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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • N Offline
      notfreemom
      last edited by

      Hi, please help me with this question.


      Evergreen School spent $9065 on some tennis rackets and badmintob rackets. The ratio of the number of tennis rackets bought to the number of badminton rackets bought was 5:7. A tennis rackets costs $13.30 more than a badminton racket. The total cost of the tennis racket was 17/20 of the total cost of the badminton rackets. Find the cost of the one such tennis racket.
      Thanks.

      1 Reply Last reply Reply Quote 0
      • T Offline
        tianzhu
        last edited by

        notfreemom:
        Hi, please help me with this question.


        Evergreen School spent $9065 on some tennis rackets and badmintob rackets. The ratio of the number of tennis rackets bought to the number of badminton rackets bought was 5:7. A tennis rackets costs $13.30 more than a badminton racket. The total cost of the tennis racket was 17/20 of the total cost of the badminton rackets. Find the cost of the one such tennis racket.
        Thanks.
        Hi

        One neat way is to use MD.Due to time constraints, I'll give some pointers.

        The total cost of the tennis racket was 17/20 of the total cost of the badminton rackets.Evergreen School spent $9065 on some tennis rackets and badminton rackets.

        Hence, tennis rackets ------- 4165 and badminton rackets ------ 4900

        The ratio of the number of tennis rackets bought to the number of badminton rackets bought was 5:7

        7 units ------ 4900
        1 unit ------ 700

        4165 – (5*700) ------- 665

        Number of tennis rackets ------ 665/13.3 -------50

        Cost of 1 tennis racket ------ 4165/50 ------ 83.3

        Best wishes

        1 Reply Last reply Reply Quote 0
        • N Offline
          notfreemom
          last edited by

          Thanks for our prompt reply. I appreciate it very much. πŸ˜„

          1 Reply Last reply Reply Quote 0
          • N Offline
            Neat
            last edited by

            tianzhu:
            Neat:

            Hi morning,


            Please assist on the following question:

            30% of the books in a library were fiction, 25% of them were non-fiction and the rest were reference books. After 200 more fiction and non-fiction books were ordered, the percentage of the reference books in the library decreased to 40% and the number of fiction books increased by 10%. How many non-fiction books were ordered?

            Thanks vm

            Hi

            You may use MD or UM.

            FB:NFB:RB ----- 30%:25%:45% -------6u:5u:9u

            RB remained unchanged.

            40% ------ 9u
            60% ------- 13.5u

            13.5u ------- 11u + 200
            1u ------ 80

            Number of FB at first ------6*80 -------480
            Number of FB in the end ------ 528 (10% increase)

            Number of FB and NFB in the end ------13.5*80 ------1080
            Number of NFB in the end ------- 1080 – 528 ------552

            Number of NFB at first ------ 5*80 ------- 400
            552 – 400 --------152

            Number of NFB ordered ------152

            Best wishes

            [quote]Thanks tianzhiu :congrats: [/quote]

            1 Reply Last reply Reply Quote 0
            • N Offline
              Neat
              last edited by

              Neat:
              tianzhu:

              [quote=\"Neat\"]Hi morning,


              Please assist on the following question:

              30% of the books in a library were fiction, 25% of them were non-fiction and the rest were reference books. After 200 more fiction and non-fiction books were ordered, the percentage of the reference books in the library decreased to 40% and the number of fiction books increased by 10%. How many non-fiction books were ordered?

              Thanks vm

              Hi

              You may use MD or UM.

              FB:NFB:RB ----- 30%:25%:45% -------6u:5u:9u

              RB remained unchanged.

              40% ------ 9u
              60% ------- 13.5u

              13.5u ------- 11u + 200
              1u ------ 80

              Number of FB at first ------6*80 -------480
              Number of FB in the end ------ 528 (10% increase)

              Number of FB and NFB in the end ------13.5*80 ------1080
              Number of NFB in the end ------- 1080 – 528 ------552

              Number of NFB at first ------ 5*80 ------- 400
              552 – 400 --------152

              Number of NFB ordered ------152

              Best wishes

              [quote]Thanks tianzhiu :congrats: [/quote][/quote][quote]Sorry! :oops: :thankyou: [/quote]

              1 Reply Last reply Reply Quote 0
              • H Offline
                homeworkmummy
                last edited by

                mathfreak:
                Superbugs:

                Nan Hua CA1 P6 2011

                Q14.
                My salary is 1/5 more than my sister but 20% less than my brother. If our total salary is $11,100, what is my sister's salary?

                If Me=100%
                Brother =120%
                Sister=80%
                80/300x11,100=2960
                but answer is $3000?
                Pls assist. Tks

                Actually, if Me is 100%, Sister is not 80% (this means \"Me\" had 1/4 more than Sister), but instead is 100%*5/6=83 1/3%. This is so that 1/5 of Sister added to Sister will give \"Me\".
                Brother is also not 120% (this means \"Me\" had 16 2/3% less than Brother), but instead is 100%*5/4=125%. This is so that 20% of Brother subtracted from Brother will give \"Me\".

                The total would be 308 1/3%, which means 83 1/3% is $3000.

                Could you pls advise if this can be solved by model method. My DD was confused with the percentage method.

                1 Reply Last reply Reply Quote 0
                • T Offline
                  tianzhu
                  last edited by

                  Hi notfreemom and Neat


                  You’re welcome.

                  Best wishes

                  1 Reply Last reply Reply Quote 0
                  • H Offline
                    homeworkmummy
                    last edited by

                    I need help for another 1 Qs from Nan Hua paper.


                    Mrs Samy had a sum of money to spend. She spent 1/2 of her money plus $4 on a handbag. She then spent 1/2 of the remaining money plus $2 on a pair of shoes. Finally she spent 2/3 of what was left plus $1 on a skirt. She was then left with $11.
                    (a) How much did each item cost?
                    (b) How much money did she have at first?

                    1 Reply Last reply Reply Quote 0
                    • P Offline
                      pixiedust
                      last edited by

                      Appreciate any help with this question :


                      http://i1197.photobucket.com/albums/aa424/pixie_dust8/ksp2012/mq3.jpg\">

                      1 Reply Last reply Reply Quote 0
                      • T Offline
                        tianzhu
                        last edited by

                        pixiedust:
                        Appreciate any help with this question :


                        http://i1197.photobucket.com/albums/aa424/pixie_dust8/ksp2012/mq3.jpg\">
                        Hi

                        Let angle DCF be u

                        DCF=BCA=DEF = u

                        ABC + CDE = 120
                        Likewise, BAC+CFE =120

                        Add the sum of angles for the triangle ABC and parallelogram CDEF

                        ABC + CDE + BAC + CFE + 3u --------180+360 ------540
                        3u ------- 540 - 120 - 120 ------300

                        u -------100

                        Best wishes

                        1 Reply Last reply Reply Quote 0

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