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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • D
      Dharma
      last edited by

      tianzhu:
      Perhaps girls of 2008/9 RGPS would like to comment on the extra cube shown in the picture.


      My gut feeling is it's not there.
      You're right. It was hand-drawn (its the one at the top row - on the righthand side)

      Cube size - 2cm x 2cm x 2cm
      Height of container = 6cm

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      • D
        Dharma
        last edited by

        tianzhu:
        Other than Guess and Check, what are the other alternatives to solve this problem?


        Annie wrote her mother's age followed by her own age to form a 4-digit number.She used the difference between their ages to subtract from the 4-digit number. Then Annie obtained the number 4489.What was Annie's age ? (RGPS P6 Prelim 2008 Q47)
        The 4 digit number is ABCD ... AB is mother's age while CD is Annie's age.

        ABCD - (AB - CD) = 4489

        ABCD = (AB00 + CD) -( AB - CD) = 4489

        AB - CD > 10 .... AB = 45

        4500 - CD - 45 + CD = 4489
        2CD = 34
        CD = 17

        Annie's age = 17

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        • T
          Tang
          last edited by

          Dharma:
          Drdj:

          Hi there,


          Please help me with the following :

          NanHua Prelim 2008

          Qn 24
          15 cats can catch 15 rats in 15 minutes. How long does it take 60 cats to cath 60 rats? [Ans = 15 mins - how do you know which qty to stay constant/change]

          Thanks in advance šŸ™‚

          15 cats - 15 rats - 15 mins
          1 cat - 15 rats - 225 mins
          1 cat - 60 rats - 900 mins
          60 cats - 60 rats - 900/60 = 15 mins
          (Only change 1 independent variable at a time)

          15 cats 15 rats 15 min
          1 cat 1 rat also 15 min
          Hence 60 cats 60 rats also 15 min

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          • T
            Tang
            last edited by

            Tang:
            Dharma:

            [quote=\"Drdj\"]Hi there,


            Please help me with the following :

            NanHua Prelim 2008

            Qn 24
            15 cats can catch 15 rats in 15 minutes. How long does it take 60 cats to cath 60 rats? [Ans = 15 mins - how do you know which qty to stay constant/change]

            Thanks in advance šŸ™‚

            15 cats - 15 rats - 15 mins
            1 cat - 15 rats - 225 mins
            1 cat - 60 rats - 900 mins
            60 cats - 60 rats - 900/60 = 15 mins
            (Only change 1 independent variable at a time)

            15 cats 15 rats 15 min
            1 cat 1 rat also 15 min
            Hence 60 cats 60 rats also 15 min[/quote]15 cats 15 min

            60 cats, the number of min will be less (Multiply by 15/60 - Original number of cats / New number of cats).
            60 rats, the number of min will be more, since more rats to catch (Multiply by 60/15 - New number of rats / Original number of rats)

            So 60 cats to catch 60 rats will require 15 x 15/60 x 60/15 = 15 min.

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            • D
              Dharma
              last edited by

              Drdj:
              Hi there,


              Please help me with the following :

              Misc
              David paints once every 2 days. Larry paints once every 3 days.
              If the 2 men met on 28th May, what is the earliest date David has to start work? [Answer = 24th May]

              Thanks in advance šŸ™‚
              The underlying assumption is both David and Larry met for the 1st time on 28 May.

              If the assumption is not true, they would have met 6 days before i.e. on 22 May (LCM of 2 and 3)

              Since the assumption holds, then the earliest David starts work is on 24 May (2 days after 22 May)

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              • A
                Andaiz
                last edited by

                Drdj:
                Hi there,


                Please help me with the following :

                Misc
                David paints once every 2 days. Larry paints once every 3 days.
                If the 2 men met on 28th May, what is the earliest date David has to start work? [Answer = 24th May]

                Thanks in advance šŸ™‚
                I would have assumed too that they've met for the first time on 28th May.
                Larry would have worked on 28-3 i.e. 25th; and 25-3 i.e., 22nd.

                With David painting every 2 days, he'd have worked 28th, 26th, or 24th or 22nd.

                If they have never met previously, David's earliest date he could have started work is 24th.

                We used to do the LCM way but now its modelling eh? I'd try with the number line


                David 22_________ 24 _______26___________28
                Larry 22_______________25_______________ 28

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                • E
                  enoawng
                  last edited by

                  tianzhu:
                  Thank you for your help.


                  RGPS SA2 2008 Q43.


                  http://www.postimage.org/
                  3 plane of waters
                  1st plane has 1 cube
                  2nd plane has 3 cubes
                  3rd plane has 6 cubes and 352cm3

                  2xtimes third plane = 768cm3 + 4 cubes
                  12cubes + 2x352cm3 is the same as 768cm3 + 4 cubes

                  8 cubes = 64cm3
                  1 cube = 2x2x2cm = 8 cm3

                  Hence height of cube = 2cm ; height of tray = 6cm

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                  • T
                    Tang
                    last edited by

                    [Moderator's note: Topics merged.]


                    Can't recall if I have posted Uncle Observer's Blog on P6 Maths Questions here previously.

                    http://prischoolmaths.blogspot.com/


                    Anyway the answers have been released and you may want to check.


                    http://prischoolmaths.blogspot.com/2009/07/maths-volume_18.html

                    http://prischoolmaths.blogspot.com/2009/07/maths-percentage_2485.html

                    http://prischoolmaths.blogspot.com/2009/07/maths-percentage_4168.html

                    http://prischoolmaths.blogspot.com/2009/07/maths-percentage_17.html

                    http://prischoolmaths.blogspot.com/2009/07/maths-whole-number_16.html

                    http://prischoolmaths.blogspot.com/2009/07/maths-whole-number_18.html

                    http://prischoolmaths.blogspot.com/2009/07/maths-fraction_19.html

                    http://prischoolmaths.blogspot.com/2009/07/maths-fraction.html

                    http://prischoolmaths.blogspot.com/2009/07/maths-rates.html

                    http://prischoolmaths.blogspot.com/2009/07/maths-speed_22.html

                    http://prischoolmaths.blogspot.com/2009/07/maths-speed_18.html

                    http://prischoolmaths.blogspot.com/2009/07/maths-average.html

                    http://prischoolmaths.blogspot.com/2009/07/maths-circles.html

                    http://prischoolmaths.blogspot.com/2008/11/maths-challenging_01.html

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                    • N
                      N3SKiasu
                      last edited by

                      Hi I have one Maths question but the answer kit used Algebra to solve, hence wld like to kw if anyone cld help with using Models.


                      Mr Tan had some apples and oranges in his shop. 30% of the fruits were oranges. He sold 70 apples and bought another 170 oranges. Then 65% of the fruits were oranges. How many apples did he have at first?

                      Thks in advance!

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                      • T
                        Tang
                        last edited by

                        N3SKiasu:
                        Hi I have one Maths question but the answer kit used Algebra to solve, hence wld like to kw if anyone cld help with using Models.


                        Mr Tan had some apples and oranges in his shop. 30% of the fruits were oranges. He sold 70 apples and bought another 170 oranges. Then 65% of the fruits were oranges. How many apples did he have at first?

                        Thks in advance!
                        After
                        -----
                        Oranges New -- 3 units + 170 (= 65% -- 13 small units)
                        Apples New -- 7 units - 70 (=35% -- 7 small units

                        Before
                        --------
                        Orange -- Draw 3 units
                        Apples -- Draw 7 units

                        Apples -- Shade out 10 in each of the 7 units (to represent 70 apples sold)
                        Orange -- Shade out 10 in each of the 3 units, then add 170 oranges. You get 3 small units + 3 x 10 + 170 = 13 small units

                        10 small units --> 3 x 10 + 170 = 200

                        1 small unit --> 200 / 10 = 20

                        Apples --> 20 x 7 + 70 = 210 apples.

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