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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • A
      andante
      last edited by

      MathIzzzFun:
      andante:

      [quote=\"MathIzzzFun\"]Hi,

      pls help to solve the following question WITHOUT using simultaneous equation.

      There was a total of 2400 red, blue and green marbles in Box A and Box B at first. The number of marbles in Box A was twice the number of marbles in Box B. In Box A, The number of red marbles is 25% of the total number of blue and green marbles. The number of blue and green marbles in Box B is 60% of the total number of marbles in Box B. After transferring some marbles between each other, 25% of the marbles in Box A and 75% of marbles in Box B were red. How many marbles were there in Box A after the change?

      Hi

      hope this helps πŸ˜„

      http://www.flickr.com/photos/62167097@N02/5997248173/in/photostream

      cheers.

      Hi

      After transfer,

      Box A = @ @ @ @
      Box B = * * * *
      Total in Box A + Box B = 2400,
      so @ + * = 2400 / 4 = 600 (there are 4 groups of \"@ + *\" in Box A & Box B)

      25% of Box A and 75% of Box are red,
      so @ + * * * = 640,

      since @ + * = 600, * * = 640-600, * = (640-600)/2 = 20

      cheers.[/quote]Thank you very much πŸ™‚

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      • MathIzzzFunM
        MathIzzzFun
        last edited by

        andante:
        MathIzzzFun:


        Hi

        After transfer,

        Box A = @ @ @ @
        Box B = * * * *
        Total in Box A + Box B = 2400,
        so @ + * = 2400 / 4 = 600 (there are 4 groups of \"@ + *\" in Box A & Box B)

        25% of Box A and 75% of Box are red,
        so @ + * * * = 640,

        since @ + * = 600, * * = 640-600, * = (640-600)/2 = 20

        cheers.

        Thank you very much πŸ™‚


        u r welcome πŸ˜„

        cheers.

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        • J
          jtparent
          last edited by

          Hi,

          need ur assistance in the below q:

          Brain has some 50cent, 20cent & 10cent coin. 60% of his coins are 50cent & 20cent. The number of his 10cent coin is 75% that of his 50cent coins. If he has $16 worth of 50cent coins,what percentage of the value of all his coins is the value of 20cent coins.Give your ans correct to 2 decimal place.

          1 Reply Last reply
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          • A
            Angel25
            last edited by

            Beatrice arranged some beads in 15 short rows and 14 long rows. there were 36 more beads in each long row than each short row. Beatrice used 70% of the beads she had to arrange the beads in long rows while the rest of the beads were arranged in short rows. How many beads were there in each short row?


            steps and explanations pls

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            • MathIzzzFunM
              MathIzzzFun
              last edited by

              Angel25:
              Beatrice arranged some beads in 15 short rows and 14 long rows. there were 36 more beads in each long row than each short row. Beatrice used 70% of the beads she had to arrange the beads in long rows while the rest of the beads were arranged in short rows. How many beads were there in each short row?


              steps and explanations pls
              hi

              http://i54.tinypic.com/wch5c7.jpg\">

              cheers.

              1 Reply Last reply
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              • MathIzzzFunM
                MathIzzzFun
                last edited by

                jtparent:
                Hi,

                need ur assistance in the below q:

                Brain has some 50cent, 20cent & 10cent coin. 60% of his coins are 50cent & 20cent. The number of his 10cent coin is 75% that of his 50cent coins. If he has $16 worth of 50cent coins,what percentage of the value of all his coins is the value of 20cent coins.Give your ans correct to 2 decimal place.
                Hi

                ratio of number of 10cent coins : 50cent coins = 3:4 = 6u : 8u
                ratio of number of 10cent coins : 50cent & 20 cent coins = 2:3 = 6u : 9u
                so, ratio of number of 10cent coins: 50cent coins : 20cent coins = 6u:8u:1u

                ratio of value of 10cent coins: 50cent coins : 20cent coins
                = 6ux1:8ux5:1ux2
                = 6u:40u:2u

                So, value of 20cent coins as percentage of value of all the coins
                = 2u/(40u+6u+2u)x100% = 1/24 x 100% =4.17% (to 2 decimal place)

                cheers.

                1 Reply Last reply
                Reply Quote 0
                • J
                  jtparent
                  last edited by

                  MathIzzzFun:
                  jtparent:

                  Hi,

                  need ur assistance in the below q:

                  Brain has some 50cent, 20cent & 10cent coin. 60% of his coins are 50cent & 20cent. The number of his 10cent coin is 75% that of his 50cent coins. If he has $16 worth of 50cent coins,what percentage of the value of all his coins is the value of 20cent coins.Give your ans correct to 2 decimal place.

                  Hi

                  ratio of number of 10cent coins : 50cent coins = 3:4 = 6u : 8u
                  ratio of number of 10cent coins : 50cent & 20 cent coins = 2:3 = 6u : 9u
                  so, ratio of number of 10cent coins: 50cent coins : 20cent coins = 6u:8u:1u

                  ratio of value of 10cent coins: 50cent coins : 20cent coins
                  = 6ux1:8ux5:1ux2
                  = 6u:40u:2u

                  So, value of 20cent coins as percentage of value of all the coins
                  = 2u/(40u+6u+2u)x100% = 1/24 x 100% =4.17% (to 2 decimal place)

                  cheers.


                  hi
                  thanks for the solution. is this the only way to solve this q? btw what type of method do you use to solve this?

                  1 Reply Last reply
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                  • MathIzzzFunM
                    MathIzzzFun
                    last edited by

                    jtparent:
                    MathIzzzFun:

                    [quote=\"jtparent\"]Hi,

                    need ur assistance in the below q:

                    Brain has some 50cent, 20cent & 10cent coin. 60% of his coins are 50cent & 20cent. The number of his 10cent coin is 75% that of his 50cent coins. If he has $16 worth of 50cent coins,what percentage of the value of all his coins is the value of 20cent coins.Give your ans correct to 2 decimal place.

                    Hi

                    ratio of number of 10cent coins : 50cent coins = 3:4 = 6u : 8u
                    ratio of number of 10cent coins : 50cent & 20 cent coins = 2:3 = 6u : 9u
                    so, ratio of number of 10cent coins: 50cent coins : 20cent coins = 6u:8u:1u

                    ratio of value of 10cent coins: 50cent coins : 20cent coins
                    = 6ux1:8ux5:1ux2
                    = 6u:40u:2u

                    So, value of 20cent coins as percentage of value of all the coins
                    = 2u/(40u+6u+2u)x100% = 1/24 x 100% =4.17% (to 2 decimal place)

                    cheers.


                    hi
                    thanks for the solution. is this the only way to solve this q? btw what type of method do you use to solve this?[/quote]Hi

                    Usually there will be more than one approach to solving any problem sum, and there is no fixed method or \"formula\" for a particular problem type.

                    For this case, one has to find a way to calculate the value of all the coins, so we could either use ratio or model to determine the ratio of the number of coins for each coin type and then multiply the individual ratio by the coin value to get the ratio for the value for each coin type.

                    http://i56.tinypic.com/25k0r28.jpg\">

                    cheers.

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                    • W
                      wahwah
                      last edited by

                      Hi,

                      Need help with Math qn again. Many thanks in advance.

                      Sam made some toys to sell. He sold 20% of the toys on Monday. He sold 20% of the toys on Tuesday. On Wednesday he sold 10% of the remaining toys. After that he found that the number of toys he had left was 1 more than 1/2 the number of toys he had made. How many toys did he make?

                      1 Reply Last reply
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                      • C
                        Chan09
                        last edited by

                        Need some help:

                        In a test, A,B,C and D scored an average of 73.25marks. D score was 60% of A. A scored 4 marks more than C. B scored 27 marks less than A. Calculate B scores?

                        Ans: 63 marks

                        1 Reply Last reply
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