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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      Angel25:
      CHIJ Prelims 2011 P2 Q12


      At 8.30am, Myke and Jerome set off at the same time from Town X to Town Y. At 11.00am, Myke completed his journey but Jerome had covered only 5/8 of the journey. Jerome's speed was 54km/h slower than Myke's.

      a) Find the distance between Town X and Town Y.
      b) At what time would Jerome complete his journey?
      Hi

      8.30am --> 11.00am = 2.5h, Myke reached Town Y in 2.5h.
      2.5h x 54km = 135 km --> Jerome was still 135 km from Town Y at 11.00am
      so 3/8 of the distance = 135 km, distance between Town X & Y = 135/3 x 8 = 360 km

      Jerome took 2.5h to cover 5/8 of the distance, for remaining 3/8 of the distance, time taken = 3/5 x 2.5 = 1.5h = 1h 30 min

      Jerome will reach Town Y at 11.00 am + 1h 30min = 12.30 pm

      cheers.

      1 Reply Last reply Reply Quote 0
      • T Offline
        tianzhu
        last edited by

        Hi


        HP 2011 SA2 Q11

        Outer fence ----- 40cm
        Inner fence ------ 180cm

        Use a common length of 360cm as comparison

        Inner fence ------- 2180 ------- 18 metal spokes
        Outer fence ------- 9
        40 --------27 wooden spokes
        Difference ------- 9 wooden spokes

        198/9 -------22
        22(18+27) ------- 990

        Best wishes

        1 Reply Last reply Reply Quote 0
        • T Offline
          tianzhu
          last edited by

          Hi


          CHIJ 2011 Prelims P2 Q15

          You may solve it using MD.

          Donovan ----- 1 unit + 48

          Ethan ------1 unit

          Freddy ------ 2 units

          Gilbert ------- 432

          1 unit + 48 -------20%
          4 units + 192 ------ 80%

          4 units + 192 -------- 3 units + 432

          1 unit ------- 240

          Total number of trading cards -------- 4 units + 48 + 432 --------1440

          487 – (240+48) -------199

          199/288* 100% --------- 69.1%

          Best wishes

          1 Reply Last reply Reply Quote 0
          • MathIzzzFunM Offline
            MathIzzzFun
            last edited by

            Angel25:
            http://i53.tinypic.com/sfey6o.jpg\"> http://i53.tinypic.com/sfey6o.jpg\"> Henry Park 2011 Prelim P2 Q11

            Hi

            every 360cm stretch,
            Number of metal spokes = 9 x 2 = 18
            Number of wooden spokes = 3 x 9 = 27
            27 – 18 = 9 --> 9 more wooden spokes than metal spokes every 360cm.
            198 ÷ 9 = 22 of 360 cm-stretch
            Number of metal spokes = 22 x 18 = 396
            Number of wooden spokes = (22 x 27) x 4 = 2376
            2376 + 396 = 2772
            There a total of 2772 wooden and metal spokes.


            cheers.

            1 Reply Last reply Reply Quote 0
            • T Offline
              tianzhu
              last edited by

              Angel25:
              http://i52.tinypic.com/10ruv0z.jpg\"> Henry Park 2011 Prelim P2 Q10

              Hi

              Rearrange the figure.

              Area of square (12*12) ------ area of circle (r6) -------- A

              Area of eye -------- area of semi circle (r6) – square (6*6) -------- B

              The answer is (A+B)

              I’ll leave it to students to work out the calculations

              Best wishes

              1 Reply Last reply Reply Quote 0
              • A Offline
                Alchemist
                last edited by

                Hi - Could someone h http://i56.tinypic.com/9tcx1t.jpg\"> elp me with the sum below.

                1 Reply Last reply Reply Quote 0
                • D Offline
                  Daddy
                  last edited by

                  Hi,


                  Need help!! Thanks

                  A group of boys tool their pets to a park. Each boy either has a dog or cat. Between the boys and theirs pets, there were a total of 204 leags.
                  a) How many boys were there?
                  b) If there were 15 cats, how many more dogs than cats were there?

                  Thanks all the masters

                  1 Reply Last reply Reply Quote 0
                  • A Offline
                    Alchemist
                    last edited by

                    Daddy:
                    Hi,


                    Need help!! Thanks

                    A group of boys tool their pets to a park. Each boy either has a dog or cat. Between the boys and theirs pets, there were a total of 204 leags.
                    a) How many boys were there?
                    b) If there were 15 cats, how many more dogs than cats were there?

                    Thanks all the masters

                    Every group of Boy + Cat/Dog will have 6 legs.
                    So total no of such groups - 204/6 = 34.

                    Therefore a) 34 boys

                    b) If there were 15 cats - there are 19 dogs. So 4 more dogs than cats.

                    Am I missing something here?

                    1 Reply Last reply Reply Quote 0
                    • T Offline
                      tianzhu
                      last edited by

                      vidhyalog:
                      Hi - Could someone h http://i56.tinypic.com/9tcx1t.jpg\"> elp me with the sum below.

                      Hi

                      Draw a bigger square such that the circle is inscribed in it.

                      This bigger square is twice the area of the smaller square (8)

                      Area of big square ------ 8*2 -----16
                      Length of 1 side of big square -------4

                      Radius of circle ------- 2cm

                      Best wishes

                      1 Reply Last reply Reply Quote 0
                      • M Offline
                        mvmir26
                        last edited by

                        Please help on below. Thanks


                        John takes 40 min and Peter takes 30min to travel from Point X to Point Y.
                        A) What is the ratio of John’s average speed to Peter’s average speed?
                        B) If John starts traveling 5 min earlier than Peter, how long will Peter take to catch up with John.

                        1 Reply Last reply Reply Quote 0

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