Q&A - PSLE Math

[shurley197323]

Hi.jieheng. can I check with you another q.

Jane had 9/10m of ribbon. She used 4/5kg of it to tie 2 identical parcels
(a) how many cm of ribbons did jane use to tie 1 parcel.
(b) What fraction of ribbon was left?

Can use the same method as the last q?
The method I use is ( 9/10 x 4/5) / 2.
Thanks

[jieheng]

shurley197323:

Hi.jieheng. can I check with you another q.

Jane had 9/10m of ribbon. She used 4/5kg of it to tie 2 identical parcels
(a) how many cm of ribbons did jane use to tie 1 parcel.
(b) What fraction of ribbon was left?

Can use the same method as the last q?
The method I use is ( 9/10 x 4/5) / 2.
Thanks

Jane had 9/10m of ribbon. She used 4/5kg of it to tie 2 identical parcels

Yes , you can . (I assume there is no unit after 4/5 in the question )

[shurley197323]

jieheng:

shurley197323:

Hi.jieheng. can I check with you another q.

Jane had 9/10m of ribbon. She used 4/5kg of it to tie 2 identical parcels
(a) how many cm of ribbons did jane use to tie 1 parcel.
(b) What fraction of ribbon was left?

Can use the same method as the last q?
The method I use is ( 9/10 x 4/5) / 2.
Thanks

Jane had 9/10m of ribbon. She used 4/5kg of it to tie 2 identical parcels

Yes , you can . (I assume there is no unit after 4/5 in the question )

Yes.should be 4/5 only. Can show me the steps? My gal said cannot bcos different methods.

[jieheng]

shurley197323:

jieheng:

[quote=\"shurley197323\"]Hi.jieheng. can I check with you another q.

Jane had 9/10m of ribbon. She used 4/5kg of it to tie 2 identical parcels
(a) how many cm of ribbons did jane use to tie 1 parcel.
(b) What fraction of ribbon was left?

Can use the same method as the last q?
The method I use is ( 9/10 x 4/5) / 2.
Thanks

Jane had 9/10m of ribbon. She used 4/5kg of it to tie 2 identical parcels

Yes , you can . (I assume there is no unit after 4/5 in the question )

Yes.should be 4/5 only. Can show me the steps? My gal said cannot bcos different methods.[/quote]
a)

the length of ribbons that Jane used to tie 1 parcel = [(9/10)*(4/5)] / 2 = 9/25 m = (9/25)*100 = 36 cm (Ans)

b)

the original length of the ribbons = 9/10 m = 90 cm

the length of the ribbons that Jane used = 2*36 = 72 cm

the length of the ribbons that she left was = 90 - 72 = 18 cm

the fraction of ribbon was left = 18 / 90 = 1/5 (Ans)

[shurley197323]

Thanks a lot , jieheng.

[peggy]

Help is needed here!


P5 qtn :

Vernice had $1196 more than Ethan. If Vernice were to give 1/7 of her money to Ethan, she would have 4 times as much as Ethan. How much money did Ethan have?


Thanks.

[jieheng]

shurley197323:

Thanks a lot , jieheng.

Hi shurley197323 ,

You are welcome .

Regards,

[jieheng]

peggy:

Help is needed here!


P5 qtn :

Vernice had $1196 more than Ethan. If Vernice were to give 1/7 of her money to Ethan, she would have 4 times as much as Ethan. How much money did Ethan have?

Thanks.

V [---------------][---------------][---------------][---------------]

E [---------------]

Vernice left 6/7 if she were to give 1/7 to Ethan , change [---------------] to [-------6u-----]

V [-------6u-----][-------6u-----][-------6u-----][-------6u-----]

E [-------6u-----]

6/7 ------> 24u , so 1/7 -----> 4u

V [-------6u-----][-------6u-----][-------6u-----][-------6u-----]

E [2u-][---4u---]

Transferred back 4u from E to V

V [-------6u-----][-------6u-----][-------6u-----][-------6u-----][---4u---] (28u)

E [2u-]

Vernice had $1196 more than Ethan ,

(28u - 2u) -----> 1196
26u -----> 1196
1u -----> 46

the amount of money that Ethan had = 2u = 2*46 = $92 (Ans)

[peggy]

Hi Jieheng,


Thanks for the solution. A little confused as to why (--------) can change to (----6u—)??

Thanks.

[jieheng]

peggy:

Hi Jieheng,


Thanks for the solution. A little confused as to why (--------) can change to (----6u---)??

Thanks.

As Vernice left 6 / 7 , if we change [---------------] to [-------6u-----] or (any multiples of 6) , we are able to know how many units is (1/7) that Vernice gave to Ethan .

Regards,