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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      fsaith:
      Hi I would like to know the solution of this question. Thanks so much in advance!


      Siti has some dark chocolates and white chocolates in a container. If she eats 3 dark chocolates, the ratio of the number of dark chocolates to the number of white chocolates will become 5:4. If she eats 3 white chocolates, the ratio of the number of dark chocolates will then be 7:5. What is the original number of dark chocolates and white chocolates in the container?
      Hi

      This is variatiion to typical \"transfer\" problem.

      First, assume we start with situation after Siti has taken 3 dark chocolate ie initial = dark : white = 5 : 4. Then the situation of \"when Siti eats 3 white chocolate\" would become after exchanging 3 white chocolate for 3 dark chocolates, the ratio = 7:5

      So we have :

      initial, dark : white = 5 : 4 = 20u : 16u
      after, dark : white = 7 : 5 = 21u : 15u

      1u = 3
      Initial, dark: white = 20 u : 16u = 60:48

      need to add back the 3 dark chocolates

      There were 63 dark chocolates and 48 white chocolates at first.

      cheers.

      1 Reply Last reply Reply Quote 0
      • B Offline
        Brenda10
        last edited by

        tianzhu:
        Brenda10:


        Terry bought a vase which he decides to sell. If he sells thh vase at a discount of 20%, he makes a gain of $150. if he sells it at a 45% discount, he loses $325. How much did Terry pay for this vase?

        Hi Brenda10

        There are two scenarios in your question.

        The first one involves Terry selling at a discount of 20% from the usual price or marked price. In the second case, he sells at a discount of 45% from the usual price.

        When the selling price of the vase is less than the usual price or marked price of the vase, a discount on the item is given.

        The selling price of the vase in the two scenarios is different, only the usual price or marked price remains the same.

        I’ve problem uploading the images at this moment, I’ll do it at a later time.

        Best wishes

        Thank you Tianzhu and do take your time.

        1 Reply Last reply Reply Quote 0
        • T Offline
          tianzhu
          last edited by

          Brenda10:

          Thank you Tianzhu and do take your time.
          Hi Brenda10.

          Hope this helps.

          Best wishes.

          http://farm4.static.flickr.com/3325/5817158092_59fee6a1d8_z.jpg\">

          http://farm6.static.flickr.com/5064/5816591015_a98e4eb5a1_z.jpg\">

          1 Reply Last reply Reply Quote 0
          • F Offline
            fsaith
            last edited by

            [quote]Hi


            This is variatiion to typical \"transfer\" problem.

            First, assume we start with situation after Siti has taken 3 dark chocolate ie initial = dark : white = 5 : 4. Then the situation of \"when Siti eats 3 white chocolate\" would become after exchanging 3 white chocolate for 3 dark chocolates, the ratio = 7:5

            So we have :

            initial, dark : white = 5 : 4 = 20u : 16u
            after, dark : white = 7 : 5 = 21u : 15u

            1u = 3
            Initial, dark: white = 20 u : 16u = 60:48

            need to add back the 3 dark chocolates

            There were 63 dark chocolates and 48 white chocolates at first.

            cheers.[/quote]Thank you so much for your help!

            1 Reply Last reply Reply Quote 0
            • MathIzzzFunM Offline
              MathIzzzFun
              last edited by

              fsaith:
              [quote]Hi


              This is variatiion to typical \"transfer\" problem.

              First, assume we start with situation after Siti has taken 3 dark chocolate ie initial = dark : white = 5 : 4. Then the situation of \"when Siti eats 3 white chocolate\" would become after exchanging 3 white chocolate for 3 dark chocolates, the ratio = 7:5

              So we have :

              initial, dark : white = 5 : 4 = 20u : 16u
              after, dark : white = 7 : 5 = 21u : 15u

              1u = 3
              Initial, dark: white = 20 u : 16u = 60:48

              need to add back the 3 dark chocolates

              There were 63 dark chocolates and 48 white chocolates at first.

              cheers.
              Thank you so much for your help![/quote]u r welcome :lol:

              cheers.

              1 Reply Last reply Reply Quote 0
              • S Offline
                stary
                last edited by

                Dharma:
                If Charles continued driving after reaching the finishing line, he would have covered an additional 45km in the same time that Tony took to finish the race.


                Time taken by Charles to drive the additional 45km = 45km/(90km/h) = 0.5 hr
                Therefore, Charles finished the race (reached the finishing line) ½ hr earlier than Tony.[9.05 a.m.]


                Hi Dharma n ksi,

                Thanks for the solution. I got it. Tony will be 1/2 hrs faster than Charles, so Charles will reach finishing line at 9:35 + 1/2 hrs = 10:05 am

                CHEERS :dancing:

                1 Reply Last reply Reply Quote 0
                • B Offline
                  Brenda10
                  last edited by

                  tianzhu:
                  Brenda10:


                  Thank you Tianzhu and do take your time.

                  Hi Brenda10.

                  Hope this helps.

                  Best wishes.

                  http://farm4.static.flickr.com/3325/5817158092_59fee6a1d8_z.jpg\">

                  http://farm6.static.flickr.com/5064/5816591015_a98e4eb5a1_z.jpg\">

                  Hi Tianzhu

                  Thank you for your wonderful picture and explanation. DD said she can understand and also like the presentation. :lol:

                  1 Reply Last reply Reply Quote 0
                  • W Offline
                    WLRR
                    last edited by

                    Hello


                    Need help with the following question:

                    The total mass of Jane and Jacky is 101 kg and the total mass of Jacky and Jorine is 77 kg. Jane is twice as heavy as Jorine. What is the average mass of the three girls ?

                    1 Reply Last reply Reply Quote 0
                    • H Offline
                      Hifive
                      last edited by

                      Hi


                      Maths problem - pls help…

                      Terry and John went shopping with a total of $198. Terry had $10 more than John. Terry spent 25% as much money as John. After which, he had twice as much money as John.
                      a) How much money did Terry bring for shopping?
                      b) How much money had Terry left after shopping?

                      Kindly help. Thanks in advance!

                      1 Reply Last reply Reply Quote 0
                      • corneyAmberC Offline
                        corneyAmber
                        last edited by

                        WLRR:
                        Hello


                        Need help with the following question:

                        The total mass of Jane and Jacky is 101 kg and the total mass of Jacky and Jorine is 77 kg. Jane is twice as heavy as Jorine. What is the average mass of the three girls ?
                        http://i53.tinypic.com/qmys1w.jpg\">

                        1 Reply Last reply Reply Quote 0

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