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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      Superbugs:




      My dau got up to 3u : 15u : 25u and she got the difference at 12u. However, she has forgotten to express as a percentage.

      Thanks a lot for your solution. Really appreciate it.
      Hi

      u r welcome 😄

      cheers.

      1 Reply Last reply Reply Quote 0
      • S Offline
        Superbugs
        last edited by

        P5 Question:


        Before a game, Azmi and Peiqin had the same no. of pitcure cards. During the first round, Azmi lost 12 of his picture cards to Peiqin. During the second round, Peiqin won 16 picture cards from Azmi. In the end, Peiqin had 3 times as many picture cards as Azmi.

        a) How many more picture cards did Peiqin have in the end?
        b) How many pitcure cards did both of them have in all?

        a)
        Azmi= 1u
        Peiqin=3u+28

        2u=28
        1u=14
        3u+28=3x14+28=56 picture cards

        b) 4u+28=84 picture cards

        Part a) is correct but for part b) the answer sheet shows 112? Appreciate help on part b) pls. Tks

        1 Reply Last reply Reply Quote 0
        • S Offline
          Superbugs
          last edited by

          P5 question:

          Mr Tan had some oranges for sale. The first customer bought 1/2 of the oranges and received 8 oranges free. The second customer bought 45% of the remaining and received 5 free oranges free. The third customer bought 70% of the remaining oranges and received 3 oranges free. Mr Tan then had 1 dozen oranges left. How many oranges did he have at first?

          This is what I gathered from the question but I can’t solve it, pls help:
          1st Customer bought =1/2u+ 8 oranges
          Remaining =1/2u- 8 oranges
          2nd Customer bought = 45% of (1/2u-8 oranges)
          Remaining = 55% of (1/2u-8oranges)
          3rd Customer bought = 70% of 55% of (1/2u-8oranges)
          Remaining = 30% of 55% of (1/2u-8 oranges)= 12 oranges
          1u=16
          Pls help as I am unable to get d answer. Tks

          1 Reply Last reply Reply Quote 0
          • MathIzzzFunM Offline
            MathIzzzFun
            last edited by

            Superbugs:
            P5 question:

            Mr Tan had some oranges for sale. The first customer bought 1/2 of the oranges and received 8 oranges free. The second customer bought 45% of the remaining and received 5 free oranges free. The third customer bought 70% of the remaining oranges and received 3 oranges free. Mr Tan then had 1 dozen oranges left. How many oranges did he have at first?

            This is what I gathered from the question but I can't solve it, pls help:
            1st Customer bought =1/2u+ 8 oranges
            Remaining =1/2u- 8 oranges
            2nd Customer bought = 45% of (1/2u-8 oranges)
            Remaining = 55% of (1/2u-8oranges)
            3rd Customer bought = 70% of 55% of (1/2u-8oranges)
            Remaining = 30% of 55% of (1/2u-8 oranges)= 12 oranges
            1u=16
            Pls help as I am unable to get d answer. Tks

            Hi

            Work backwards to get to the initial number.

            Steps:
            Quantity Left ---- Quantity Bought
            Initial ---- 1st: ½ Initial + 8

            ½ initial–8=R1 ---- 2nd : 45% of R1 + 5

            55% of R1-5=R2 ---- 3rd: 70% of R2 + 3

            30% of R2- 3 = 12

            work backwards,

            30% of R2 = 15, R2 = 15/3 x 10 = 50

            55% of R1 – 5 = R2 = 50, R1 = 55/55 x 100 = 100

            ½ initial -8 = R1 = 100, Initial = 108 x 2 = 216

            cheers.

            1 Reply Last reply Reply Quote 0
            • MathIzzzFunM Offline
              MathIzzzFun
              last edited by

              Superbugs:
              P5 Question:


              Before a game, Azmi and Peiqin had the same no. of pitcure cards. During the first round, Azmi lost 12 of his picture cards to Peiqin. During the second round, Peiqin won 16 picture cards from Azmi. In the end, Peiqin had 3 times as many picture cards as Azmi.

              a) How many more picture cards did Peiqin have in the end?
              b) How many pitcure cards did both of them have in all?

              a)
              Azmi= 1u
              Peiqin=3u+28

              2u=28
              1u=14
              3u+28=3x14+28=56 picture cards

              b) 4u+28=84 picture cards

              Part a) is correct but for part b) the answer sheet shows 112? Appreciate help on part b) pls. Tks
              hi

              http://i52.tinypic.com/2vmaaz4.jpg\">

              cheers.

              1 Reply Last reply Reply Quote 0
              • W Offline
                wahwah
                last edited by

                Hi,

                Need help for the following Math Qn. Many thanks in advance.

                Andy, Ben, Chris shared a box of marbles. Andy received 3/8 od the marbles. Ben received 3/7 as many marbles as Chris. Andy received 213 more marbles then Ben. How many marbles were there in the box?

                1 Reply Last reply Reply Quote 0
                • MathIzzzFunM Offline
                  MathIzzzFun
                  last edited by

                  wahwah:
                  Hi,

                  Need help for the following Math Qn. Many thanks in advance.

                  Andy, Ben, Chris shared a box of marbles. Andy received 3/8 od the marbles. Ben received 3/7 as many marbles as Chris. Andy received 213 more marbles then Ben. How many marbles were there in the box?
                  Hi

                  Ben: Chris = 3u:7u

                  Andy: Andy+Ben+Chris = 3:8
                  Andy: Ben+Chris = 3: 5 = 6u : 10u (total 16u)

                  Andy: Ben : Chris = 6u: 3u : 7u
                  So 6u-3u = 3u= 213, 1u = 213/3 = 71
                  Total 16u = 16 x 71 = 1136 marbles.

                  cheers.

                  1 Reply Last reply Reply Quote 0
                  • W Offline
                    wahwah
                    last edited by

                    Hi MathIzzzFun,

                    Thanks for the solution!

                    1 Reply Last reply Reply Quote 0
                    • ozoraO Offline
                      ozora
                      last edited by

                      Need help. Unable to comprehend " with the same amount of money?" Does it mean $90?

                      How to solve?
                      Jane bought some pens at $90. If she was given a discount of 20% on her purchase, she would be able to buy 6 more pens wuth the same amount of money. Find the usual price of 1 pen.

                      1 Reply Last reply Reply Quote 0
                      • A Offline
                        andante
                        last edited by

                        Hi,

                        pls help to solve the following question WITHOUT using simultaneous equation.

                        There was a total of 2400 red, blue and green marbles in Box A and Box B at first. The number of marbles in Box A was twice the number of marbles in Box B. In Box A, The number of red marbles is 25% of the total number of blue and green marbles. The number of blue and green marbles in Box B is 60% of the total number of marbles in Box B. After transferring some marbles between each other, 25% of the marbles in Box A and 75% of marbles in Box B were red. How many marbles were there in Box A after the change?

                        1 Reply Last reply Reply Quote 0

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