Logo
    • Education
      • Pre-School
      • Primary Schools Directory
      • Primary Schools Articles
      • P1 Registration
      • DSA
      • PSLE
      • Secondary
      • Tertiary
      • Special Needs
    • Lifestyle
      • Well-being
    • Activities
      • Events
    • Enrichment & Services
      • Find A Service Provider
      • Enrichment Articles
      • Enrichment Services
      • Tuition Centre/Private Tutor
      • Infant Care/ Childcare / Student Care Centre
      • Kindergarten/Preschool
      • Private Institutions and International Schools
      • Special Needs
      • Indoor & Outdoor Playgrounds
      • Paediatrics
      • Neonatal Care
    • Forum
    • ASKQ
    • Register
    • Login

    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
    4.3k Posts 374 Posters 1.6m Views 1 Watching
    Loading More Posts
    • Oldest to Newest
    • Newest to Oldest
    • Most Votes
    Reply
    • Reply as topic
    Log in to reply
    This topic has been deleted. Only users with topic management privileges can see it.
    • ozoraO Offline
      ozora
      last edited by

      MathIzzzFun:
      ozora:

      Need help. Unable to comprehend \" with the same amount of money?\" Does it mean $90?

      How to solve?
      Jane bought some pens at $90. If she was given a discount of 20% on her purchase, she would be able to buy 6 more pens with the same amount of money. Find the usual price of 1 pen.

      Hi

      Discount of 20% = $90 x 0.2 = $ 18
      1 pen = $ 18/6 = $3 = 80% of original price

      So original price = 10/8 x $3 = $ 3.75 / pen

      cheers.

      oic
      thanks

      1 Reply Last reply Reply Quote 0
      • A Offline
        andante
        last edited by

        MathIzzzFun:
        andante:

        Hi,

        pls help to solve the following question WITHOUT using simultaneous equation.

        There was a total of 2400 red, blue and green marbles in Box A and Box B at first. The number of marbles in Box A was twice the number of marbles in Box B. In Box A, The number of red marbles is 25% of the total number of blue and green marbles. The number of blue and green marbles in Box B is 60% of the total number of marbles in Box B. After transferring some marbles between each other, 25% of the marbles in Box A and 75% of marbles in Box B were red. How many marbles were there in Box A after the change?

        Hi

        hope this helps πŸ˜„

        http://www.flickr.com/photos/62167097@N02/5997248173/in/photostream

        cheers.

        Hi,
        Thanks for the solution but I dont really understand why 2400/ 4 ?
        why 4 ? how to group as 4 ? and 640-600/2 why 2 ?

        1 Reply Last reply Reply Quote 0
        • MathIzzzFunM Offline
          MathIzzzFun
          last edited by

          andante:
          MathIzzzFun:

          [quote=\"andante\"]Hi,

          pls help to solve the following question WITHOUT using simultaneous equation.

          There was a total of 2400 red, blue and green marbles in Box A and Box B at first. The number of marbles in Box A was twice the number of marbles in Box B. In Box A, The number of red marbles is 25% of the total number of blue and green marbles. The number of blue and green marbles in Box B is 60% of the total number of marbles in Box B. After transferring some marbles between each other, 25% of the marbles in Box A and 75% of marbles in Box B were red. How many marbles were there in Box A after the change?

          Hi

          hope this helps πŸ˜„

          http://www.flickr.com/photos/62167097@N02/5997248173/in/photostream

          cheers.

          Hi,
          Thanks for the solution but I dont really understand why 2400/ 4 ?
          why 4 ? how to group as 4 ? and 640-600/2 why 2 ?[/quote]Hi

          After transfer,

          Box A = @ @ @ @
          Box B = * * * *
          Total in Box A + Box B = 2400,
          so @ + * = 2400 / 4 = 600 (there are 4 groups of \"@ + *\" in Box A & Box B)

          25% of Box A and 75% of Box B are red,
          so @ + * * * = 640,

          since @ + * = 600, * * = 640-600, * = (640-600)/2 = 20

          cheers.

          1 Reply Last reply Reply Quote 0
          • A Offline
            andante
            last edited by

            MathIzzzFun:
            andante:

            [quote=\"MathIzzzFun\"]Hi,

            pls help to solve the following question WITHOUT using simultaneous equation.

            There was a total of 2400 red, blue and green marbles in Box A and Box B at first. The number of marbles in Box A was twice the number of marbles in Box B. In Box A, The number of red marbles is 25% of the total number of blue and green marbles. The number of blue and green marbles in Box B is 60% of the total number of marbles in Box B. After transferring some marbles between each other, 25% of the marbles in Box A and 75% of marbles in Box B were red. How many marbles were there in Box A after the change?

            Hi

            hope this helps πŸ˜„

            http://www.flickr.com/photos/62167097@N02/5997248173/in/photostream

            cheers.

            Hi

            After transfer,

            Box A = @ @ @ @
            Box B = * * * *
            Total in Box A + Box B = 2400,
            so @ + * = 2400 / 4 = 600 (there are 4 groups of \"@ + *\" in Box A & Box B)

            25% of Box A and 75% of Box are red,
            so @ + * * * = 640,

            since @ + * = 600, * * = 640-600, * = (640-600)/2 = 20

            cheers.[/quote]Thank you very much πŸ™‚

            1 Reply Last reply Reply Quote 0
            • MathIzzzFunM Offline
              MathIzzzFun
              last edited by

              andante:
              MathIzzzFun:


              Hi

              After transfer,

              Box A = @ @ @ @
              Box B = * * * *
              Total in Box A + Box B = 2400,
              so @ + * = 2400 / 4 = 600 (there are 4 groups of \"@ + *\" in Box A & Box B)

              25% of Box A and 75% of Box are red,
              so @ + * * * = 640,

              since @ + * = 600, * * = 640-600, * = (640-600)/2 = 20

              cheers.

              Thank you very much πŸ™‚


              u r welcome πŸ˜„

              cheers.

              1 Reply Last reply Reply Quote 0
              • J Offline
                jtparent
                last edited by

                Hi,

                need ur assistance in the below q:

                Brain has some 50cent, 20cent & 10cent coin. 60% of his coins are 50cent & 20cent. The number of his 10cent coin is 75% that of his 50cent coins. If he has $16 worth of 50cent coins,what percentage of the value of all his coins is the value of 20cent coins.Give your ans correct to 2 decimal place.

                1 Reply Last reply Reply Quote 0
                • A Offline
                  Angel25
                  last edited by

                  Beatrice arranged some beads in 15 short rows and 14 long rows. there were 36 more beads in each long row than each short row. Beatrice used 70% of the beads she had to arrange the beads in long rows while the rest of the beads were arranged in short rows. How many beads were there in each short row?


                  steps and explanations pls

                  1 Reply Last reply Reply Quote 0
                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    Angel25:
                    Beatrice arranged some beads in 15 short rows and 14 long rows. there were 36 more beads in each long row than each short row. Beatrice used 70% of the beads she had to arrange the beads in long rows while the rest of the beads were arranged in short rows. How many beads were there in each short row?


                    steps and explanations pls
                    hi

                    http://i54.tinypic.com/wch5c7.jpg\">

                    cheers.

                    1 Reply Last reply Reply Quote 0
                    • MathIzzzFunM Offline
                      MathIzzzFun
                      last edited by

                      jtparent:
                      Hi,

                      need ur assistance in the below q:

                      Brain has some 50cent, 20cent & 10cent coin. 60% of his coins are 50cent & 20cent. The number of his 10cent coin is 75% that of his 50cent coins. If he has $16 worth of 50cent coins,what percentage of the value of all his coins is the value of 20cent coins.Give your ans correct to 2 decimal place.
                      Hi

                      ratio of number of 10cent coins : 50cent coins = 3:4 = 6u : 8u
                      ratio of number of 10cent coins : 50cent & 20 cent coins = 2:3 = 6u : 9u
                      so, ratio of number of 10cent coins: 50cent coins : 20cent coins = 6u:8u:1u

                      ratio of value of 10cent coins: 50cent coins : 20cent coins
                      = 6ux1:8ux5:1ux2
                      = 6u:40u:2u

                      So, value of 20cent coins as percentage of value of all the coins
                      = 2u/(40u+6u+2u)x100% = 1/24 x 100% =4.17% (to 2 decimal place)

                      cheers.

                      1 Reply Last reply Reply Quote 0
                      • J Offline
                        jtparent
                        last edited by

                        MathIzzzFun:
                        jtparent:

                        Hi,

                        need ur assistance in the below q:

                        Brain has some 50cent, 20cent & 10cent coin. 60% of his coins are 50cent & 20cent. The number of his 10cent coin is 75% that of his 50cent coins. If he has $16 worth of 50cent coins,what percentage of the value of all his coins is the value of 20cent coins.Give your ans correct to 2 decimal place.

                        Hi

                        ratio of number of 10cent coins : 50cent coins = 3:4 = 6u : 8u
                        ratio of number of 10cent coins : 50cent & 20 cent coins = 2:3 = 6u : 9u
                        so, ratio of number of 10cent coins: 50cent coins : 20cent coins = 6u:8u:1u

                        ratio of value of 10cent coins: 50cent coins : 20cent coins
                        = 6ux1:8ux5:1ux2
                        = 6u:40u:2u

                        So, value of 20cent coins as percentage of value of all the coins
                        = 2u/(40u+6u+2u)x100% = 1/24 x 100% =4.17% (to 2 decimal place)

                        cheers.


                        hi
                        thanks for the solution. is this the only way to solve this q? btw what type of method do you use to solve this?

                        1 Reply Last reply Reply Quote 0

                        Hello! It looks like you're interested in this conversation, but you don't have an account yet.

                        Getting fed up of having to scroll through the same posts each visit? When you register for an account, you'll always come back to exactly where you were before, and choose to be notified of new replies (either via email, or push notification). You'll also be able to save bookmarks and upvote posts to show your appreciation to other community members.

                        With your input, this post could be even better πŸ’—

                        Register Login
                        • 1
                        • 2
                        • 381
                        • 382
                        • 383
                        • 384
                        • 385
                        • 429
                        • 430
                        • 383 / 430
                        • First post
                          Last post



                        Online Users
                        Eva2015E
                        Eva2015

                        Statistics

                        5

                        Online

                        210.7k

                        Users

                        34.2k

                        Topics

                        1.8m

                        Posts
                        Popular Topics
                        New to the KiasuParents forum? Tips and Tricks!
                        Choosing and Evaluating Primary Schools
                        DSA 2026
                        PSLE Discussions and Strategies
                        How much do you spend on the kids' tuition/enrichments?
                        SkillsFuture + anything related to upskilling/learning something new!

                          About Us Contact Us forum Terms of Service Privacy Policy