Q&A - P4 Math
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need help on this following question.
there are 3 different types of tiles.
Tile A- 0.54 kg
Tile B - 0.76kg
Tile C-0.63kg
Kim has a stack of 21 different types of tiles which are made of a combination of Tiles A, B and C. 9 of them are Tiles C and the total mass of 21 tiles is 13.69kg. How many tiles A and B are there respectively? -
ozora:
this is a guess and check question.need help on this following question.
there are 3 different types of tiles.
Tile A- 0.54 kg
Tile B - 0.76kg
Tile C-0.63kg
Kim has a stack of 21 different types of tiles which are made of a combination of Tiles A, B and C. 9 of them are Tiles C and the total mass of 21 tiles is 13.69kg. How many tiles A and B are there respectively?
Wt of 9 tiles C = 9 x 0.63 = 5.67kg
Wt of tiles A & B = 13/69 - 5.67 = 8.02kg
# of tiles A & B = 21 - 9 = 12
Guess and check
6A & 6B = (6x0.54) + (6x0.76) = 7.8kg
5A & 7B = (5x0.54) + (7x0.76) = 8.02
5 tile A and 7 tile B -
zeemimi:
this question is similar to the money question...and the number of legs question (in P3)... no need to use guess and check also can (want to use also can :D)
this is a guess and check question.ozora:
need help on this following question.
there are 3 different types of tiles.
Tile A- 0.54 kg
Tile B - 0.76kg
Tile C-0.63kg
Kim has a stack of 21 different types of tiles which are made of a combination of Tiles A, B and C. 9 of them are Tiles C and the total mass of 21 tiles is 13.69kg. How many tiles A and B are there respectively?
Wt of 9 tiles C = 9 x 0.63 = 5.67kg
Wt of tiles A & B = 13/69 - 5.67 = 8.02kg
# of tiles A & B = 21 - 9 = 12
Guess and check
6A & 6B = (6x0.54) + (6x0.76) = 7.8kg
5A & 7B = (5x0.54) + (7x0.76) = 8.02
5 tile A and 7 tile B
Tile A- 0.54 kg
Tile B - 0.76kg
Tile C-0.63kg
Kim has a stack of 21 different types of tiles which are made of a combination of Tiles A, B and C. 9 of them are Tiles C and the total mass of 21 tiles is 13.69kg. How many tiles A and B are there respectively?
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9 Tile C --> 9x0.63=5.67
(21-9=)12 Tiles (A & B mix) --> 13.69-5.67=8.02
assume all 12 tiles are Tile A\t
--> 12x0.54=6.48\t
Difference --> 8.02-6.48=1.54
difference between Tile A & Tile B
1Tile --> 0.76-0.54=0.22
1.54 divide 0.22 = 7\t
\t
therefore 7\tTile B
and (12-7=) 5Tile A
hope it is clear...
(veterans....pls help double check
TQ).
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Need help.
How many whole numbers are there between 1000 and 10000?
Do we need to include nos ā1000ā n ā10000ā? -
The table shows the weights of some marbles.What is the weight of the heaviest marble?
a+b+c=240
b+c+d=230
c+d+a=250
a+b+d=210
can someone please help me on this question.
thank you in advanced. -
raysusan:
HiThe table shows the weights of some marbles.What is the weight of the heaviest marble?
a+b+c=240
b+c+d=230
c+d+a=250
a+b+d=210
can someone please help me on this question.
thank you in advanced.
adding all will give: 3 (a+b+c+d) = 930 or a+b+c+d= 310
d = 310-240=70
a=310-230=80
b=310-250=60
c=310-210=100
cheers. -
Need help urgently on the following Maths qns :
1). Yvonne and Alyssa had a total of $432. Yvonne spent 1/3 of her money and Alyssa spent 3/7 of her money. If they spent an equal amount of money, find the amount of money Alyssa had left.
Thanks in advance ! -
CNS:
HiNeed help urgently on the following Maths qns :
1). Yvonne and Alyssa had a total of $432. Yvonne spent 1/3 of her money and Alyssa spent 3/7 of her money. If they spent an equal amount of money, find the amount of money Alyssa had left.
Thanks in advance !
They spent equal amount of money ie
1/3 of Yvonne's money = 3/7 of Alyssa's money
--> 3/9 of Yvonne's money = 3/7 of Alyssa's money
... draw a model and you should be able to see that 3 units of Yvonne's money = 3 units of Alyssa's money. so, amount of money each has :
Yvonee --> 9 units
Alyssa --> 7 units
Total 16 units --> $ 432, 1 unit --> $ 27
Alyssa's money left --> 4 units --> 4 x $ 27 = $ 108
cheers. -
Thanks! Btw, are you a maths tutor ?
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Thanks to zeemimi, jedamum and wcw for answering the question
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