Q&A - PSLE Math

[htn]

Hi, anyone tried Pei Chun 2011 prelim paper (paper 2) question 14, can teach me how to solve ?


Tia

[Andrew Lee]

Belle2011:

tianzhu:

[quote=\"Belle2011\"]Thank-you very much tianzhu.

sigh... I also don't know how to solve RGPS Q14b.

Hi Belle2011

You’re welcome.

I don’t have a set of 2011 test papers.

Please post the question if you need clarification.

Best wishes

http://i52.tinypic.com/wvskmd.jpg\">
Thank-you Mr Andrew Lee.[/quote]You are welcome, I also cant solve this question too

[tianzhu]

Hi Belle


I did a quick check for Q14b

Is the answer 14?

Best wishes

[Belle2011]

atutor2001:

Andrew Lee:

Can help me solve Q14b:


http://i52.tinypic.com/wvskmd.jpg\">

Following the labeling in your diagram

Area of Quadrant = a+b+c+d

Shaded Area = (a+b+c+d) + c + d + (b+d) + (a+d)
= 2a+2b+2c+4d

Unshaded Area = b + (b+c) + a + (a+c)
=2a+2b+2c

Shaded - Unshaded = 4d = 2.5x1.4x4 = 14

I understand area of quadrant but unsure how do you get Shaded Area and Unshaded Area.

[Belle2011]

tianzhu:

Hi Belle

I did a quick check for Q14b
Is the answer 14?
Best wishes

Dear tianzhu,
Yes, this answer is the same as atutor.
Thank-you.

[tianzhu]

Belle2011:

Dear tianzhu,

Yes, this answer is the same as atutor.
Thank-you.

Hi

You need to draw two lines in mirror images to those in the question.

The answer is 5*2.8 which is 14.

If you need the slide, please let me know.

Best wishes

[Belle2011]

tianzhu:

You need to draw two lines in mirror images to those in the question.

The answer is 5*2.8 which is 14.

If you need the slide, please let me know.

Best wishes

Where to draw that 2 lines? Now is too late, perhaps tomorrow if you are free, please show us the working.
Thanking you in advance.

[MathIzzzFun]

Belle2011:

atutor2001:

[quote=\"Andrew Lee\"]Can help me solve Q14b:


http://i52.tinypic.com/wvskmd.jpg\">

Following the labeling in your diagram

Area of Quadrant = a+b+c+d

Shaded Area = (a+b+c+d) + c + d + (b+d) + (a+d)
= 2a+2b+2c+4d

Unshaded Area = b + (b+c) + a + (a+c)
=2a+2b+2c

Shaded - Unshaded = 4d = 2.5x1.4x4 = 14

I understand area of quadrant but unsure how do you get Shaded Area and Unshaded Area.[/quote]Hi

hope this helps..

http://i56.tinypic.com/35idr2o.jpg\">

cheers.

[ivanhoo99]

Hi pls help


Mr Tan drove from city X to city Y.At the same time,Mr Koh drove from city Y to city X.They passed each other 64 km away from city Y and continued their journeys. They made a u-turn upon reaching their destinations so that they could return to their own cities. They passed each other again 52 km away from city X… Find the distance between the two places when they met each other.

This question has been posted much earlier but can’t seem to find the solution…

[MathIzzzFun]

ivanhoo99:

Hi pls help


Mr Tan drove from city X to city Y.At the same time,Mr Koh drove from city Y to city X.They passed each other 64 km away from city Y and continued their journeys. They made a u-turn upon reaching their destinations so that they could return to their own cities. They passed each other again 52 km away from city X.. Find the distance between the two places when they met each other.

This question has been posted much earlier but can't seem to find the solution..

Hi

http://www.flickr.com/photos/62167097@N02/6085706330/in/photostream

cheers.