathIzzzFun]

imacsg:

Sandra had twice as many apples as oranges at first. She removed 4 apples and 3 oranges each time. In the end, there were 18 apples and 1 orange left. How many fruits did Sandra have at first?


[3][3]....[3][1][1+2][1+2]...[1+2][1] apples
[3][3]....[3][1] oranges
<____1u____>

number of groups --> (18 - 2)/2 = 8

1u --> 8 x 3 + 1 = 25
Sandra had 3 x 25 = 75 fruits at first.

Thanks for your prompt reply. But I do not understand. Can you help to explain or any one can help to explain. Thanks.

Hi

hope this helps.


http://postimage.org/image/nlwj5pms/

cheers.

[jieheng]

imacsg:

Can anyone help me on the below question.


Sandra had twice as many apples as oranges at first. She removed 4 apples and 3 oranges each time. In the end, there were 18 apples and 1 orange left. How many fruits did Sandra have at first?

Thanks.

A [-------][-------]

0 [-------]

She removed 4 apples and 3 oranges each time , so the ratio of the apples to be removed to the ratio of the oranges to be removed is 4 : 3 until there were 18 apples and 1 orange left

A [][][][][---18---] (4u+18)

O [][][][1] (3u+1)

Given Sandra had twice as many apples as oranges at first ,

A [][][][1][][][][1] (6u+2)

Compare the models of A ,

6u+2 -----> 4U+18
2u -----> 16
1u -----> 8

At first , number of fruits that Sandra had = (4u+1 8) + (3u+1) = 7u+19 = 7*8 + 19 = 75 (Ans)

[imacsg]

Thanks MathIzzzFun and jieheng for your help. Now I understand.

[jieheng]

imacsg:

Thanks MathIzzzFun and jieheng for your help. Now I understand.

Hi imacsg ,

You are welcome.

Regards,

[MathIzzzFun]

imacsg:

Thanks MathIzzzFun and jieheng for your help. Now I understand.

Hi imacsg

glad to be of help :lol:

cheers.

[mummyoftwo]

Hi need help on these 3 Fractions problem sum, can someone help?


1. James spent 1/5 of his money on shoes. John Spent 3/4 of his money on bag and had $25 left. If John had half of what James had in the beginning, how much is hte cost of James’ shoes?

2. Jane ate 1/6 of the cookies. Mary are 2/3 of the cookies and had 10 cookies left. If Jane had thrice of what Sally had in the beginning, how many cookies did Sally ate?

3. Thed spent 3/8 of his money on books. Tony spent 1/2 of his money on magazine and had $15 left. If Tony Tony had half of what Thed had in the beginning, how much did Thed spend on his books?

Thank you in advance.

[jieheng]

mummyoftwo:

Hi need help on these 3 Fractions problem sum, can someone help?


1. James spent 1/5 of his money on shoes. John Spent 3/4 of his money on bag and had $25 left. If John had half of what James had in the beginning, how much is hte cost of James' shoes?

James [------10u------]

..John [--5u--]


Since 5u is not divisible by 4 , we have to change the unit of John to 20u (5u*4) and James to 40u (10u*4)


James [-------40u-------]

..John [--20u--]


James [-8u--][-8u--][-8u--][8u--][-8u--]

..John [5u][5u][5u][5u]


5u -----> 25
1u -----> 5

the cost of Jame's shoes = 8u = 8 * 5 = $40 (Ans)

[jieheng]

mummyoftwo:

Hi need help on these 3 Fractions problem sum, can someone help?


2. Jane ate 1/6 of the cookies. Mary are 2/3 of the cookies and had 10 cookies left. If Jane had thrice of what Sally had in the beginning, how many cookies did Sally ate?

J [---6u--][---6u--][---6u--]

S [---6u--]


J [---------15u---------][3u]

S [2u][4u]

2u -----> 10
1u -----> 5

The number of cookies that Sally ate = 4u = 4 * 5 = 20 (Ans)

the number of cookies that Jane ate = 3u = 3 * 5 = 15