Q&A - P4 Math
-
tianzhu:
Hi tianzhu, thanks for your help,
Hibabies:
Hi any kind soul willing to help solving... :oops:
Q1: What is the smallest odd number that has only 3 factors?
Q2: Gary was given these numbers: 42, 50, 72, 84 and 96. Write down the sum of all the given numbers that have 2 and 6 as common factors.
:?: :? :?: :?
In answering these questions, it may useful to get your child to read the chapter on Factors in the school textbook.
Q1) The answer is 9 (1,3,9).
Q2) The number 50 does not have 6 as a common factor.
The sum of 42, 72, 84 and 96 is 294
Best wishes
But do you mind to explain in details for Q1 as I dont know how to get the steps done.
Thanks! -
babies:
Hi
Hi tianzhu, thanks for your help,
But do you mind to explain in details for Q1 as I dont know how to get the steps done.
Thanks!
The question asks for the smallest odd number that has only 3 factors.
9 = 1*9
9 = 3*3
The factors of 9 are 1, 3 and 9.
Best wishes -
:thankyou:
tianzhu:
:thankyou: why didnt I think of that... Thanks!
Hibabies:
Hi tianzhu, thanks for your help,
But do you mind to explain in details for Q1 as I dont know how to get the steps done.
Thanks!
The question asks for the smallest odd number that has only 3 factors.
9 = 1*9
9 = 3*3
The factors of 9 are 1, 3 and 9.
Best wishes -
Patrick had thrice as many marbles as Joe.
Patrick gave away 15 marbles and Joe gave away 3 marbles.
Then they had an unequal number of marbles.
How many marbles did Patrick have at first? -
babies:
Hi:thankyou:
:thankyou: why didnt I think of that... Thanks!tianzhu:
Hi tianzhu, thanks for your help,
But do you mind to explain in details for Q1 as I dont know how to get the steps done.
Thanks!
Hi
The question asks for the smallest odd number that has only 3 factors.
9 = 1*9
9 = 3*3
The factors of 9 are 1, 3 and 9.
Best wishes
additional information for Q1. All numbers have even number of factors except square numbers. So, if we are looking for odd number of factors, we can narrow the search to square numbers only ie 1x1, 3x3, 5x5,7x7 etc.
cheers. -
cmm:
HiPatrick had thrice as many marbles as Joe.
Patrick gave away 15 marbles and Joe gave away 3 marbles.
Then they had an unequal number of marbles.
How many marbles did Patrick have at first?
If unequal is replaced by equal, then the answer is Patrick had 18 marbles at first.
Best wishes -
tianzhu:
Hicmm:
Patrick had thrice as many marbles as Joe.
Patrick gave away 15 marbles and Joe gave away 3 marbles.
Then they had an unequal number of marbles.
How many marbles did Patrick have at first?
If unequal is replaced by equal, then the answer is Patrick had 18 marbles at first.
Best wishes
Oops, you're right tianzhu, it should be \"equal\". Got the solution le. Tks lots!! -
tianzhu:
Hi Tianzhu,
Hicmm:
Patrick had thrice as many marbles as Joe.
Patrick gave away 15 marbles and Joe gave away 3 marbles.
Then they had an unequal number of marbles.
How many marbles did Patrick have at first?
If unequal is replaced by equal, then the answer is Patrick had 18 marbles at first.
Best wishes
i have been thinking and trying, but still cant get your answer.
can you show us? -
Hi chloecube!
first Partic had 3u
joe had 1u
from the model,2u+3=15…u=6
so 3u=18 -
chloecube:
Hi
Hi Tianzhu,
i have been thinking and trying, but still cant get your answer.
can you show us?
Please do not spend too much thinking about maths, especially today.
1) Draw 3 boxes to show Patrick’s marbles.
2) Draw 1 box to show Joe’s marbles.
3) From the end of the third box, move 15 (shown by a line with arrows on both sides) to cut a vertical line down (1) and (2).
4) From (2) draw a line to show 3 marbles to touch vertical line drawn in (3)
5) Now, you’ll see 2 units ------ 12 or 1 unit ------ 6
6) Patrick had 3 units or 18 marbles.
Please let me know if you need me to draw the MD.
Best wishes
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