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    All About Math Olympiad Training & Questions

    Scheduled Pinned Locked Moved Mathematics
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    • P Offline
      Pen88n
      last edited by

      Let me try to get the answers:


      1) Between 1 - 99, total # of digits 189 digits
      Betweem 100 - 199, total # of digits 300
      Between 200 - 299, total # of digits 300
      Between 300 - 399, total # of digits 300

      So you can see the 1000th digit falls within number "370" and it ends at digit 3.

      2) From 1- 100, there are 19 numbers with digit 2 (10 from the "20 - 29" range and 1 each from the "1 - 90 exclude 20+" range)

      For 200 - 299, there are 100 numbers with digit 2

      From 1 - 1000, there are 100 + 9(19) = 271 numbers with digit 2.

      From 1001 - 1999, there are 271 numbers with digit 2

      From 2000 - 2009, there are 10 numbers with digit 2

      From 1 - 2009, total 271+271+10 = 552 numbers with digit 2

      3) 22+24+26+…+200 = 200(200+2)/2 = 20200

      Please advise if answers are correct. Thanks

      1 Reply Last reply Reply Quote 0
      • C Offline
        Courage
        last edited by

        Pen88n, Thanks for your reply.


        My working for Q3 is

        2(11+12+13+…+100)
        2(1+2+3+4+5+…+100)

        Using the formula,
        1+2+3+4+…+100 is 100(100+1)/2 =5050

        thus, 2(5050-55)=9990 since 1+2+3…+10=55

        1 Reply Last reply Reply Quote 0
        • K Offline
          kiasiparent
          last edited by

          Pen88n:
          Let me try to get the answers:


          1) Between 1 - 99, total # of digits 189 digits
          Betweem 100 - 199, total # of digits 300
          Between 200 - 299, total # of digits 300
          Between 300 - 399, total # of digits 300

          So you can see the 1000th digit falls within number \"370\" and it ends at digit 3.

          2) From 1- 100, there are 19 numbers with digit 2 (10 from the \"20 - 29\" range and 1 each from the \"1 - 90 exclude 20+\" range)

          For 200 - 299, there are 100 numbers with digit 2

          From 1 - 1000, there are 100 + 9(19) = 271 numbers with digit 2.

          From 1001 - 1999, there are 271 numbers with digit 2

          From 2000 - 2009, there are 10 numbers with digit 2

          From 1 - 2009, total 271+271+10 = 552 numbers with digit 2

          3) 22+24+26+....+200 = 200(200+2)/2 = 20200

          Please advise if answers are correct. Thanks
          First 2 are correct
          3) 45 pairs x 222 = 9990

          1 Reply Last reply Reply Quote 0
          • P Offline
            Pen88n
            last edited by

            Thanks, Courage & Kiasiparent.


            Finally see \"light\" for Q3.

            It's great workout for my brain 🙂

            1 Reply Last reply Reply Quote 0
            • T Offline
              Tang
              last edited by

              Pen88n:
              Let me try to get the answers:


              1) Between 1 - 99, total # of digits 189 digits
              Betweem 100 - 199, total # of digits 300
              Between 200 - 299, total # of digits 300
              Between 300 - 399, total # of digits 300

              So you can see the 1000th digit falls within number \"370\" and it ends at digit 3.

              2) From 1- 100, there are 19 numbers with digit 2 (10 from the \"20 - 29\" range and 1 each from the \"1 - 90 exclude 20+\" range)

              For 200 - 299, there are 100 numbers with digit 2

              From 1 - 1000, there are 100 + 9(19) = 271 numbers with digit 2.

              From 1001 - 1999, there are 271 numbers with digit 2

              From 2000 - 2009, there are 10 numbers with digit 2

              From 1 - 2009, total 271+271+10 = 552 numbers with digit 2

              3) 22+24+26+....+200 = 200(200+2)/2 = 20200

              Please advise if answers are correct. Thanks
              1)
              1 to 9 --> 9 digits
              10 to 99 --> 2 x 90 = 180 digits
              100 to 299 --> 3 x 200 = 600 digits

              1000 - 9 - 180 - 600 = 211 digits

              211 / 3 = 70 r 1 --> So number from 300 to 369 and 3(70) is incomplete
              Hence the digit is 3.

              3)
              (2 + 4 + .... 200) - (2 + 4 + ....20)
              = (2+200)/2 x 100 - (2+20)/2 x 10
              = 10100 - 110
              = 9990

              1 Reply Last reply Reply Quote 0
              • M Offline
                mathzgenius
                last edited by

                Courage:
                Need :?: for the following questions:


                (1) If we write whole numbers starting from 1 to form a 1000-digit number N as follows: N=12345678910111213.... what is the unit digit of N?

                (2) How many whole numbers from 1 to 2009 contain the digit \"2\"?

                (3) Study the following pattern:

                1=1: 1(1+1)/2=1
                1+2=3; 2(2+1)/2=3
                1+2+3=6; 3(3+1)/2=6
                1+2+3+4=10; 4(4+1)/2=10
                1+2+3+4+5=15; 5(5+1)/2=15

                Find the value of 22+24+26+....+200.

                TIA.
                My answers for the questions are:

                2)355

                3)55

                Please advise if the answers are correct. I can teach you how to work it out mentally.

                * How do you solve Q1??

                Please help. I don't quite get your workings. TIA

                1 Reply Last reply Reply Quote 0
                • M Offline
                  Merlion
                  last edited by

                  > 3)55


                  How can 22+24+ … +200 equal to 55? No way.
                  We can simply use Gauss’s method, the answer is 9990.

                  1 Reply Last reply Reply Quote 0
                  • T Offline
                    Tang
                    last edited by

                    Merlion:
                    > 3)55


                    How can 22+24+ .... +200 equal to 55? No way.
                    We can simply use Gauss's method, the answer is 9990.

                    (2 + 4 + ...... + 200) - (2 + 4 + ..... + 20)
                    = (2 + 200)/2 x 100 - (2 + 20)/2 x 10
                    = 10100 - 110
                    = 9990

                    1 Reply Last reply Reply Quote 0
                    • K Offline
                      kidsjoy
                      last edited by

                      Maths Olympiad is hot here. Myself went through this training and loved it. Also it helped prepare me in logic and analysis that helps a lot in my higher education. But as said by some parents here, I am born to have a stronger mind in this type of analysis. Well, I am really weak in art . I did spent some time looking around, and I do not find lots of this type of training in Singapore. Looks like only the school themselves have these training. Anyway, still a long way for my kids.

                      1 Reply Last reply Reply Quote 0
                      • U Offline
                        usaik
                        last edited by

                        Please pardon my ignorance. I was trying to look for maths enrichment class information for my P2 kiddo and happen to stumble into this thread. After browsing through the thread. I am still not very sure what is the purpose of Maths Olympiad?


                        What is the purpose of so many parents sending their kids for Maths Olympiad training?

                        Why is the objective of the Olympiad competition? What are the schools trying to achieve?
                        [quote]Maths Olympiad is hot here. Myself went through this training and loved it. Also it helped prepare me in logic and analysis that helps a lot in my higher education. But as said by some parents here, I am born to have a stronger mind in this type of analysis. ..[/quote] Hi Kidsjoy, you make the training sound fun..... can share whether it help to do well in the school Maths syllabus by attending this FUN training? THANKS!

                        1 Reply Last reply Reply Quote 0

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