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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • T Offline
      thinkgmama
      last edited by

      Thank you do much. I finally understand. 🙂

      1 Reply Last reply Reply Quote 0
      • H Offline
        homeworkmummy
        last edited by

        tianzhu:
        homeworkmummy:


        Could you pls advise if this can be solved by model method. My DD was confused with the percentage method.

        Hi

        It’s possible to provide graphical representations of the information in the question.

        Perhaps you may want to check with your DD.

        What is confusing her?

        What is her understanding of percentages after reading her textbooks?

        What is her understanding on comparing two quantities of percentages?

        Percentages is first started in P5 Maths.Maybe, she is confused because her teacher has not covered the topic in Percentages for her P6 syllabus yet.

        Best wishes

        Thanks tianzhu. She is not familiar with the comparison method. Is this only cover in p6?

        1 Reply Last reply Reply Quote 0
        • T Offline
          tianzhu
          last edited by

          homeworkmummy:

          Thanks tianzhu. She is not familiar with the comparison method. Is this only cover in p6?
          Hi

          Good Morning.

          You're welcome.

          “Finding percentage increase/decrease” is only covered in P6 syllabus.

          http://www.moe.gov.sg/education/syllabuses/sciences/files/maths-primary-2007.pdf

          Best wishes

          1 Reply Last reply Reply Quote 0
          • H Offline
            homeworkmummy
            last edited by

            tianzhu:
            homeworkmummy:


            Thanks tianzhu. She is not familiar with the comparison method. Is this only cover in p6?

            Hi

            Good Morning.

            You're welcome.

            “Finding percentage increase/decrease” is only covered in P6 syllabus.

            http://www.moe.gov.sg/education/syllabuses/sciences/files/maths-primary-2007.pdf

            Best wishes

            Thanks Tianzhu for the info.

            1 Reply Last reply Reply Quote 0
            • T Offline
              tianzhu
              last edited by

              homeworkmummy:

              Thanks Tianzhu for the info.
              Hi

              You’re welcome.

              I believe she’ll understand it better when the teacher has covered the topic.

              Best wishes

              1 Reply Last reply Reply Quote 0
              • C Offline
                Chan09
                last edited by

                I do need help as I can solve using algebra but even looking at models this is tough:

                a group of friends play tennis. each of them play with everyone else. Ann played with 4 times as many girls as boys. Bob played with 5 times as many girls as boys.
                a) how many people were there altogether? ans: 31 people
                b) were there more boys than girls and how many more? ans: 19 more girls than boys

                1 Reply Last reply Reply Quote 0
                • MathIzzzFunM Offline
                  MathIzzzFun
                  last edited by

                  Chan09:
                  I do need help as I can solve using algebra but even looking at models this is tough:

                  a group of friends play tennis. each of them play with everyone else. Ann played with 4 times as many girls as boys. Bob played with 5 times as many girls as boys.
                  a) how many people were there altogether? ans: 31 people
                  b) were there more boys than girls and how many more? ans: 19 more girls than boys
                  Hi

                  Ann played with 4 times as many girls as boys, so
                  Girls : Boys --> 4u +1 : 1u,
                  total 5u + 1 people and there were 3u + 1 more girls

                  Bob played with 5 times as many girls as boys,
                  Girls : Boys --> 4u + 1 : 1u -1 = 5 : 1

                  cross multiply or equalize --> 4u + 1 = 5u -5
                  1u --> 6
                  5u + 1 = 31
                  3u+1 --> 19

                  There were 31 people and there were 19 more girls than boys.

                  cheers.

                  1 Reply Last reply Reply Quote 0
                  • H Offline
                    hazelwong
                    last edited by

                    Hi, I came across this type of question:

                    Charlie had $490 more than Eugene. Charlie spent 1/7 of his money, Eugene spent 1/5 of his money. If Eugene spent $20 less than Charlie, find the total amount of money the children had in the end.
                    The answer given is such a complex model (subdivided into many units) :? that I wonder if there is an easier way?
                    TIA 😄

                    1 Reply Last reply Reply Quote 0
                    • MathIzzzFunM Offline
                      MathIzzzFun
                      last edited by

                      hazelwong:
                      Hi, I came across this type of question:

                      Charlie had $490 more than Eugene. Charlie spent 1/7 of his money, Eugene spent 1/5 of his money. If Eugene spent $20 less than Charlie, find the total amount of money the children had in the end.
                      The answer given is such a complex model (subdivided into many units) :? that I wonder if there is an easier way?
                      TIA 😄
                      Hi

                      Eugene's money --> 5 units
                      Eugene spent --> 1 unit
                      Charlie spent --> 1 unit + 20
                      Charlie's money --> 7 x (1 unit + 20) = 7 units + 140
                      So, 7 units + 140 = 5 units + 490
                      1 unit --> 175
                      ...you should be able to complete the solution from here 😄

                      cheers.

                      1 Reply Last reply Reply Quote 0
                      • H Offline
                        hazelwong
                        last edited by

                        MathIzzzFun:
                        hazelwong:

                        Hi, I came across this type of question:

                        Charlie had $490 more than Eugene. Charlie spent 1/7 of his money, Eugene spent 1/5 of his money. If Eugene spent $20 less than Charlie, find the total amount of money the children had in the end.
                        The answer given is such a complex model (subdivided into many units) :? that I wonder if there is an easier way?
                        TIA 😄

                        Hi

                        Eugene's money --> 5 units
                        Eugene spent --> 1 unit
                        Charlie spent --> 1 unit + 20
                        Charlie's money --> 7 x (1 unit + 20) = 7 units + 140
                        So, 7 units + 140 = 5 units + 490
                        1 unit --> 175
                        ...you should be able to complete the solution from here 😄

                        cheers.

                        Ahhh... tha's so much easier than the proposed method. Looks like sometimes some books are not so good, despite all their claims!
                        Thanks so much!
                        :thankyou:

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