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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      Winx5015:
      Thanks MathIzzzFun. The answer is 104cm, is this correct?


      Cheers πŸ™‚
      bingo...

      u r welcome πŸ˜„

      cheers.

      1 Reply Last reply Reply Quote 0
      • S Offline
        Superbugs
        last edited by

        On Mon, M read 52 pages of a book. On Tues, he read 2/5 of the remaining pages. If he still had 1/3 of the book left to be read, how many pages were there in the book?


        I am unable to draw the model here but it goes like this:

        52 pages (Mon) + 2/5 (Tues) + 3/5 (unread)
        So 1/3 = 3/5 unread
        Hence 2/3 = 52 pages + 2/5 read
        I get common denominator of 15, hence
        10/15 = 52 pages + 6/15, so
        4u => 52 pages
        15u=> 195 pages but answer is 117 pages where becos 1/3 = 3/5 unread, 2/3 must be = 6/5 read
        Hence 52 pages = 4/5 read
        9u => 117 pages

        Why is that so?

        1 Reply Last reply Reply Quote 0
        • PiggyLalalaP Offline
          PiggyLalala
          last edited by

          Superbugs:
          On Mon, M read 52 pages of a book. On Tues, he read 2/5 of the remaining pages. If he still had 1/3 of the book left to be read, how many pages were there in the book?


          I am unable to draw the model here but it goes like this:

          52 pages (Mon) + 2/5 (Tues) + 3/5 (unread)
          So 1/3 = 3/5 unread
          Hence 2/3 = 52 pages + 2/5 read

          Should be 2/3 of the book = 52 pages + 2/5 of remaining pages.
          Hence we cannot subtract the 2 fractions


          10/15 = 52 pages + 6/15, so
          4u => 52 pages
          15u=> 195 pages but answer is 117 pages where becos 1/3 = 3/5 unread, 2/3 must be = 6/5 read
          Hence 52 pages = 4/5 read
          9u => 117 pages

          Why is that so?

          1 Reply Last reply Reply Quote 0
          • MathIzzzFunM Offline
            MathIzzzFun
            last edited by

            Superbugs:
            On Mon, M read 52 pages of a book. On Tues, he read 2/5 of the remaining pages. If he still had 1/3 of the book left to be read, how many pages were there in the book?


            I am unable to draw the model here but it goes like this:

            52 pages (Mon) + 2/5 (Tues) + 3/5 (unread)
            So 1/3 = 3/5 unread
            Hence 2/3 = 52 pages + 2/5 read
            I get common denominator of 15, hence
            10/15 = 52 pages + 6/15, so
            4u => 52 pages
            15u=> 195 pages but answer is 117 pages where becos 1/3 = 3/5 unread, 2/3 must be = 6/5 read
            Hence 52 pages = 4/5 read
            9u => 117 pages

            Why is that so?
            Hi

            the MD approach ...

            http://i56.tinypic.com/xeig7d.jpg\">

            cheers.

            1 Reply Last reply Reply Quote 0
            • PiggyLalalaP Offline
              PiggyLalala
              last edited by

              Superbugs:
              On Mon, M read 52 pages of a book. On Tues, he read 2/5 of the remaining pages. If he still had 1/3 of the book left to be read, how many pages were there in the book?
              Easier to do this question using model method.

              52 + XX ( read) + XXX( unread) = book
              XXX ( unread) = 1/3 of book
              2/3 of book = XXXXXX
              therefore 52 + XX = XXXXXX
              4X = 52
              X= 13
              Total pages in the book = 52 + 5X = 52 + 5(13) = 117

              1 Reply Last reply Reply Quote 0
              • S Offline
                Superbugs
                last edited by

                I still don’t get yours - Mathizzzfun!

                However my DD can solve it easily so I rest my case!
                Tks to all!

                1 Reply Last reply Reply Quote 0
                • PiggyLalalaP Offline
                  PiggyLalala
                  last edited by

                  pixiedust:
                  Ah, yes! I managed to get the correct answer, thanks piggylalala!

                  You're welcome πŸ™‚
                  All the best for the PSLE next year.

                  1 Reply Last reply Reply Quote 0
                  • J Offline
                    jtparent
                    last edited by

                    Hi,


                    was lost in dealing fractions / %. Pls help on the following qs:

                    1. At a toy fair 40% of those present were boys . 8/15 of the remainder were girls & the rest were adults. There were 480 more boys than adults. How many more children than adults were there at the toy fair?

                    2. Last mth, David use $840 of his salary to buy a laptop. He spent 1/8 of the remaining salary on rent, $400 on food & saved the rest. The amount that he spent on food was $20 less than that spent on rent.
                    a. What was his salary?
                    b. What % of his salary did he save?

                    3. Larry spent $60 less than 5/8 of his money on a MP3 player & $25 more than 7/9 of his remaining money on assessment books. After buying the assessement books, he still had $10 left.

                    a. How much money was left after Larry bought the MP3 player but before he bought the assessment books?
                    b. How much money did Larry have at first?

                    TIA

                    1 Reply Last reply Reply Quote 0
                    • S Offline
                      Superbugs
                      last edited by

                      Need help on this question!

                      There are 60% as many blueberry muffins as banana muffins and 20% more chocolate muffins than the blueberry muffins. What is the ratio of the number of banana muffins to the number of chocolate muffins?

                      1 Reply Last reply Reply Quote 0
                      • MathIzzzFunM Offline
                        MathIzzzFun
                        last edited by

                        Superbugs:
                        Need help on this question!

                        There are 60% as many blueberry muffins as banana muffins and 20% more chocolate muffins than the blueberry muffins. What is the ratio of the number of banana muffins to the number of chocolate muffins?
                        Hi
                        Blueberry : Banana = 60 : 100 = 3:5 -- (1)
                        Blueberry : Chocolate = 100 : 120 = 5:6 -- (2)

                        (1)x5, (2) x 3
                        Blueberry : Banana: Chocolate = 15 : 25 : 18

                        cheers.

                        1 Reply Last reply Reply Quote 0

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