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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      Essential:
      Mathizzfun, could you help me with this question?

      Rosie, sandy and Tabby shared a box of cards. Rosie took 1/5 of th total number of cards and another 12 cards. Sandy took 50% of the remaining cards in the box another 13 cards . Tabby took the last 27 cards in the box. How many cards were there in the box at first?
      Hi

      work backwards..

      13+27 = 40 = 50% of remaining cards ,
      remaining cards after Rosie took = 2 x 40 = 80
      80 + 12 = 4/5 of total number of cards =92
      Total number of cards in the box = 5/4 x 92 = 115

      cheers.

      1 Reply Last reply Reply Quote 0
      • MathIzzzFunM Offline
        MathIzzzFun
        last edited by

        Essential:
        Hi, need some help to solve this question.

        The ration of Ben's cards to Benny's cards was 3:4 After Ben bought another 9 cards and Benny lost 18 cards , the ration became 3:2. Find the total number of cards Ben and Benny had at first.
        Hi

        At first, Ben : Benny = 3u : 4u

        After Ben bought another 9 cards and Benny lost 18,
        Ben : Benny = 3u + 9 : 4u - 18 = 3 : 2

        Cross multiply-
        2(3u+9) = 3(4u-18)
        6u + 18 = 12u - 54
        6u = 72, 1u = 12

        3u = 36, 4u = 48. Ben had 36 cards and Benny had 48 cards at first.

        cheers.

        1 Reply Last reply Reply Quote 0
        • E Offline
          Essential
          last edited by

          Hi MathIzzfun, thank you so much for your replied.

          1 Reply Last reply Reply Quote 0
          • MathIzzzFunM Offline
            MathIzzzFun
            last edited by

            Essential:
            Hi MathIzzfun, thank you so much for your replied.

            u r welcome 😄

            cheers.

            1 Reply Last reply Reply Quote 0
            • S Offline
              Superbugs
              last edited by

              MGS SA2 2011


              Q26
              Jerry had some beads. He can divide them equally into 2, 5 or 7 groups. What was the max. number of beads that he had if he had less than 250 beads?

              Q29
              The figure below has a perimeter of 36cm. It is made up of 9 identical triangles. What is the increase in the perimeter of the figure when a row of triangles is added to the base?
              Regret that I do not know how to incorporate the figure here.
              My solution: 36/9= 4cm
              Increase triangles = 9 - 4base, 2 sides
              Hence 6x4=24cm
              However answer is only 12cm?

              Pls help!

              1 Reply Last reply Reply Quote 0
              • T Offline
                tianzhu
                last edited by

                Superbugs:
                MGS SA2 2011

                Q26
                Jerry had some beads. He can divide them equally into 2, 5 or 7 groups. What was the max. number of beads that he had if he had less than 250 beads?
                Hi

                For Q26, find the common multiple of 2, 5 and 7 closest to 250, the answer is 210.

                A common method used in primary maths is “Systematic Listing”

                A faster way to find the lowest multiple of 70 and multiply by 3.

                Best wishes

                1 Reply Last reply Reply Quote 0
                • MathIzzzFunM Offline
                  MathIzzzFun
                  last edited by

                  Superbugs:
                  MGS SA2 2011


                  Q26
                  Jerry had some beads. He can divide them equally into 2, 5 or 7 groups. What was the max. number of beads that he had if he had less than 250 beads?

                  Q29
                  The figure below has a perimeter of 36cm. It is made up of 9 identical triangles. What is the increase in the perimeter of the figure when a row of triangles is added to the base?
                  Regret that I do not know how to incorporate the figure here.
                  My solution: 36/9= 4cm
                  Increase triangles = 9 - 4base, 2 sides
                  Hence 6x4=24cm
                  However answer is only 12cm?

                  Pls help!
                  Hi

                  for q29.. if the figure is as shown, then the increase in perimeter is in red.

                  http://i53.tinypic.com/why5nm.jpg\">

                  cheers.

                  1 Reply Last reply Reply Quote 0
                  • S Offline
                    Superbugs
                    last edited by

                    To MazzIzzzFun,


                    The figure is right! Tks so
                    Much for your explanation!

                    1 Reply Last reply Reply Quote 0
                    • S Offline
                      Superbugs
                      last edited by

                      Aitong SA2 P2 Q9


                      ABCD us a rectangle. It is divided into 4 unequal triangles P, Q, R and S which meet at a point as shown (sorry I am unable to draw the figure here). Find the area of triangle S.

                      Assume Meet point is H, Some other information:
                      Triangle ABH - 24cm
                      Triangle ADH - 51cm2
                      Triangle CHD - 45cm2
                      Both ABH and CHD shares the same base (breadth of rectangle)

                      Kindly assist. Tks

                      1 Reply Last reply Reply Quote 0
                      • S Offline
                        Superbugs
                        last edited by

                        Aitong P2 Q17

                        The ratio of Steven’s cards to Benny’s cards was 3:4. After Steven bought another 9 cards and Benny lost 18 cards, the ratio became 3:2. Find the total number of cards Steven and Benny had at first?

                        Pls help. Tks

                        1 Reply Last reply Reply Quote 0

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