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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • C Offline
      Chan09
      last edited by

      I do need help as I can solve using algebra but even looking at models this is tough:

      a group of friends play tennis. each of them play with everyone else. Ann played with 4 times as many girls as boys. Bob played with 5 times as many girls as boys.
      a) how many people were there altogether? ans: 31 people
      b) were there more boys than girls and how many more? ans: 19 more girls than boys

      1 Reply Last reply Reply Quote 0
      • MathIzzzFunM Offline
        MathIzzzFun
        last edited by

        Chan09:
        I do need help as I can solve using algebra but even looking at models this is tough:

        a group of friends play tennis. each of them play with everyone else. Ann played with 4 times as many girls as boys. Bob played with 5 times as many girls as boys.
        a) how many people were there altogether? ans: 31 people
        b) were there more boys than girls and how many more? ans: 19 more girls than boys
        Hi

        Ann played with 4 times as many girls as boys, so
        Girls : Boys --> 4u +1 : 1u,
        total 5u + 1 people and there were 3u + 1 more girls

        Bob played with 5 times as many girls as boys,
        Girls : Boys --> 4u + 1 : 1u -1 = 5 : 1

        cross multiply or equalize --> 4u + 1 = 5u -5
        1u --> 6
        5u + 1 = 31
        3u+1 --> 19

        There were 31 people and there were 19 more girls than boys.

        cheers.

        1 Reply Last reply Reply Quote 0
        • H Offline
          hazelwong
          last edited by

          Hi, I came across this type of question:

          Charlie had $490 more than Eugene. Charlie spent 1/7 of his money, Eugene spent 1/5 of his money. If Eugene spent $20 less than Charlie, find the total amount of money the children had in the end.
          The answer given is such a complex model (subdivided into many units) :? that I wonder if there is an easier way?
          TIA πŸ˜„

          1 Reply Last reply Reply Quote 0
          • MathIzzzFunM Offline
            MathIzzzFun
            last edited by

            hazelwong:
            Hi, I came across this type of question:

            Charlie had $490 more than Eugene. Charlie spent 1/7 of his money, Eugene spent 1/5 of his money. If Eugene spent $20 less than Charlie, find the total amount of money the children had in the end.
            The answer given is such a complex model (subdivided into many units) :? that I wonder if there is an easier way?
            TIA πŸ˜„
            Hi

            Eugene's money --> 5 units
            Eugene spent --> 1 unit
            Charlie spent --> 1 unit + 20
            Charlie's money --> 7 x (1 unit + 20) = 7 units + 140
            So, 7 units + 140 = 5 units + 490
            1 unit --> 175
            ...you should be able to complete the solution from here πŸ˜„

            cheers.

            1 Reply Last reply Reply Quote 0
            • H Offline
              hazelwong
              last edited by

              MathIzzzFun:
              hazelwong:

              Hi, I came across this type of question:

              Charlie had $490 more than Eugene. Charlie spent 1/7 of his money, Eugene spent 1/5 of his money. If Eugene spent $20 less than Charlie, find the total amount of money the children had in the end.
              The answer given is such a complex model (subdivided into many units) :? that I wonder if there is an easier way?
              TIA πŸ˜„

              Hi

              Eugene's money --> 5 units
              Eugene spent --> 1 unit
              Charlie spent --> 1 unit + 20
              Charlie's money --> 7 x (1 unit + 20) = 7 units + 140
              So, 7 units + 140 = 5 units + 490
              1 unit --> 175
              ...you should be able to complete the solution from here πŸ˜„

              cheers.

              Ahhh... tha's so much easier than the proposed method. Looks like sometimes some books are not so good, despite all their claims!
              Thanks so much!
              :thankyou:

              1 Reply Last reply Reply Quote 0
              • M Offline
                mathnoobs
                last edited by

                MathIzzzFun:
                Chan09:

                I do need help as I can solve using algebra but even looking at models this is tough:

                a group of friends play tennis. each of them play with everyone else. Ann played with 4 times as many girls as boys. Bob played with 5 times as many girls as boys.
                a) how many people were there altogether? ans: 31 people
                b) were there more boys than girls and how many more? ans: 19 more girls than boys

                Hi

                Ann played with 4 times as many girls as boys, so
                Girls : Boys --> 4u +1 : 1u,
                total 5u + 1 people and there were 3u + 1 more girls

                Bob played with 5 times as many girls as boys,
                Girls : Boys --> 4u + 1 : 1u -1 = 5 : 1

                cross multiply or equalize --> 4u + 1 = 5u -5
                1u --> 6
                5u + 1 = 31
                3u+1 --> 19

                There were 31 people and there were 19 more girls than boys.

                cheers.

                I'm afraid I don't get this:

                Bob played with 5 times as many girls as boys,
                Girls : Boys --> 4u + 1 : 1u -1 = 5 : 1

                why is Boys = 1u-1 ? and Girls = 4u+1 ? is that from the previous statement ?

                1 Reply Last reply Reply Quote 0
                • 2 Offline
                  2DMommy
                  last edited by

                  Please help with this question :


                  After a maths quiz, Mr Li gave the 3 prize winners a box of pencils to share. The 1st winner received 2/3 of the pencils plus 1/3 of a pencil. The 2nd winner received 2/3 of the remainder plus 1/3 of a pencil. The 3rd winner received 2/3 of the new remainder plus 1/3 of a pencil, but there were no pencils left after this. How many pencils were there in all ?

                  thanks !

                  1 Reply Last reply Reply Quote 0
                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    mathnoobs:
                    MathIzzzFun:

                    [quote=\"Chan09\"]I do need help as I can solve using algebra but even looking at models this is tough:

                    a group of friends play tennis. each of them play with everyone else. Ann played with 4 times as many girls as boys. Bob played with 5 times as many girls as boys.
                    a) how many people were there altogether? ans: 31 people
                    b) were there more boys than girls and how many more? ans: 19 more girls than boys

                    Hi

                    Ann played with 4 times as many girls as boys, so
                    Girls : Boys --> 4u +1 : 1u,
                    total 5u + 1 people and there were 3u + 1 more girls

                    Bob played with 5 times as many girls as boys,
                    Girls : Boys --> 4u + 1 : 1u -1 = 5 : 1

                    cross multiply or equalize --> 4u + 1 = 5u -5
                    1u --> 6
                    5u + 1 = 31
                    3u+1 --> 19

                    There were 31 people and there were 19 more girls than boys.

                    cheers.

                    I'm afraid I don't get this:

                    Bob played with 5 times as many girls as boys,
                    Girls : Boys --> 4u + 1 : 1u -1 = 5 : 1

                    why is Boys = 1u-1 ? and Girls = 4u+1 ? is that from the previous statement ?[/quote]Hi

                    Ann played with 4 times as many girls as boys, so if she played with 1 unit of boys, she played with 4 units of girls. So, total number of girls = 4 units + 1 (Ann)

                    So, Bob will play with 1 unit - 1 (Bob) of boys and 4 units + 1 of girls.

                    cheers.

                    1 Reply Last reply Reply Quote 0
                    • A Offline
                      anneshirleygilbert
                      last edited by

                      Hi MathIzzzFun,


                      Charlie had $490 more than Eugene. Charlie spent 1/7 of his money, Eugene spent 1/5 of his money. If Eugene spent $20 less than Charlie, find the total amount of money the children had in the end.


                      Eugene’s money –> 5 units
                      Eugene spent –> 1 unit
                      Charlie spent –> 1 unit + 20
                      Charlie’s money –> 7 x (1 unit + 20) = 7 units + 140
                      So, 7 units + 140 = 5 units + 490
                      1 unit –> 175
                      …you should be able to complete the solution from here

                      I’m a little confused. Should what Charlie spent have been 1u + 70?
                      seeing he spent (1/7 of 7 units and 1/7 of $490)?
                      We did this question using simultaneous equations and our answers are $1170 for Charlie and $700 for Eugene. Are our answers correct?

                      TIA

                      1 Reply Last reply Reply Quote 0
                      • S Offline
                        small
                        last edited by

                        Hi anneshirleygilbert,


                        Your answer is correct. πŸ™‚

                        1 Reply Last reply Reply Quote 0

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