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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • Suz855S Offline
      Suz855
      last edited by

      Moderator's Note: Please use this thread to ask for help on specific questions. Please refrain from out of topic chatter in this thread to make it easier for the community to find the answers they need.


      Pls help, thanks


      http://i937.photobucket.com/albums/ad214/suz855/areaoftriangle-1.gif\">

      :?

      1 Reply Last reply Reply Quote 0
      • V Offline
        Vanilla Cake
        last edited by

        Suz855:
        Pls help, thanks


        http://i937.photobucket.com/albums/ad214/suz855/areaoftriangle-1.gif\">

        :?
        There is missing information as you don't see the letters R and S of the triangle in the picture. Most likely, it was erased away with the letters R and S unintentionally and the important information that base of the triangle PRS has the measurement of 9 cm ie RS = 9 cm.

        With this important information that RS = 9 cm, here's the solution:

        Area of ΔPRS = ½x(12+4)x9= 72 cm²
        (a) Area of shaded part = 72/8x7 = 63 cm²

        Area of rectangle = (129+63) cm² = 192 cm²
        Length of rectangle = 192÷12=16 cm
        12/16x100% = 75%
        (b) Breadth of the rectangle as a percentage of the length of the rectangle = 75%

        Mods: Pls merge this post with http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&start=2030.
        Thks.

        1 Reply Last reply Reply Quote 0
        • Suz855S Offline
          Suz855
          last edited by

          Thanks VC,


          I was thinking along using the ratio given.

          Since the shaded part is 7 and given that area of the triangle is 8, the unshaded triangle at the tip will be 1 vs the complete triange as 8.

          Taking the height of whole triangle as 16 and the height of the unshaded triangle as 4, the base of the triangle should have the ratio of 1 : 2 which will bring us to area of triange as 32 or 64cm2 and the shaded portion as 28 or 56cm2.....

          However probably you are right that the base of 9cm might already been given thus making this a simple area of triangle question instead of a more challenging one 😄

          1 Reply Last reply Reply Quote 0
          • C Offline
            ck123
            last edited by

            Hi anyone


            Please help with the following questions:

            1) Zara had 70 more dresses than skirts. She sold 3/4 of the dresses and 3/5 of the skirts. She sold 126 more dresses than skirts. What fraction of the remaining clothes that Zara had were skirts?

            2) A seamstress had some white and some black buttons. 60% of the buttons were white. He bought another 120 buttons. Now, the percentage of white buttons became only 40% of the total. How many white buttons did he have at first?

            Thanks a lot... :?:

            [/img][/list]

            1 Reply Last reply Reply Quote 0
            • B Offline
              Brenda10
              last edited by

              ck123:
              Hi anyone


              Please help with the following questions:

              2) A seamstress had some white and some black buttons. 60% of the buttons were white. He bought another 120 buttons. Now, the percentage of white buttons became only 40% of the total. How many white buttons did he have at first?

              Thanks a lot... :?:

              [/img][/list]
              Hi, dd working for Q2)

              W:B
              3:2 (Before)
              Plus 120
              4:6 (After)

              4-3=1
              6-2=4
              1+4=5
              120/5=24
              24*3= 72

              There are 72 white marbles at frist.

              Thank you.

              1 Reply Last reply Reply Quote 0
              • B Offline
                Brenda10
                last edited by

                ck123:
                Hi anyone


                Please help with the following questions:

                1) Zara had 70 more dresses than skirts. She sold 3/4 of the dresses and 3/5 of the skirts. She sold 126 more dresses than skirts. What fraction of the remaining clothes that Zara had were skirts?Thanks a lot... :?:

                [/img][/list]
                Hi, you may refer the following link for solution.

                http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=6373&postdays=0&postorder=asc&start=2880

                1 Reply Last reply Reply Quote 0
                • I Offline
                  iFruit
                  last edited by

                  ck123:
                  Hi anyone


                  Please help with the following questions:

                  2) A seamstress had some white and some black buttons. 60% of the buttons were white. He bought another 120 buttons. Now, the percentage of white buttons became only 40% of the total. How many white buttons did he have at first?

                  Thanks a lot... :?:

                  [/img][/list]
                  I think this is question is incomplete. There can be many solutions as it is.

                  1 Reply Last reply Reply Quote 0
                  • C Offline
                    ck123
                    last edited by

                    A big Thank You to all. :celebrate:


                    How can i insert a picture for a question to ask?

                    Thanks[/img]

                    1 Reply Last reply Reply Quote 0
                    • G Offline
                      greenfinger
                      last edited by

                      Hi ,anyone can help me, pls



                      question:

                      A wheel made 72 revolutions.It has a radius of 23 cm.How far did it travel? :?

                      1 Reply Last reply Reply Quote 0
                      • J Offline
                        jieheng
                        last edited by

                        greenfinger:
                        Hi ,anyone can help me, pls



                        question:

                        A wheel made 72 revolutions.It has a radius of 23 cm.How far did it travel? :?
                        The distance it travelled = No. of revolutions * Circumference = No. of revolutions * Pi * Diameter = 72 * 3.14 * ( 2 * 23 ) = 10400 cm (Ans)

                        1 Reply Last reply Reply Quote 0

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